Advanced Functions 7.1 Equivalent Trigonometric Functions including cofunctions!

Ms Havrot's Canadian University Math Prerequisites

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In this lesson we will look at different equations for the same trig graph, cofunction identities, identities describing negative angles as well as the principal angles as they relate to pi in the various quadrants. It's a very basic but important lesson that will show up later in this chapter. Learn them well!

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3 окт 2024

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Комментарии : 36

@newbieestar421 3 года назад

You’re a super woman!! Your explanation is so clear and understandable,, I’m so gladdd I found you just in time bcuz I was really worried about my finals.

@mshavrotscanadianuniversit6234 3 года назад

How sweet of you ❤️

@aidenkofoed2352 4 года назад

My teachers make it sound so complicated and overwhelming but when you teach it, it feels like I’m in kindergarten😂 thanks so much ur saving my grades

@mshavrotscanadianuniversit6234 4 года назад

That’s the way it should be! 😊 made me smile 😃

@catsrepic8813 Год назад

I just wanted to say thank you so much, I have been watching all of your advanced functions videos and I'm so grateful for you. You're a life saver!!!

@mshavrotscanadianuniversit6234 Год назад

Thank you for your kind message ❤️ Glad that I could help you achieve your goals ☺️

@zeidalsendy9696 Год назад

You are a great teacher, and your teaching saves so much of time and effort of the students

@mshavrotscanadianuniversit6234 Год назад

It’s always good to hear a lesson a second time ❤️

@cyprus_ 4 года назад

This is amazing,, cant believe i didn't find this in september, couldve done so much better. Thanks for actually explaining things in laymen's terms

@mshavrotscanadianuniversit6234 4 года назад

You're not too late to the party! Tell all your friends and you can always get better prepared for your exam!

@tns_lover9271 4 года назад

Thank you so much for your video :) my test is tomorrow and this video helped me a lot

@mshavrotscanadianuniversit6234 4 года назад

I'm sorry that I wasn't able to have all of this chapter finished for you before your test. At least you can still review for your exam using the lessons I will be posting.

@mazen125 3 года назад

loved this. thank you so much

@tanya4706 11 месяцев назад

at 3:32, shouldn’t it be pie/2 shifted to the left instead of shifted to the right?

@mshavrotscanadianuniversit6234 11 месяцев назад

No, because we want to define it as a negative cosine function

@hollowayfan0586 Год назад

Hi Ms. Havrot I had a question in homework asking to prove sin(π-x) cos(π+x) tan(2π -x) Over Sec(π/2 + x) csc(3π/2 - x) cot(3π/2 + x) Is equal to Sin^4(x) - sin^2(x) I can’t figure how this is true, & when I put it into a photo calculator it even disagreed! Is this equality true, & if so could you help me solve it? Also please like my comment when you reply, as for some reason I only get notifications when my comments are liked, but not when they’re replied to. Thank you!

@mshavrotscanadianuniversit6234 Год назад

Yes, it is true LHS = sinx(-cosx)(-tanx) over -cscx(-secx)(-tanx) So now the (-tanx) cancel out and you are left with -sinxcosx / 1/(sinxcosx) Giving you -sin^2(x)cos^2(x) for you simplified lhs On the rhs you would need to factor out a sin^2(x) RHS = sin^2(x)[sin^2(x) -1] And what is in the square bracket? -cos^2(x) So now lhs = rhs 😜

@hollowayfan0586 Год назад

@@mshavrotscanadianuniversit6234 wow that’s amazing & makes so much sense Thank you so so much miss havrot!

@joannaesuola718 3 года назад

THANK YOU!!!

@mshavrotscanadianuniversit6234 3 года назад

You're most welcome! Please like, share and subscribe to help increase the visibility of the channel : )

@RD-fb6ei 3 года назад

Thanks for saving my grades :)

@mshavrotscanadianuniversit6234 3 года назад

Happy to help! BUT, you are the one that did all of the work! Thanks for watching my channel : ) Please, like, subscribe and tell all your friends to help increase the channel's visibility. : )

@ShaianKhondaker Год назад

thank you so much

@mshavrotscanadianuniversit6234 Год назад

You are most welcome! Thanks for watching and commenting. Please like, share and subscribe to increase the channel’s visibility ❤️

@dannytran1587 4 года назад

12:28 Ouch my head. So do we have to memorize that the Sin goes to Cos, Cos goes to Sin, and Tan goes to Cotan?

@mshavrotscanadianuniversit6234 4 года назад

Yes! Sounds like you’ve got it already! 😊

@ramshariazuddin45 2 года назад

Hi Ms. Havrot!! Loved this video! Can you please show me how to do question 4 on page 392, I'm so confused😭

@mshavrotscanadianuniversit6234 2 года назад

First you need to understand what a cofunction is. If you take the cos 60 = 1/2 you also know that the sin 30 = 1/2 so cos (pi/2 - 30) = sin 60 and vice versa. That is the basis for cofunctions. In question 4 they ask for the reciprocal cofunctions, which is basically the same You could do them by simply replacing cscx by sinx and following the above and at the end plug back in the reciprocal trig functions. for instance if I wanted to know what the cofunction is for cscx I would say that sinx =cos( pi/2 - x) and then switch sin to csc and cos to sec to get cscx = sec (pi/2 - x)

@ramshariazuddin45 2 года назад

@@mshavrotscanadianuniversit6234 Thank you so much for clarifying!!💜

@evadervishi7829 Год назад

Hi Ms. Havrot, I'm confused with 6a from page 393 (7.1). Any help would be much appreciated. As well, with number 5b from the same page, I'm confused about which related angle identities to use in order to solve it. I was thinking of using -cosx=cos(pi-x) to solve it since cos is negative in the third quadrant. But the solutions manual used cosx=-cos(pi+x). This really confuses me.

@mshavrotscanadianuniversit6234 Год назад

Cos (13pi)/12 is negative as it is in Q3. The related acute angle is pi/12 so the answer should be -cos pi/12

@mshavrotscanadianuniversit6234 Год назад

Sorry I’m just about to take off on a plane.

@dannytran1587 4 года назад

Is chapter 7 more difficult than 8/9?

@mshavrotscanadianuniversit6234 4 года назад

I have found that most students struggle the most with trig. It does require more practice but it is NOT impossible!!