I’m sure that changing pressure affects the value of Kp, if you do your calculation at the end again with a different pressure then the value for Kp changes.
Great video! Just one thing, at roughly 9:30 when you found out the no. of moles of all the gases, I don’t understand how you go from 2 moles of PCl5 to 3.25 total moles. Where did the extra 1.25 moles come from. I know my understanding of what moles are is probably completely off, but I’m trying to self-teach in coronavirus lockdown, if someone could help it would really be appreciated! Thanks
Because the ratio of the moles after equilibrium is 1:1 for the products so, therefore, PCl3 and Cl2 are both equal to 1.25, (and PCl5 is 0.75 because 2 - 1.25 = 0.75) after equilibrium. Adding 1.25 +1.25 + 0.75 = 3.25. So using this we can find out the mole fraction. Hope this helped! :)
I'm just a little bit confused. In which spec is this video for? I've looked at the spec and I can't seem to find anything on Kp. As in, is this video for those who will be sitting both AS and A2 exams at the end of the A level course like me to know about?
Sana It's for the NEW linear spec, if your AS paper (if you even did it) does not count then this is the correct specification for you. 3.1.10 in the AQA spec if you wanna check it out
@@georgewisa6769 having not touched a chemistry textbook for 3 years, at this point i don't even understand my question anymore lool.😂😂 but I appreciate the response
I love you ... go to heaven please Also why did u divide the no. of moles of N and O I mean shouldnt we add them to find the M.F bcz u said no.of moles of gas / TOTAL no . of moles of gases?
He added the no. of moles of O2 (0.075625 mol) and the no. of moles of N2 (0.2864 mol) to get 0.362025 mol. He then divided the no. of moles of the gas he was dealing with (O2, 0.075625 mol) by the TOTAL no. of moles he just calculated (0.362025 mol). moles of gas / total moles of gases = moles of O2 / moles of N2 + moles of O2 = 0.075625 / 0.2864 + 0.075625 = 0.075625 / 0.362025 = 0.2088..... You probably already figured this out already but if you didn't, hope that answered your question.
