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i just bought your membership today ! i have ochem summer session my first test is wednesday. you are saving my life just so you know ;) I just want to make sure im clear the WA will be more stable ?
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Although there is an entropic factor in all reactions and phase changes, we also have to consider the energy stability. Entropy is relatively minor a lot of the time compared to enthalpy
@@paysonkeown2960 That makes sense. How can you tell if the reaction is reactant-favored or irreversible for the reactants? Does it depend on the strength of the acids?
@@mayflowerimpact that’s a good question. If I’m understanding you correctly, you can tell which way a reaction will go based on the strengths of the acids and bases on both sides. Take water and HCl reacting. When they react, you get H3O+ and Cl-. H3O+ is a weaker acid than HCl, and Cl- is a weaker base than water. Therefore, the reaction will rarely go in the reverse, making this almost completely go towards the product. Now take acetic acid and water. These make acetate and hydronium (H3O+). Acetate is a stronger base than water and hydronium is a stronger acid than acetic acid. Thus, the reaction will want to go to the reactants, making the K
For the last example in the video, the reaction between F- and CH3OH is reactant favored because the pKa of CH3OH is greater than HF (thus CH3OH is weaker acid). Why do we not consider pKb in determining which side is favored?
pKa and pKb are related: 14 = pKa + pKb. You can use either set or even a blend of pka and pkb values to determine the direction of the equilibrium. The smaller the pka, the greater the pkb, but since the conjugate pair is on the other side, your answer stays the same.
It's a year now😮...but I think we were given pka of the acid (Ch3OH) and it's conjugate acid (HF)....so I'm not sure there would be a need to be comparing the pkb of their conjugate bases....you might as well end up confusing your self...I was almost confused and had to refer back to the video ...I now realised what he was doing😂....I've gotten it now more clearer...but I think ...you can also reference to see it...thanks😊 25:40
What about the structure tells us which is the bronsted acid/ base? You don’t say why HF is acid or why NH3 is base. Please clarify, I would rather not have to memorize weak acids/ bases.
It depends on the reaction, but usually, bronsted acids have a proton that can easily be lost and bronsted bases have a site to take in that proton. However, it always depends on the reaction. For example, water is a bronsted base when with something like HCl but an acid when with something like methoxide(CH3O-).
In this process( HF + H2O ) becomes( F- + H3O +) and it is said to be a reversible reaction! Why does HF + H2O have to become F- + H3O + and reverse back to HF + H2O ? It can just not form F- + H3O !! Please reply 🙏 🙏🙏 I know it is a silly question but I just wanna know!!
because F- conjugate base of strong acid HF which will dissociate completely in water.therefore is no way for ths reaction to be reversible reaction.it's done in one direction.
@@MrChAcHa96 Yes but what makes them strong acids and strong bases? Is there a consistent rule that can be followed so that we can potentially understand what's going on?
@@noakuu393 actually chemists discovered them so you don’t need to mess your brain to understand properly what’s strong acid or not. But if you want the explanation is the following: take for example HI (pka-10) and HBr (pka-9) both strong acids, remind that stronger the acid weaker the conjugate base and more stable it is. Iodide(I-) it’s a bigger anion than Bromide (Br-) therefore it has more space to stabilise negative charge, and if you can stabilise a negative charge you can make the ion more stable which means a stronger acid. And because Iodide is more stable it doesn’t have a strong affinity for H+, therefore it’s a strong acid, it’ll ionize in H+ and I- Hope this satisfy your doubt
@@jizla9061 To start you would have to figure out which one is your acid and which one is your base. HNO3 is a strong acid but water has been known to act as either an acid or base. Since you have a strong acid present water would be the base in this situation. Hope that helps!
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