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Arrhenius Plots 

Allery Chemistry
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Arrhenius plots are just another addition this Nobel prize winning Swedish scientist brought to Chemistry. In this video you will find out how to calculate activation energy and the Arrhenius constant using an Arrhenius plot. Yes.. y=mx+c makes an appearance.

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15 окт 2016

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Комментарии : 112   
@HappyHorseJumping
@HappyHorseJumping 7 лет назад
Just wanted to say, I'm an A2 student (OCR) and need an A for uni. Thank you so much for doing these videos and putting in such effort. Honestly you are an amazing teacher, you make things simple to understand whilst making sure we understand why and how it works as well as just being able to do it which is really important for remembering in exams. So thank you so much. You make this so understandable in 14 minutes when at college I was struggling for 2 hours! Amazing teaching skills.
@AlleryChemistry
@AlleryChemistry 7 лет назад
Ah thanks so much! Means a lot to get feedback, I really never know how useful they are until people tell me. I hope you get your Amazon what a result that will be!! What are planning on studying at uni?
@HappyHorseJumping
@HappyHorseJumping 7 лет назад
Allery Chemistry yes they are very helpful, please keep making them!! Haha. I'm going to study Veterinary Medicine so need AAA. I'm studying chemistry, biology and geography :)
@JunkInMyTrunk_Shorts
@JunkInMyTrunk_Shorts 6 лет назад
Seeing as your exam has now passed how did it go? are you doing veterinary medicine?
@moe5965
@moe5965 5 лет назад
What did you get if you don’t mind me asking
@Levi-iv3nm
@Levi-iv3nm 3 года назад
@@HappyHorseJumping I'm curious did you get there? I'm in the same position now. Year 13, I need a AAB for Pharmacy! I'm studying Biology Chemistry and Computer science, though I wish I did geography instead of Computer Science
@joegirton7835
@joegirton7835 7 лет назад
so much clearer than the text books/revision guides. THANKS!!!!!!
@AlleryChemistry
@AlleryChemistry 7 лет назад
Great! So pleased they are helping you.
@gothamrues7510
@gothamrues7510 5 лет назад
Was so confused on this in class, you really have a great way of explaining tricky topics in a short amount of time very clearly and concisely :) This channel is a lifesaver, thank you so much!
@blippity.
@blippity. 7 лет назад
watching on the day of my exam. I wish I had found this sooner 😖😫
@abdoulrahoufououedraogo2682
@abdoulrahoufououedraogo2682 4 месяца назад
just warching 43 min before my exam. thank you
@gabs8240
@gabs8240 2 года назад
Thank you so so much this really helped me - I'm not a maths student and struggled with this concept. This clearly explained it to me and I finally get it!
@IshyB135
@IshyB135 6 лет назад
Thank you so much for this video you don't understand how easy you made this to understand I am so glad I found ur channel and I cannot wait to donate and listen to your podcasts
@crw9618
@crw9618 5 лет назад
Thank you so much for these videos; you honestly help out so many people including myself.
@lawrencium4101
@lawrencium4101 4 года назад
i didn't think I will ever understand this graph :) but your video is making a MASSIVE difference- thank you so much!! :'))))
@Blaze-ls3zw
@Blaze-ls3zw 7 лет назад
Definitely the hardest part of A level Chemistry imo
@AlleryChemistry
@AlleryChemistry 7 лет назад
Yes I think you may be right! Hope the vid made it a little bit easier for you.
@williamatkins9648
@williamatkins9648 2 года назад
Cannot thank you enough for this video you’ve explained it so well!!!
@naomijohnson5048
@naomijohnson5048 7 лет назад
Thank you so much, your videos are such a help!!
@waheebkhan270
@waheebkhan270 5 лет назад
I'm doing the A2 specification for Edexcel and you have clearly explained all of the points we need to know for our unit 4 exam. THANK YOU SO MUCH!
@khayzuranhunter9426
@khayzuranhunter9426 5 лет назад
I think you are brilliant Allery. I have to teach this and now I feel more confident explaining this to my students. Thank you
@tracye6595
@tracye6595 7 лет назад
Thank you very much for this!! very well explained and taught!! my understanding of this is so much better!! thanks once again
@subhaaffan5326
@subhaaffan5326 6 лет назад
Thank you so so much. My friend told me about u. I understnd this so much now and it looked really complicated so i left it to the last min.
@eesha5906
@eesha5906 5 лет назад
Okay this was AMAZING!! U were born to teach
@cphyk6923
@cphyk6923 2 года назад
Mans got such a cute smile 😊
@rainandnature214
@rainandnature214 5 лет назад
Thank you so much for your help! You're amazing.
@aupaaupa2377
@aupaaupa2377 4 года назад
You are brilliant, you make much more sense than my teacher
@amycollinson217
@amycollinson217 6 лет назад
paper 3 tomorrow chemistry A I was shocked how it was on paper 1 8 marks in total just on this split in 2 sections. Everything I didn't want coming up all came u- on a positive note I really appreciate your videos n I truly feel u don't get enough credit!!!! thank you
@lucian0043
@lucian0043 2 года назад
when i got that big number for lnA i thought my calculator was just broken and was trying to fix it, until i unpaused the video and realised that was the correct answer
@alanadyke3950
@alanadyke3950 6 лет назад
THANK YOU SO MUCH SUCH A GREAT HELP
@sabinahasanova7198
@sabinahasanova7198 3 года назад
Amazing explanation 👏 thanks
@noorjabban5687
@noorjabban5687 3 года назад
You are a life saver !!!!! Thank you so much
@AlleryChemistry
@AlleryChemistry 3 года назад
No worries!
@EpicandAwesome
@EpicandAwesome 7 лет назад
Couldn't have come at a better time! First test on Thursday
@AlleryChemistry
@AlleryChemistry 7 лет назад
Fab! Good luck for your test! Please share the video, the more people that benefit from it the better!
@user-nn4eh6wy8q
@user-nn4eh6wy8q 5 месяцев назад
Great video.Thank you so much
@benjamintempest4333
@benjamintempest4333 6 лет назад
Really helpful thanks so much!
@rabihanasir315
@rabihanasir315 3 года назад
This video is excellent! I have got full marks on my exam question, eventhough I'm not a maths student, I just followed the steps.
@AlleryChemistry
@AlleryChemistry 3 года назад
Excellent!
@hi-ow3hb
@hi-ow3hb 7 месяцев назад
So beyond useful!!
@AlleryChemistry
@AlleryChemistry 7 месяцев назад
Glad it was helpful!
@swiftietay99
@swiftietay99 7 лет назад
We are doing these next! Starting it thursday woo thank you xx
@AlleryChemistry
@AlleryChemistry 7 лет назад
A bit of a head start then! Better to do that than to be behind and struggling. Keep up the hard work!
@msocial845
@msocial845 6 лет назад
wow this is great thank you so much
@nchimunyabukoole5876
@nchimunyabukoole5876 4 года назад
Really helpful, thank you 😊
@AlleryChemistry
@AlleryChemistry 4 года назад
You’re welcome 😊
@user-on4si6rm1h
@user-on4si6rm1h 4 года назад
I have a question. When calculating A doesn't the section in brackets have to be multiplied by -1 as it is -(Ea/RT) ? As before, when you calculated Ea you did - (-11,000 x 8.31).
@nice1bruva199
@nice1bruva199 5 лет назад
thank you for being a hero
@EmanFatima-ic2be
@EmanFatima-ic2be 2 месяца назад
Thank you sooooo much!!!!!!!
@AlleryChemistry
@AlleryChemistry Месяц назад
You're welcome!
@MH-fq4vy
@MH-fq4vy 7 лет назад
how do you work out the units for A?
@MrArtbyart
@MrArtbyart 5 лет назад
Thank you. May I ask how to best convert the Arrhenius equation to solve for (or predict) 't' from the increase of carbon? Similar to Arrhenius' original predictions.
@Saad-qz3vv
@Saad-qz3vv 4 года назад
Just wondering that when you rearrange for Ea from -Ea/R= gradient why does the minus in front of the Ea not become positive so Ea = +(-11,000x8.31)?
@dilshan2032
@dilshan2032 3 года назад
Thank you very much..🖤
@AlleryChemistry
@AlleryChemistry 3 года назад
No worries!
@Simplyriri23
@Simplyriri23 5 лет назад
are the units for A dm^3mol^-1s^-1 (time stop in video is 13:49) or moldm^-3s^1? This was such a great video! I am currently revising for my year 13 mocks, so thank you!!!
@amiraibrahim9478
@amiraibrahim9478 6 лет назад
Hi, was wondering if you could cover the specification point for AQA on defining the terms order of a reaction and defining the rate constant. Just comment this back to me pls. I understand all the calculations and how to deduce the rate equation, but I’m not sure how to actually define these if asked.
@charlottekennedy8081
@charlottekennedy8081 5 лет назад
Hi I was just wondering why in the part for the calculation of the activation energy you put.......... - (-11,300x8.31) whereas you didn’t put a minus in front of the bracket in the calculation for A? Why wouldn’t it be -4= -(-1.1/0.1x10^3)? Sorry if it’s a silly question! Thanks for the really helpful video
@gduicplumtree
@gduicplumtree 2 года назад
Well said. It is confusing.
@eltonfernz9163
@eltonfernz9163 6 лет назад
just wanted to say that the units for A are the same as the units for K
@TopPlay_Tv
@TopPlay_Tv Год назад
Ur are the best ❤
@roxystobiecka
@roxystobiecka 7 лет назад
How did you get those units for A? (or is that a stupid question..)
@AlleryChemistry
@AlleryChemistry 7 лет назад
It's complex so you just need to remember them unfortunately.
@chichi_ix
@chichi_ix 2 года назад
Hello, once we know the value of A and the gradient, we could technically plot the graph, right?
@haloshoot3218
@haloshoot3218 5 лет назад
Thanks
@physchemwithliz5879
@physchemwithliz5879 2 года назад
Hi :) If we calculate A from a point on the graph, A is dependent on temperature, so wouldn't we get a different value of A from each of the three points (because of the different temperatures)? And when I use the actual y intercept to get A, I get a different value altogether. If we extrapolate your line back to the y intercept, it would be something like -3, so e^(-3) = 0.050 I'm probably missing something obvious. Help, I'm confused haha
@angelahalton8827
@angelahalton8827 3 года назад
Hi Chris, you explained this really well, thank you? To work out the arrhenius constant if the straight line touched the y-axis could you just get lnA like that?
@lucahervada3697
@lucahervada3697 3 года назад
Theoretically yes
@coomstar1235
@coomstar1235 5 лет назад
Legend
@dawitdereje2690
@dawitdereje2690 6 лет назад
Why is the unit dm3mol-s- at the end?
@swiftietay99
@swiftietay99 7 лет назад
Hiya! I was just wondering.. You know the last example in this video? It's so much more complex than the only one in my textbook.. And another textbook for the same spec doesn't have arrhenius at all! So where did you find this/do you have anymore/ did you make it up? And do you know if the AQA spec this year requires this difficulty of question because we can't find any hard examples more complex than rearranging. No gradient working out etc. 😕 thank you so much if you can help xx
@AlleryChemistry
@AlleryChemistry 7 лет назад
Yes you will need to know both. The spec requires you to know how to use Arrhenius Equation. This leaves it open for them to ask questions using an equation or graph. They are just using 2 different ways. I just made up the questions as there are very few questions available, it is very new to majority of boards.
@swiftietay99
@swiftietay99 7 лет назад
Allery Chemistry It's awkward with no questions to do! We have looked so long for some 😭Thank you so much for your help and thank you for your examples you gem!
@AlleryChemistry
@AlleryChemistry 7 лет назад
No problem at all. If you look through the old edexcel/OCR salters past papers you may find some on there. Edexcel/OCR Salters were the only board that had Arrhenius to my knowledge.
@fatimaa8770
@fatimaa8770 4 года назад
Why is it -(-1100*8.31) Why is there two minuses
@lucahervada3697
@lucahervada3697 3 года назад
@@fatimaa8770 It was -Ea/R initially, so to save some time in rearranging the equation later on, he minused a minus. -Ea = -11000*8.31. Hence Ea=-(-11000*8.31). Multiplying both sides by -1 to cancel the minus on Ea.
@mohammadmiah9727
@mohammadmiah9727 Год назад
there is another way to calculate A because its the y intercept if the line is extrapolated u can get a figure of A on the y-axis however the risk is if you are a decimal off, the result is a complete different answer
@ashrafmuhammad255
@ashrafmuhammad255 5 лет назад
Don,t we need to determine the value of k constant first to move forward to plote ln(k) on Y-axis and 1/T on x-axis. How to determine the value of ln k, when we don,t have value of k?
@sanabalmaqsood8576
@sanabalmaqsood8576 6 лет назад
Just wanted to ask is this for AQA
@amyadamson4285
@amyadamson4285 4 года назад
Was just wondering, do the exams give us both the original and the simplified Arrhenius Equations?
@AlleryChemistry
@AlleryChemistry 4 года назад
I would assume they don't give you the equation. But definitely check with your specification. The simplifying of it is definitely something you need to do though.
@missdahir123
@missdahir123 5 лет назад
you're the best
@henrynyirongo8761
@henrynyirongo8761 5 лет назад
So it does not matter which constant and temperature you choose when calculating the Arrhenius equation?
@ramkumarneerathilingam5242
@ramkumarneerathilingam5242 6 лет назад
I want know how to convert from Differential scanning calorimetery graph into Arrhenius graph
@AlleryChemistry
@AlleryChemistry 6 лет назад
Not on A Level spec so not needed.
@zahradaneshgar4331
@zahradaneshgar4331 5 лет назад
Can u zoom into the board a bit please
@angelahalton8827
@angelahalton8827 3 года назад
Also how did you know the units for A? Thank you
@queenbless7787
@queenbless7787 Год назад
am a bit late but apparently its complex so u just need to know them
@annajones3451
@annajones3451 4 года назад
Stupid question- is 1/t time or temperature? If it’s time, where does the temperature part fit into all of this?
@amyadamson4285
@amyadamson4285 4 года назад
Absolute temperature (K)
@slfmfilmproduction9071
@slfmfilmproduction9071 5 лет назад
THANKS just saying!!!!!
@User-ts2jj
@User-ts2jj 6 лет назад
is the formula given in the exam?
@bilalkhalid742
@bilalkhalid742 7 лет назад
Hi I think I get it mostly but when you worked out Ea you did -Ea/R but what happened to the T I thought it should be -Ea/RT... I think the T was the 3.1?
@mcrrocks897
@mcrrocks897 7 лет назад
If y = mx + c, and lnk = lnA - Ea/RT, y = lnk, c = lnA, and what's left is -Ea/RT. -Ea/RT can be re-written in the format -Ea/R * 1/T, as when they're multiplied, they form -Ea/RT. The mx, can therefore be assigned as x = 1/T (which is why it forms the x axis), making m (or the gradient) be equal to -Ea/R.
@bilalkhalid742
@bilalkhalid742 7 лет назад
Louis Greenhalgh thanks for replying 1 day after my chem exam 😂😅it's okay it never came up
@mcrrocks897
@mcrrocks897 7 лет назад
Depending on your spec, it still could. It's on my next paper (edexcel paper 2) and could also be on paper 3
@bilalkhalid742
@bilalkhalid742 7 лет назад
Louis Greenhalgh it can only come up in paper 3 now, I hope it does I was kind of upset it didn't come up in paper 1
@NikeetShah
@NikeetShah 7 лет назад
the gradient is equal to -Ea/r 1/T is your x coordinate , so as we worked oout gradient we equate it to -Ea/r
@kieranlynch9950
@kieranlynch9950 7 лет назад
how was ln(K) value found? I'm guessing experimentally and then ln( 1/time)
@IshyB135
@IshyB135 6 лет назад
Lnk is the y axis
@amyadamson4285
@amyadamson4285 4 года назад
Assuming the rate constant can be found from the rate equation? however the initial rates needed to find the rate constant (k) are found experimentally.
@JBCJackson
@JBCJackson 7 лет назад
good timing for this video lol
@AlleryChemistry
@AlleryChemistry 7 лет назад
I must be psychic!
@JBCJackson
@JBCJackson 7 лет назад
Can you do a video on directing groups?
@sososoawesome1
@sososoawesome1 5 лет назад
why is k proportional to 1/t.
@lewdscholar8175
@lewdscholar8175 5 лет назад
Anyone watching just before 2019 exams???
@ramkumarneerathilingam5242
@ramkumarneerathilingam5242 6 лет назад
This video for not clear
@AlleryChemistry
@AlleryChemistry 6 лет назад
In what way?
@subhanahmed4879
@subhanahmed4879 4 года назад
Allery Chemistry are you sure your LnA/A calculations are right sir? I’m even more confused