An Interesting Radical Equation Challenge | Can You Solve? 

The equation simplifies to x^2 + √(5-x) = 5. Let a =5. Then, squaring, a^2-(2x^2+1)a +(x^4+x) =0 > a=5 = 1/2[2x^2+1 +/-(2x-1)] > x^2+x-5=0 or x^2-x-4=0. The possible solutions are x=1/2[-1 +/-√21] and x = 1/2[1 +/-√17]. The actual solutions are x=1/2[√21 -1] and 1/2[1-√17].

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