Why does the slope varies non linearly (fixed count variable slope part ) .. exactly similar to the 2nd situation we have a constant current given by i=Vin/R entering the inverting terminal(used loosely) of the operational amplifier !!
Sir, at 15:36, if t is time for counter to count from 00...0 to 11...1 (t = (2^n) * tc, where n = number of bits, tc = period of CLK signal) then t1 can be only t
Unfortunately I still don't get, how a fixed time span can lead to variable voltages. I mean what I "there's still voltage left" and the capacitor didn't load up to the full voltage, because the time was already over. Sorry, might be a stupid question. But that is still not clear to me.
+freebird9 For higher amplitudes the wave has to cover more voltage as time proceeds , due to which the wave gets more steep . keep it simple . Just consider that your input voltage is in abundance . The capacitor stores a small part of it within time 't' .
consider DC current .. which can't flow directly through the capacitor .... so for a R- C (consider C to be ideal ie no dielectric break down ) series arrangement acted by a strong current source (constant magnitude ) .. current flows through the resistor and creates a PD across the resistor but unfortunately I cant flow through the capacitor .. so while the floating terminal of the capacitor maintain at a fixed at constant potential .. for the terminal towards the resistor Potential constantly falls linearly with time ... AS a result potential drop across the capacitor increases
