Aptitude Preparation for Campus Placements #13 | Clocks - Part 2 (Questions) | Logical Aptitude 

To find the angle between hour hand and minute hand we can also use the formula : angle=30*Hour-(11/2)*Minute Conditions: 1)if angle is more than 180 then subtract it from 360. 2) If negative then take modulus

Angle between hour hand and minute hand when time is 2:25 = 2*30 -25*5.5= -77.5 degree (no consider sign) ,where 5.5 is relative speed between hour and minute hand .

Guys last ans is 360-30 +x/2 -6x=90 and now you can solve this and build your logic

Between 2-4 and 7-10, ideally the number of right angles should be 4 but due to overlap, each interval only has 3 right angles

Formula for angle in any specific time. let time is in H : M H= hour, M= minute angle = |30H - 5.5M|

Also we can use "degree= 30*hour-(11/2)*minitue"

Angel Between Minute and Hour Hand is... [(11/2)M - 30(H)]

last question answer : x/2 + 6x - 150 = 90 -> x = 480/11

Formala to find angel between min and hour hand :-. Let x:y time ;x is hour,y is mins. A=| y*6 - (x*30+0.5*y)|. 0.5 is 1/2

Last question please explain , my answer is not coming

Answer is not coming ?

for last question i am getting 510/11,is that right? i am not sure about it

i didnot get the answer of last question. How you did that?

Answer: C. 43+(7/11) minutes past 5 15+6x-(x/2) = 90 X = 13+(7/11) 30 + 13 + (7/11) = 43 + ( 7/11)

I am not getting correct answer in question 5 of Practice problems..........in i) my ans is same which is 60/11 but in ii) & iii) I got 300/11 and 120/11 respectively. Anyone who can help me ?

Please explain

Can anyone tell us how it is coming 480/11? My answer is 150/11. using the equation 15+6x-x/2=90

First watch 😂

Q4 is wrong