Yes, these materials are still tested on the digital SAT. If anything new is added, will create a new video. Guys, so I don't know what I was going through that day but the correct answer to the first question is 8. Ignore the little 4's added in and just follow the audio (what I say in the video) . 🏆 3-Step To 700+ On SAT Math Without Naturally Being Good At Math [Free Masterclass] www.admissionhackers.com/free-training-summer . 📚 SAT Math Accelerator [6-Week Prep Course]: www.admissionhackers.com/sma
i was solving and waited for your answer, then i saw 4 and im like shit! i started breaking my head over it coz the problem was too simple, then i saw this, lol XD
in case anyone's confused about the problem at 0:44: you have to use the properties of quadrilaterals as well as the inscribed angle theorem to set up an equation and solve for x. all the inner angles of a quadrilateral add to 360 degrees, and the inscribed angle theorem says that an inscribed angle (angle with the vertex on the circumference of the circle) is equal to half of the central angle subtending the same arc. this tells us that a=x/2, and knowing that P=360-x we can set up an equation to solve for x as follows: 20+20+x/2+(360-x)=360, which simplifies to x=80. hope this helps!
what worked for me is that I created a new line segment by connecting point P to point A. Line A creates two isosceles triangles on either side of point P. Becuase both legs of the icoscesles triangles have the same angle, I was able to to find that the triangles vertex is equal to 140, as s 2(20)+x=180. then I used the vertex's angle to find the value of x by doing: 2(140)+x=360 which simplifies to x=80.
One more tip. The kite type figure is called a cyclic quadrilateral and it has a property that opposite angles are supplementary ie if that was 60 the other ones 120 straight away
example 1 (3:14) becomes even easier if you use s=θr for arc length where θ is in radians. 180° is equal to π radians, so you end up with 8π=πr for your equation. if you know this, then getting the answer becomes much easier because all you have to do is divide out π. 8π/π = 8, the answer is C. if you're familiar with radians i'd definitely recommend you use them for problems like this example 2 (7:25) also becomes easier if you know that 120° is equal to 2π/3 radians. if you keep the radius as 96/2π and plug it into s=θr, you get s=(2π/3)(96/2π). 2π cancels out and 96/3 is 32.
@@bestselfimprovement3 radians are a different unit for measuring angles and if you know what they are and how to use them the first two examples in this video become easier and faster to solve
@@tylermorris8856 this works perfectly, and if you prefer degrees make sure your mode of your calculator suits, as well as keeping in either degree of radians, I can see you took pre calc definitley
The benefit of using radians is nullified by the fact that (I'm pretty sure) the SAT never uses radians on their questions. Radians get introduced in pre-calc, which is outside of the scope of the SAT. So if you wanted to use radians, you would have to convert to it from degrees. IDK about you, but that doesn't seem worth it to me.
Yes, but if you work with radians you end up memorizing a bunch of values and their degree equivalents. If it's not worth it for you then don't do it but if you can convert quick it's faster
I genuinely wanna thank you, you put efforts into your videos and honestly I don’t know what would i do if you didn’t make these little videos. They have helped me immensely. I don’t stand a chance when it comes to maths but I guess that’ll have to change now lol ❤ thanks man!
math has been my best subject in everything for as long as i can remember but these SAT math questions screw me over so bad to the point my R&W scores are unbelievably higher. so thank you for making these life changing videos because my whole life depends on this score, literally.
A little shortcut for 4:43, C represents circumference = 2 pi x r or pi x diameter. The Arc length: Circumference multiplied by the angle over 360. Basically 96 x 120/360 = 32. There's no need to do the extra.
@@gauravnath8926 I’m sitting on August 28. The only reason I’m taking it this early tho is because I’m required to for a program. Only had around a month to prepare;) Wbu?
@@n-kay9676 so basically i still have not decided as i havent registered it yet.... looking for a comfortable month to write the exam ! well when did you start your prep for SAT ?
@@gauravnath8926 well I just finished a five-week sat course and I guess I’m sitting in August because I figured I should take it while the info is still fresh yknow. Btw, I registered for October as well ( I need a decent grade by December). For you, how long have you been studying? Are you required to take the test as soon as possible or is it flexible? Nevertheless, I suggest you take it in August and try your luck! After all, you can redo it as much times you want and there’s still enough time for the August exam! :)
I forgot to mention, I’ve heard that the grading is going to be lighter in august and brutal in may and October, I’m not sure if this is accurate but better safe than sorry
thank you so much i always had difficulties with these type of problems, now i finally understand them. i also have the sat this saturday the 13th im extremely nervous.
TIP- the circle characteristic question- there circumference is already given. So you don't need to find the radius. Just plug in 96 where 2pir is present. As circumfrence=2pir.
For the first question, just use the formula for calculating length of an arc but in radians not in degree => Let angle = § r§ = 8x pie In radians the angle § = pie so those two cancel out Hence, radius r = 8
hey John, whatever I try the radius equals 8 in question#1. But the video corrects it saying it's 4. I just want to make sure if it is correct. I really love your videos. I am so nervous right now, MY SAT IS TOMORROW!
I just found your channel from a reel on RU-vid and you just earned my sub because you make math extremely easy and your amazing please Do calculus Integral’s I would greatly appreciate it
The first question can be solved by using the arclength formula s=r*theta,where r is the radius and theta is the angle measured in radian. Since the arclength is 8pi and the angle is pi radian, by comparing to the formula, the radius is 8.
Hello My dear teacher. I got nearly the whole concept about circles. Btw, the beginning is kinda same situation when i faced in circle ⭕ questions But not from now on. Thank you so much again. You rock. ✊✊✊✊✊✊✊✊🙂😊😊
Although using the degree based formulas still works, I think using the radian based formulas is more time efficient and intuitive. Arc Length = s = (r)(angle in radians) Sector Area = A = (½)(r^2)(angle in radians) Even if you have to convert from degrees to radians, I think it’s still faster and the numbers you get are smaller which leads to fewer simplification mistakes.
for the problem shown at 5:40 you could also solve it visually! as someone bad at geometry, i like to just see that section LNO is about 1/3 of the circle so then 96 divided by 3 would be 32. it happens to be the answer! :)
Hiii, i watched all of these videos took notes and studied hard with other resources too but mostly these vids honestly thank you it was so much help but i think some of the 21 vids werent very helpful and just a waste of time(no offense) because it wasnt on the test i think there are some topics that maybe you can go over more. Btw ij took the test this morning lol some vids def helps too. ill see my score on the 6th wish me luck!!!🤞🏾
For the arc length question, all I did was use the C=pi*D formula. Since a diameter cuts the circle in half, and one half of the circumference is 8pi I just plugged that into the formula. So it would be, 16pi = pi*D. Then, you would divide by pi on both sides to get D = 16. Radius is 1/2 diameter so just do 16/2 = 8. Would that be an acceptable way of approaching this problem?
guys for the first question theirs a even easier method to solve it in my opinion you can set up a proportions to find the entire circumference of the circle. the first thing you do is write a ratio saying 180/360 is equell to 8pi over x and u cross multiply and u find the circumference of the circle then you can use the circumference formula witch is 2piR and solve for the radius and u get 8
7:56 or you can just do it the easier way. We all know that the formula to solve for arc length is (2πr • θ | 360). You already have the angle at the point of intersection which is 60 & you have the circumference which is 96 and is technically the (πr) in 2πr. Now just plug in all the values in your calculator. It is going to be ( 2 x 96 x 60 divided by 360 ) = 32 :D
Simple tricks for the ques For the first ques 2(pi)r=8pi R=8/2=4 For the second ques just know that the a angle substended by the tangents is half the angle at the centre by the same arc
Quick note. On question 2, you could have skipped some steps by noting that the central angle is twice the exterior angle of 60 degrees. I'm pretty sure that's a theorem.
Thank you sooooo much for this video🥺🥺❤️❤️❤️…VERY EXPLANATORY AND EASY TO UNDERSTAND..you helped me on this one ❤️. Going to watch more videos but first I’ll watch your “stop watching SAT videos (including mine)” video😭🤣❤️
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