It's odd how I don't get this topic for a month, I spend hours reading through the text book and I still don't get it. I then come across this video and get it instantly! Thank-you!!
Thanks so much! Actually understood this just need to keep repeating it to get it in my head! Its funny how my Chem Teachers needed 3-4 lessons to explain this and even then they rushed through it, I didn't understand barely any of it...But you explain it perfectly in 40 (which is 5 mins earlier than a single lesson in my school) making it easier to understand. Ty once again!
Your videos are helping me so much! Very compact and straight forward with key information required for exam, eliminating things we do not need to know which are included in the textbook! Thanks again!
great example of why this guy is a better teacher than my teachers: if my teachers had just called it formation of bleach i would've remembered it from the start
One of my Chem teachers is useless.. The other is amazing. So, I can only do half of Unit 2 (due to the good teacher lol) and the other half I can't do because she doesn't properly teach us. BUT! Thanks to you, I'm starting to understand the other half of Unit 2 that I did not understand so thank you. Unit 2 exam on Tuesday. Studying 24/7 now haha.
Thank you so much, sir. You don't realize how much of a favour you're doing by spreading education in the world. You're literally changing the world. Thank you so much! I'll be done with my Alevels in OCT/NOV, but never making such informative Alevel vids, I assure you, it'll be a great help for the next generation of students as well!!!
after mygcsescience was no more for a level (clue's in the name) i had no nope. how could i binge videos before every exam to ensure i got a good grade now?? and then someone in my class recommended your channel and with that i have found my saviour. really nicely done videos with nice looking layouts and good explanations that are detailed but summarised!
+Kyosuke Sagara Feel like I should try and put some Spinal Tap quote here but I can't quite get it to fit. Anyway, you got the A so the credit is all for you!
Thank you for your amazing videos after i have lost motivation and nearly quite on going to my exam i found your videos and it made thing easier and way simple thank you lots
omg this was soooooooo helpful, I couldn't understand it in class, and the book further baffled me. Thank you! I have made some very useful notes based from this video. It's 00:55 and I should probably sleep as I'm tired, but I need to watch more of your videos! I have a mock later this week x
E Rintoul there's also another equation i have been taught, it is when the chloric acid further ionises. H2O + HCLO ----> CLO + H3O Do we need to know this ^
was doing a past paper when i realised my teacher completely skimmed over this topic.... then saw that i lost 15 marks for it! but your videos always save the day
Hey. Very nice video...thank you! But I do have one question. In the beginning in the table the KBr solution turned orange when Cl2 was added because of bromine water being formed which is orange right? And in KI the solution turned brown when Cl or Br was added because iodine solution is brown right? That makes it easy to learn because I already know the colours of the solutions. However, I’m a bit confused at around 29:26 when you said the bromine would produce brown fumes...shouldn’t it be orange? And that the iodine would produce a black solid...wouldn’t it be brown? Please clear up my confusion. This video was great though! It really helped. I’m just confused in one thing
E Rintoul I used to run windows from a separate partition so i could run it on its own in order to play games, but windows kept messing up after some time for different compatibility reason. So I just installed parallels and now I run windows and mac at the same time on the same partition. But because doing this takes up a lot of ram you can't play major on windows while windows and mac are running at the same time. For me when im using Microsoft office programs, they run smoothy together on 16gb of ram. :)
Thank you so much! A big fan of yours. Just a quick question, about the Iodide reduction with conc H2SO4 My teacher taught us .... NaI + H2SO4 --> NaHSO4+ HI HI + H2SO4 --> I2 + H2S + 4H2O Is that correct? Or Is it better off me learning your version? which you said is specified.
+may thu aung win sorry if i'm incorrect but is the 2nd equation meant to have these products instead: sulphur dioxide (SO2) instead of H2S (also should have I2 and H20? (unless you intended to write this displacement as the last stage of displacement (3rd stage) in which you would be correct).
Thank you so much I am in A2 and I have mocks in a few weeks, I have never really understand this topic in class until now. I always find your videos helpful I just use the text book for references. Thanks again
Just a quick question, you mentioned that you couldn't find an equation for the formation of sulphur in the reaction of Iodide with sulphuric acid but when we learnt it we were also taught H2SO4 + 6HI --> S + 4H20 + 3I2 so I was wondering if this was correct? Thanks
my a level chem exam is tomoz, i owe you many thanks, i think u have just saved me xD. Great guide, sums it up very well and makes it much less confusing than in class
This video is really helpful, especially after forgetting the complexity of the equations over Easter break. Just wanted to ask what app/ website do you use to make your videos. It would be really helpful to know, so I can make my own summary videos to come back to when I’m studying A2.
Nice video but again, according to the AS portion there is another disproportionation reaction. The one you did was in cold alkali (15 degrees celsius). The one with hot alkali (NaOH at 70 degrees celsius): 3Cl2 + 6H20 ---> 5NaCl + NaClO3 + 3H20. Please add that. Other than this, solved all my doubts, thank you so much.
Yash Verma Again, as per the other comments that you left, thank you for taking the time to leave them. However, as per the other video, you really need to check your facts before trying to correct me. Here's an excerpt from the specification, relating to the reaction that you mention: "know the reaction of chlorine with cold, dilute, aqueous NaOH and the uses of the solutions formed" In my book, cold is not 70 degrees.
QUESTION ………….. Can you use TRANSITION metal halide salts like iron bromide or tin bromide to make the corresponding acid HBr by dripping sulfuric acid on the salt...……….OR DOES IT HAVE TO BE A SODIUM BROMIDE????????????????????????
Plz Can I ask a small question... When u say sulphur dioxide has been reduced is it because the sulphur has been reduced from +6 to +4? Why did you not consider it as separate molecule. I mean just because sulphur has been reduced do we say whole sulphur dioxide has been reduced? Thank you
Will we ever have to talk about how fluorine deviates from the trends in atomisation energy and electron affinity and thus how instead the trend in hydration enthalpy better explains the trend in oxidising power? Or should we stick with the 'faulty explanation' (so-called by Jim Clark on Chemguide)? Thanks a lot! :) Also, shouldn't NaClO be called sodium chlorate (I), to differentiate it from NaClO3?
Eddard Stark Fluorine isn't required for this topic, only Cl, Br and I! I guess they could start looking at astatine and fluorine, but it would be incredibly harsh and I'm really not convinced that they would! Yeah, it should be that, but NaClO3 isn't in the spec!
quick question based on 29:20 my aqa book says 2H+ +2BR + HSO4> SO2 + 2H20 + BR where as on your video there is no bromines in the second reaction. can you explain why? please i got an exam coming up tomorrow and i really dont understand, i was also wondering since i understood it your way, would i lose marks for not putting the bromine in.
Don't worry about it i looked at the mark scheme for a question based on this, and your explanation is right. its probably because my exercise book has complex compounds.
Thank you so much for the video! So useful! Just liked to correct that halides are oxidising agents becuase they are themselves reduced. But apart from that, great work! Keep it up!
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F.J Vinzenz I'm a little confused... do you mean bromide? If so, the bromide ion is acting as a reducing agent. One way to tell is that the bromide ion is itself being oxidised from -1 as bromide to 0 as bromine. Does that make any sense?
Chemguide states that the colour of iodine in solution (if there's iodide for it to react with) is red, and if there's no iodide it'll form a "dark grey precipitate". Although, I doubt we would ever be examined on the colour produced, and if we were it'd be bromine or chlorine, probably
@@Psyxiiko Damn i’m getting old, second year of University now! Had to reply to the itachi profile though. The key is to do past papers, mark them yourself (honestly). Take notes on what you didn’t get right and then come to these videos to learn about them. Give it a few days and retry the question. Once you’ve done it enough times you’ll get the hang of it
Fantastic videos! Thank you so much!! 😁 Looking out for A-Level Physics and Maths also, whilst we have moved more heavily to online learning from college.
Why is it that with the naoh in the formation of bleach you can ignore the oxidation states of any compound without a halide in it but in reactions with h2so4 you consider the oxidation state of sulfur in h2so4 and so2 aswell?
About the strong acid...HCl is a STRONG acid, but that doesn't mean the same thing as a concentrated acid. It is strong, but very very dilute..so H+ ion conc is very low...do more of this in year 13 so don't worry too much if you are in year 12.
Thanks a lot for these videos, they really help. About 30 mins in, in the third extra step for iodine, wher do you get the HI from if it had been previously used in step 2? Once again thanks for all the help.
Why can’t you please be my chemistry teacher in college? It really pisses me of how we take weeks and weeks to learn stuff in class but you are able to explain large chunks of the topic in 4O minutes. Each chemistry lesson we have is 50 minutes long !!!!! I only understand chemistry when I watch your videos.
Hi, I'm a bit confused because in my textbook I've read that when KI reacts with Br or Cl it produces a red solution if you are mean with the amount chlorine or bromine used. And if you use the chlorine or bromine in excess it goes grey and I really don't understand why. So if anyone could help me out that would be very much appreciated!!!1