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Alternating Series | Leibnitz Theorem for Convergence of Infinite Series | By Gp sir 

Dr.Gajendra Purohit
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21 сен 2024

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Комментарии : 83   
@themadhavsharmaphotography7029
greetings from PEC 1st year
@priyanshuyadav1748
@priyanshuyadav1748 11 месяцев назад
Greetings from UIET chandigarh
@akashchaudhary6877
@akashchaudhary6877 9 месяцев назад
Same bro
@Shubham_Garg.4444
@Shubham_Garg.4444 9 месяцев назад
Same bro
@rupamthakur2002
@rupamthakur2002 17 дней назад
Happy🥰Teachers'❤️Day Sir!🥳 Your guidance😇 and support 🤞🏻have shaped the future of many students✨, and we are all grateful 🙏🏻for your dedication😌. _May your day be as special😍 as the impact you've had on your students😌._ Thank you 🫶🏻for being such an incredible teacher❤️.
@suryathakur-uc5wj
@suryathakur-uc5wj 9 месяцев назад
sir 13:08 how did u wrote 1/n^n-1 (n tending to infinity) 0 despite (infinity)^infinity
@shaiksalman2683
@shaiksalman2683 Год назад
Option 1 》|X|
@is_math_hard
@is_math_hard 9 месяцев назад
did you get x^2 in the end of D'Alemberts test?
@vismaybharadwaj8908
@vismaybharadwaj8908 4 месяца назад
@@is_math_hard yes
@dileepyadav4493
@dileepyadav4493 Год назад
Sir I'm in second semester and I watch your video regularly based on mathematics.I want to tell you one thing, should I start preparing the jam from now?
@arnavlearningandgamingchan7630
@arnavlearningandgamingchan7630 9 месяцев назад
Thankyou so much sir 🌺, Correct answer is option b 😊
@sachinonstudy
@sachinonstudy 8 месяцев назад
Option B ✅
@kalashdeep6623
@kalashdeep6623 3 дня назад
Watching from pec chandigarh batch 2024-2028
@divyanka4927
@divyanka4927 10 часов назад
@@kalashdeep6623 myself from Punjab University lmao
@-KundanYadav
@-KundanYadav Год назад
Thank you Sir 🙏
@jamesstephen7268
@jamesstephen7268 3 месяца назад
Sir, please put English captions.. It will be helpful for those students who don't know Hindi..
@dineshjjjjjjjjjtttt5251
@dineshjjjjjjjjjtttt5251 Год назад
Option b correct Thankyou sir
@LUc942
@LUc942 Год назад
Ksise
@Hitesh2006-e8r
@Hitesh2006-e8r 29 дней назад
A hoga..
@gauravpandeyupsc7077
@gauravpandeyupsc7077 Год назад
Good job 👌
@Rohit-zl6qj
@Rohit-zl6qj Год назад
sir apka content bhot achha h pr please bolne ki speed halki slow rkhiye ap bhot zada fast bolte h. Thanks for all the work you are doing 😋
@deveshsarode
@deveshsarode Год назад
Bhai mai toh fir bhi 2x pr dekta hu😅
@roshankumarverma4155
@roshankumarverma4155 Год назад
@@deveshsarode Because you are a legend
@jokulous8050
@jokulous8050 Год назад
Me as well watching at. 2X 😂😅
@priyansumohanty9303
@priyansumohanty9303 Год назад
Answer will be option (B).
@LUc942
@LUc942 Год назад
Kaise
@priyansumohanty9303
@priyansumohanty9303 Год назад
@@LUc942 Find the expression u(n) and u(n+1) then find lim n tends to infinity u(n) and then find lim n tends to infinity u(n+1)/u(n). Then U can solve it.
@LUc942
@LUc942 Год назад
@@priyansumohanty9303 bro bro ye toh x aa rha h💀
@LUc942
@LUc942 Год назад
@@priyansumohanty9303 axa axa dhanyawad aapka🙏🙏🙏🙏
@LUc942
@LUc942 Год назад
@@priyansumohanty9303 bro answer B nhi A hoga kiyoki x≤1 mai x=1 bhi aa rha h jisme ratio test fail ho jata h Isiliye x
@KaranRaj-lf7ju
@KaranRaj-lf7ju Год назад
Sir option A is correct in last given question
@PrashantSingh-lv5pw
@PrashantSingh-lv5pw Год назад
Sir !! Kummer's test [ INFINIT SERiEs ] par videos... 🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻🙏🏻
@Searchme1011
@Searchme1011 7 месяцев назад
Option B
@tarushibagra
@tarushibagra 5 месяцев назад
Option a is correct
@veeryadav-tz5od
@veeryadav-tz5od 9 месяцев назад
i am from pcce college in goa thank you sir
@Jay_patel_1205
@Jay_patel_1205 Год назад
PARABOLOID bata dijiye sir 🙏
@rajankumar-ps7pg
@rajankumar-ps7pg 11 месяцев назад
SIR HOW LOG N /N SQUARE IS DECREASING SEQUENCE BECAUSE AFTER CALCULATING IT'S MAXIMUM AND MINIMUM VALUE WE CAN'T SAY IT'S DECREASING OR INCREASING. KINDLY CLEAR IT SIR
@AbhishekYadav-uk7sb
@AbhishekYadav-uk7sb Год назад
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)
@neerajchandrasati3099
@neerajchandrasati3099 9 месяцев назад
Thanks 🙏
@anjankumar9730
@anjankumar9730 Год назад
B
@LUc942
@LUc942 Год назад
Kaise
@aryasingh25
@aryasingh25 Год назад
Sir 🙏🙏 Please SC Mallick and Savita Arora se pdhaiye. ( BHU UNIVERSITY)
@UmeshYadav-tg3tl
@UmeshYadav-tg3tl Год назад
B ☑️
@CODE_YOUR_TYPE
@CODE_YOUR_TYPE 5 месяцев назад
10 SEC first, use Leibnitz for Convergence, second, use ratio test to find x values
@MayankSharma-cm4zb
@MayankSharma-cm4zb Год назад
Option B ..tq sir ji
@LUc942
@LUc942 Год назад
Kaise?
@LUc942
@LUc942 Год назад
@@AkashSingh-qs3ek aapka un kitna aara h
@AkashSingh-qs3ek
@AkashSingh-qs3ek Год назад
Sorry 1st option is correct✅✔ answer h
@AkashSingh-qs3ek
@AkashSingh-qs3ek Год назад
Qki x=1 pr divergent aa rha h by second logarithium test D alembert ratio test se x^20 to ye x=1 pr divergent hoga to ye series only x
@LUc942
@LUc942 Год назад
@@AkashSingh-qs3ek hn a is correct
@atul_Damor_41
@atul_Damor_41 8 месяцев назад
Hallo sir please riply me ye video de hmm GTU University hai isame kam lgela aapka.. sare video..
@LUc942
@LUc942 Год назад
Option b ~ how?
@AbhishekYadav-uk7sb
@AbhishekYadav-uk7sb Год назад
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)
@Tsetsego
@Tsetsego 10 месяцев назад
Sir aap zabardasti karke bas answer la rahe hai jab limit put karte hai n me to uper koi value nahi honi chahiye n ke terms me. Thank you
@LUc942
@LUc942 Год назад
Option A is correct ❄️❄️ B galat h ek baar dobara ratio test pd lo😂
@ranajayghoshal5372
@ranajayghoshal5372 Год назад
x^2
@aashuraghav6494
@aashuraghav6494 Год назад
M bhi toh socho y aa kse rha h b option 😂
@AbhishekYadav-uk7sb
@AbhishekYadav-uk7sb Год назад
B option is correct because after putting x=1 , Alternating series will be { 1 -1/3+ 1/5- 1/7....................1/(2n-1) } And look at this series it follows Leibnitz theorem i.e 1/(2n-1) >= 0 1/(2n+1)
@AbhishekYadav-uk7sb
@AbhishekYadav-uk7sb Год назад
Ratio test is working on only positive series but this is alternative series bro , update your concepts clarity. 😅
@Sankhamit
@Sankhamit 8 месяцев назад
bro in each and every ratio test terms were positive, this is an alternating series
@rahulkarmakar8067
@rahulkarmakar8067 Год назад
option A
@vikings9414
@vikings9414 Год назад
Option b
@Ashish...114
@Ashish...114 10 месяцев назад
The answer is: Bombay (B)
@galaxyhighermathematicsbyr3047
Option a
@ChetnaLathwal
@ChetnaLathwal Год назад
option d
@anime_legend6969
@anime_legend6969 4 месяца назад
how did you guys solve the last question?
@TheVaibhavGupta_
@TheVaibhavGupta_ 4 месяца назад
I think the option is "A" coz Un should be less than one
@tanavposwal
@tanavposwal 11 месяцев назад
Thanks you sir from cgc landran
@PuneetChauhan-dp8ym
@PuneetChauhan-dp8ym Год назад
b
@vishnugupta3486
@vishnugupta3486 Год назад
A
@jaiveerrana5691
@jaiveerrana5691 Год назад
Sir samjh nhi aa raha
@abhishekdubey5599
@abhishekdubey5599 Год назад
First
@ajaybijarniya122
@ajaybijarniya122 Год назад
B
@somnathrakshit1283
@somnathrakshit1283 Год назад
Option B
@LUc942
@LUc942 Год назад
Kaise?
@Prashant_2_1_0
@Prashant_2_1_0 Год назад
A
@Sagars__Artwork
@Sagars__Artwork Год назад
B
@pritech2687
@pritech2687 Месяц назад
B
@aparnathijaydip
@aparnathijaydip Год назад
B