AQA Core 2 4.05 Identifying Graph Transformations

TLMaths

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31 окт 2024

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Комментарии : 16

@coolstuffings 8 лет назад

If I even pass my core 2 paper, it'll be thanks to this guy

@TLMaths 8 лет назад

Really glad I could help - good luck tomorrow!

@louismcelgunn3683 7 лет назад

This was really useful, I think I'm ready for tommorrow

@lucyyyy880 7 лет назад

Thank you so much for your videos!

@hanisnaimihasli4176 4 года назад

I UNDERSTAND! CRYSTAL CLEAR! OH, THANK YOU SO MUCH! 😁😁😁

@serinacat4781 4 года назад

Great video, just hope it can be more clearly 😭

@ayshanana-patel7156 7 лет назад

wasn't the rule to get a factor of k in the y direction u multiply by 1/k, so shouldn't to get a factor of 5 u multiply by 1/5 on the 2nd example???

@TLMaths 7 лет назад

If you replace y with (1/5)*y, then this is a stretch factor 5 in the y-direction. (1/5)*y = f(x) so y = 5f(x)

@jackdenton19 8 лет назад

if f(x+2) became f(x+3)-2 what would the translation become?

@TLMaths 8 лет назад

+Jacky boi The translation vector would be [-1,-2]

@georgeholder1099 8 лет назад

Shouldn't the 2 be positive?

@TLMaths 8 лет назад

No - the number outside the bracket remains as it is. So when f(x) becomes f(x-a)+b, this is a translation by the vector [a,b]

@georgeholder1099 8 лет назад

Ah yes, i see know thanks

@TypicalBambi 8 лет назад

Wouldn't the 4th one be SF 1/8?

@TLMaths 8 лет назад

It can't be 1/8 otherwise you would replace the x with 8x, then you would get (8x)^3. It's got to be (2x)^3 to make 8x^3

@TypicalBambi 8 лет назад

oh, so you have to use the power of x to get the number to use, in this case 2?