AES I - Group, Ring, Field and Finite Field - Abstract Algebra Basics - Cyber Security - CSE4003 

This video should appear first in youtube , when i search "Group , Ring and Field".... Thank You sir...

Thank you it was very clear

Very clear ,crisp in a flow explanation for groups, fields and rings. To good!

Hi may i ask when you are checking for whether z%2 is a field, what happens when you add two expressions that each come to 1. eg 3mod2+4mod2=1+1 = 2 or 10?

such a great explanation 💚😊

Thank you for the explanation

thank you sir

wonderful explanation .. May I have your PowerPoint that you explain on it?

5 mod 2 = 1, mentioned wrong while adding :)

Thanks for sharing, it helpful

In abstract algebra ops could be anything so say if we take natural numbers n subtraction op, it won't be closed under 2-5=-3 so it won't even be a group?

Sir Please Share notes of DES and AES algorithm.

Very nice overview professor, thank you. Some remarks: (1) in the field example (ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TPW4_Z5kiRw.html) you mention that it is commutative. How is that relevant, provided that on ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TPW4_Z5kiRw.html you say a ring does not need to be commutative, and a later that a field is an extension of a ring and you do not mention commutativity at ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TPW4_Z5kiRw.html? (2) minor but at ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-TPW4_Z5kiRw.html a typo: 'P (uppercase) ... where p (lowercase) is'.

5 mod 2 + 3 mod 2 = 2 . Since 2 is not part of { 0 , 1 } ......How can we take it as a field?