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Sir I'm in second semester and I watch your video regularly based on mathematics.I want to tell you one thing, should I start preparing the jam from now?
@@LUc942 Find the expression u(n) and u(n+1) then find lim n tends to infinity u(n) and then find lim n tends to infinity u(n+1)/u(n). Then U can solve it.
SIR HOW LOG N /N SQUARE IS DECREASING SEQUENCE BECAUSE AFTER CALCULATING IT'S MAXIMUM AND MINIMUM VALUE WE CAN'T SAY IT'S DECREASING OR INCREASING. KINDLY CLEAR IT SIR
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)