Arithmetic Progression Class 10 in One Shot 🔥 | Class 10 Maths Chapter 5 AP | Shobhit Nirwan 

Some corrections- 52:12- It’s 18+1= 19 1:20:00- Last me ans me minus sign bhi lagna hai😅, it’s -979 1:30:29- It’s 7x6= 42

1 like=98.9% in board exam(don't take any risk😅😅) Edit =Thank u for 1k likes🥰🥰

🤝10th batch 2024-25

Anyone in September 2024😢(preparation for mid term 😢)

1 like = 100 💯 Mark ‼️ in exam ( don't take any risk ‼️☠️)

1 like = 100 Marks in exam😂😂

Vote Now for The sequence Series: 1. Triangles 2. Areas related to circles 3. Circles 4. Statistics

n[48+(-3)(n-1)]=78*2 3n[16-n+1]=78*2 n(17-n)=78×2/3 n²-17n+52=0 (n-4)(n-13)=0 thus.....n=4,-13 if it is helpful...one like please Don't forget please ❤️🥺😊

Vote for triangles 👇👇

Vote for surface area and volume ❤❤

Vote for surface area and volume❤😊

00:01 Understanding the definition of Arithmetic Progression 01:58 Arithmetic Progression is a list of numbers with a fixed pattern 05:44 Understanding arithmetic progression and common difference 07:53 Understanding the general form of an arithmetic progression 11:46 Identifying an arithmetic progression (AP) in a given list of numbers 13:42 Understanding arithmetic progression through examples and calculations 17:40 Understanding arithmetic progression with example calculations. 19:37 Importance of concentration in solving word problems 23:05 Understanding arithmetic progression in a classroom setting. 24:59 Explanation of arithmetic progression pattern with detailed calculations 28:40 Understanding the formula for compound interest 30:40 Exploring arithmetic progression calculation techniques. 34:18 Finding common difference and checking for AP 35:50 Introduction to arithmetic progression and formulation of terms 40:00 Understanding arithmetic progressions and terms 42:14 -81 is the 35th term in Arithmetic Progression 45:59 Understanding Arithmetic Progression key formula 47:50 Calculating number of terms in an Arithmetic Progression 51:41 Checking for Arithmetic Progression using common difference 53:19 Checking if a list of numbers forms an arithmetic progression 57:18 Determining the two-digit numbers divisible by 3 59:24 Identifying two-digit numbers divisible by 3 1:03:17 Finding the 11th term of an arithmetic progression 1:05:22 Solving equations in Arithmetic Progression 1:09:20 Calculating the sum of terms in an arithmetic progression 1:11:23 Understanding the sum of terms calculation 1:14:53 Understanding the arithmetic progression formula and its applications. 1:16:56 Finding the sum of the first 22 terms in an AP 1:20:34 Key steps to find the sum of n terms in arithmetic progression 1:22:49 Sum of Arithmetic Progression for 1000 terms 1:26:37 Solving for the value of a and d in the arithmetic progression equation. 1:28:43 Calculate the total production in the first seven years 1:32:48 Discussion on the continuous increase in radius and total length of the true spiral 1:34:44 Understanding the concept of circumference, parameters, and calculations in circle geometry 1:38:17 Focus on self-solving questions in NCERT and RS for Arithmetic Progression. Crafted by hasnain

Thank you bhaiya ❤ Guys Vote for CIRCLE ⭕ 👇

I hope all students get 95 % in 10th board exam

35:38 principle = 10,000 ; rate of interest = 7% a=p[1+r/100]^time a=10,000[1+7/100] a=10,000[107/100] a=100*107 a=10,700

Kis kis ke half yearly exam mai ye chapter aa raha hai vo like kare , usse ache marks milenge 😊😄

I would like you to please make lectures for the following topics as your videos are much better as compared to other channels. 1) Chapter:3:Pair of Linear Equations in Two Variables 2) Chapter:4:Quadratic Equations 3) Chapter:6:Triangles 4) Chapter:10:Circles 5) Chapter:12:Areas Related to Circles 6) Chapter:13:Surface Areas and Volumes 7) Chapter:14:Statistics I would really be grateful if you could cover these topics in your upcoming videos as these are my weak points.

Thank you for the video.. Please do lectures on 1.Surface areas and volume 2.Triangles 3.statistics 4.Coordinate geometry 🙏 🙏

Math mein Lana hai 100/100=1mark best of luck everyone 🤣🤣 Who noticed it😁

Anti banti santi jisne mere comment ko like nhi kiya wo maths ke exam me fail😂😂

Arithmetic Progression (AP) is a sequence of numbers where each term is obtained by adding a fixed number to the previous term. The summary covers the definition, general form, and methods to find the nth term and sum of the first n terms of an AP. Key moments: 00:00 The video discusses arithmetic progression in Class 10th, explaining the concept of common difference and general form of an arithmetic sequence. It emphasizes adding common differences to each term to progress through the sequence. -Introduction to arithmetic progression in Class 10th and the concept of common difference. -Explaining the process of adding common differences to each term to advance through the sequence. -Understanding the general form of an arithmetic sequence and the importance of recognizing common differences. 08:05 Understanding the concept of common difference in sequences is crucial for solving mathematical problems efficiently. By identifying patterns and applying simple arithmetic operations, such as subtraction, one can easily determine the common difference in a sequence. -Explaining the concept of common difference in sequences and its significance in mathematics. -Demonstrating how to calculate the common difference by subtracting consecutive terms in a sequence. 16:10 Understanding the common difference in a series of numbers is crucial in solving mathematical problems. Simplifying complex equations by identifying patterns and common differences can lead to accurate solutions. -Importance of identifying common differences in mathematical series for problem-solving efficiency. -Simplifying equations by recognizing patterns and common differences to reach correct solutions. -Exploring the concept of air pressure in cylinders and the removal of air to understand the mathematical implications. 24:15 The video discusses solving mathematical problems involving fractions and percentages step by step, demonstrating the process of simplifying equations and understanding compound interest formulas. -Solving mathematical equations involving fractions and percentages step by step. -Demonstrating the process of simplifying equations and understanding compound interest formulas. -Explaining the concept of common differences and common ratios in mathematical sequences. 32:19 Understanding arithmetic progressions is crucial in mathematics. The formula for finding the nth term in an arithmetic progression is essential for calculations and problem-solving. -Arithmetic progressions are sequences with a common difference between consecutive terms, aiding in calculations and problem-solving in mathematics. -The formula for the nth term in an arithmetic progression involves identifying the common difference and applying it to find specific terms in the sequence. -Practicing arithmetic progressions and nth term formulas helps in developing problem-solving skills and understanding mathematical concepts effectively. 40:23 Understanding arithmetic progression formulas and identifying terms in a sequence is crucial for solving math problems efficiently. The video discusses how to determine the number of terms in a sequence using the arithmetic progression formula. -Importance of mastering arithmetic progression formulas and recognizing terms in a sequence for efficient problem-solving. -Exploring the concept of arithmetic progression and its application in determining the number of terms in a sequence. -Demonstrating the process of verifying the arithmetic progression formula and calculating the number of terms in a given sequence. 48:28 Understanding the concept of common difference is crucial in solving equations with multiple variables. Checking the common difference helps determine the value of variables in the sequence. -Importance of common difference in solving equations with multiple variables. -Utilizing the common difference to find the values of variables in the sequence. -Verifying the list of numbers and using the common difference concept to determine variable values. 56:30 Understanding the concept of finding the number of terms in a sequence divisible by 3 involves manipulating equations to determine the value of 'n' and the total number of terms in the sequence. -Manipulating equations to find the value of 'n' and the total number of terms in the sequence divisible by 3. -Explaining the concept of common difference and finding the common difference in the sequence. 1:04:36 Understanding arithmetic progressions involves finding the sum of terms using formulas. The video explains how to calculate the sum of terms in an arithmetic progression step by step. -Solving arithmetic progression problems by calculating the sum of terms using specific formulas. -Explaining the process of finding the sum of terms in arithmetic progressions with examples. -Demonstrating the application of formulas to calculate the sum of terms in arithmetic progressions. 1:12:42 Understanding mathematical formulas and calculations can be simplified by breaking them down into smaller steps, making it easier to solve complex equations like n / 2 * 2a + n - 1 * d. It is important to approach calculations methodically and with confidence to achieve accurate results. -Importance of breaking down complex equations. Simplifying calculations by focusing on individual components can lead to accurate results in mathematical problems. -Methodical approach to calculations. Following a systematic method and having confidence in solving equations step by step can enhance accuracy and understanding of mathematical concepts. -Significance of practicing calculations. Practicing mathematical calculations, even in a structured manner like children, can improve problem-solving skills and boost confidence in handling complex equations. 1:20:46 Understanding mathematical equations involving terms and values is crucial for solving problems efficiently. The video discusses solving equations step by step to find the values of variables in a given context. -Importance of understanding mathematical equations and values for problem-solving efficiency. -Step-by-step process of solving equations to determine variable values in a specific scenario. -Application of mathematical formulas and calculations to find solutions in a structured manner. 1:28:49 The video discusses the mathematical calculations involved in determining the total production of TVs over seven years using a specific formula and solving for the length of a spiral made up of concentric circles. -Calculation of total TV production over seven years using a specific formula and understanding the mathematical process involved. -Solving for the length of a spiral made up of concentric circles by considering the radii and parameters of the circles. -Deriving the total length of a spiral made up of concentric circles by calculating the parameters and common differences in the sequence. 1:36:54 The video explains a math problem-solving process step by step in Hindi, focusing on calculating the perimeter of a shape using given measurements and formulas. -The importance of understanding mathematical concepts and applying formulas accurately for problem-solving. -Encouragement to practice solving math problems independently to enhance understanding and retention of concepts.

Vote for these chapters 1-circle 2- Area realeated to circle 3- Triangles 4-Height & distance Pls bhaiya upload these chapters as soon as possible 🙏🙏🙏🙏

2024-2025 batch attendance here 🔥🔥

1:23:14 Let the number of terms be n. a = 24, d = -3, S = 78 S=n2(2a+(n−1)d) ⇒78=n2(48−3(n−1))=n2(51−3n) ⇒3n2−51n+156=0 ⇒n2−17n+52=0 ⇒(n−4)(n−13)=0 ⇒n=4,13 ???

Kon kon Final Exams ke liye dekh raha hai Like karo pass ho jaoge ache number leke 😂😂😂

This man is putting all the efforts to make our concept clear thank you Shobhit Bhaiya

35:30 If the principal amount is ₹10,000 and it's being increasing at the rate of 7% compond interest then the amount of money after 1 year would be ₹10,700.

Let's simplify and solve the equation: n[48 + (-3)(n - 1)] = 78 × 2 Expand and simplify: n[48 - 3n + 3] = 156 n(51 - 3n) = 156 Distribute n: 51n - 3n² = 156 Rearrange to quadratic form: 3n² - 51n + 156 = 0 Divide by 3: n² - 17n + 52 = 0 Factor: (n - 12)(n - 4) = 0 Solve for n: n - 12 = 0 → n = 12 n - 4 = 0 → n = 4 There are two solutions: n = 12 or n = 4 1:23:10

I used to think that this chapter is the easiest chapter of class 10, but I'm shocked to know that many people find it hard.

Vote for Surface Area and Volume, Triangles, Coordinate Geometry (Session 2023-24) 👇🏻

2024_25 attendance🎉🎉

Kon kon exam se ek din pehle ye vdo dekh reha hai ...😂

1:28:32 S7= (1250*7)/2. = 4375

As a senior i would suggest u all , trust him blindly BECAUSE OF HIM I HAVE SCORED 90% in my board exams he is putting his each and every effort just for u all love you sm bhaiya 🥺❤

1:23:20 there are 2 values of n. n=4 or n=13 For complete solution search this question on RU-vid

1Like=99.9%

TRIANGLE and circle must needed

Vote for trigonometry 👇👇👇

1:10:09 Actually 2005 hoga bhaiya, kyunki 1995+11 karte samay ham 1995 ke saal ko count nahi kar rahe, usko bhi count karke 2006-1=2005 ho jaegya... 5000 rupees- 1995 5200 rupees- 1996 5400 rupees- 1997 5600 rupees- 1998 5800 rupees- 1999 6000 rupees- 2000 6200 rupees- 2001 6400 rupees- 2002 6600 rupees- 2003 6800 rupees- 2004 *7000 rupees- 2005*

Exam is near Nothing is clear Don't fear Sobhit bhaiya is here 😂😂

1:30:50 mistake 625×7=4375

As a senior I just want to say that "abhi bhi late nhi hua hai bhaiyo aur behno abhi se hi aaj se hi padhai karna start kar do tumhare 90% kahi nahi jayenge" Best of luck ❤😍

Vote for surface area and volume 😊

2025 me board paper kon de rha hai

35:02 Sir Asked a question about compound interest. I want to share my answer. By Using Formula, Compound interest = Principal× (1+{Rate÷100})^time C.I. = 10,000 × {1+ (7/100)}^1 = 10,0000 ×{(100+7)÷100} =10,000(107/100) = 1070000÷100 = ₹10,700 Therefore,the required compound interest at the rate of 7% after 1 year when the principal amount is 10,000 will be ₹10700 Is my answer correct? It looks like commerce 😀 which is not my future aim......

I hope everyone will score 95 + in CBSE boards

1 like =90+ marks in every subject Don't take risk this is board time....

1:23:00 sum of 24+21+18 is already 63… by solving the quadratic equation in the answer we get n= 4 ,13 therefore n is 4 because the fourth term of ap is 15 and if we sum 63+15 the answer is 78…..

Aim: 100/100 in maths 🌸

11 March ko exam Dene Wale present here 👇👇

35:41 Compound interest is - 10,700

02:48​- Ch 1 Real Numbers 1:53:12​- Ch 2 Polynomials 2:59:27​- Ch 3 Pair of Linear Eq. in 2 Var 4:43:10​- Ch 4 Quadratic Equations 6:07:00​- Ch 5 Arithmetic Progressions

😢 I passed out 10th last year and Shobhit bhaiya is teaching now....I hope he taught us but still under his guidance I got 94% Thanks to you Bhaiya....

1:07:05 d=7 and a=3 so, the A.P forms as: 3,10,17,24....

26:25 ...3v/4 - v karenge na..... -v/4 thodi...

1:10:02 / correction 11th annual salary received by Suba Rao will be ₹7000/- It means after 10 years he'll get that money. If 1995 is 1st year than 11th year will be 2005

most funny time 😂1:06:59 .... well answer is a= 3 , d= 7

1:07:11 the ans is a = 3 , d = 7

1:30:45 Bhaiya wrong multiplication 625x7=4375

bhaiya pls make a video on triangles its really tough to understand even if i know the concept i am unable to use it in a problem and i loose marks my weakest subject is math but i am spending , so i am spending more time on it but still i dont get marks plssss help me out bhaiya

52:13 sir 18+1= 19 🙂❤️

How many of you are watching this video in 2024...?😎👍

I hope we all got 95% ❤

Legends watch this one day before exam😅😅😅

26:24 me sir a1 ka value v he but calculation ke vakt v/4 liya he. So ig ans most probably -¼ me ana chahiye tha. (Ps: rat me study kar rahi hu so wrong bhi ho saki hu❌)

1:7:30 subha rao carorpati😂😂😂

1 1:23:13 n-4th term

51:32 best part 1:07:03best part

Anyone in September preparing for mid term 😂😅😢

Aarambh batch se koi hai 😊😊

26:30 galat hai wo v/4 nahi v/1 hoga

N value is 4 or 13 this can be solved by splitting the middle term the equation is n^2 - 17n+52

1:31:32 bhayya woh multiplication wrong hai 625×7 hoga 4375

Shobhit bhaiya is teaching I am sure all of us score good marks in class 10th☺️

bhaiyaaaaaa i was eagerly w8ting for ur next lecture thank you sooo much bhaiyaa you have been supporting when we was in dark n relax mode..... lotss of love and supportt bhaiyaaaaaaaa💗💗💗

1:30:57 - the total production of TV sets in first 7 years is 4375 😊

24:21 ye smjh nhi lgga 😓

1:07:05 o Bhai sahab also bhaiya is a good actor 😅😅

You are a good teacher ,I hope the rest of the chapters are free as well

i would like you to please make videos on some of these topics as they are my weak parts: 1. pair of linear equations in two variables 2. quadratic equations 3. surface areas and volume 4. statistics i would be really grateful if you cover these topics.

a = 3 and d =7 01:07:00

Sir Can you pls made a One Shot on *Surface Areas and Volumes* my board exams are from 28-11-2023 and i dont know much about that chapter. i have watched your both AP and Trigno one shot's and it help me alot i can do almost all the questions. i really need One Shot video of you sir. cause ur the best teacher in Maths for real! and Maths matlab Shobhit Bhaiya!!

Standard math wale like kro.....dekhlo frnds board me achhi percentage ke liye 1 like risk mt lo

Legends who are watching this video before 1 day of board exam 😆🍻☠️

1:22:12 me ques ka answer hai n=13,n =4 splitting the middle term se hoga easy peasy

I am sad why you didn't upload this when we were in 10th..now we are in college You lucky guys🎉

It is very easy chapter just chill guys... I hope you all get good marks in yours boards Just blindly follow Shobhit bhaiya ❤

Maa Kasam jaldi se like kar do 🤐 jisne like nahi Kara wo to fail ho gaya 😭 DON'T TAKE ANY RISK 👍 jisne like kar Diya wo pass ho gaya 🎉

At 1:31:47 it will be 4375 625×7 = 4375

1:30:51 bhaiya answer 4375 hoga me dar gya mujhe lga mera galat hai !!! 😂😂

I am from SSC Maharashtra board but still I am watching for extra knowledge bahiya🙇...your teaching level is just wow

i am in 11th and watching shobhit bhaiya teach is really amazing 2024-25 batch is very lucky use it properly and make ncert your best friend (except maths) [an advice from senior]

1:01:51 Most Important Question

I have passed my 12 with 94% from commerce bg.....yet came here to thank him for putting effort when i was in 10 nd doing more for our juniors....thank you bhaiya once again

46:46 swag hai bhaiya ka‼️💯

Bhaiya, please do lectures on👇 1. Triangles 2. Circles 3. Surface area and volumes Please bhaiyaaaa

1:23:15 3(n2 - 17n+ 156) n=13 and n=4 both value can be used bcz sum of 5th term to 13th term is 0 and sum of first 4 terms is 78... Thanks Bhaiya... This Video/Lecture Helped Alot...👍👍

Question:how many terms of the Ap 24,21,18 ... must be taken so that their sum is 78? Ans:- 4

1:07:40 subha rao 💀 Subhashree rao 💀☠️

This video is very good bhaiya... Can u pls make video on triangle 😢😢.....😊