B.Sc. II Year | Oxidation State of Lanthanides | लैन्थनाइड की ऑक्सीकरण अवस्था

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B.Sc. II Year | B.Sc. 2nd Year | B.Sc. Second Year | Inorganic Chemistry | Oxidation State of Lanthanides | अकार्बनिक रसायन | लैन्थनाइड की ऑक्सीकरण अवस्था
You can learn about oxidation state of lanthanides with the help of this video.
Suggestions are always invited in comment section.
Thanks,
Learn Chemistry Online.

Опубликовано:

23 сен 2024

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Комментарии : 21

@LearnChemistryOnline 4 года назад

There are some mistakes in electronic configurations of Tb to Yb. Kindly add one electron in each 4f of Tb to Yb.

@krishnarathoree 4 года назад

Your way of teaching is really osm..

@ChandankashyapLH 6 месяцев назад

There are some thermodynamic and kinetic reasons for which lanthanides show different oxidation state.

@pranjalnamdev6993 4 года назад

Sir bahut acha explain kiya aapne 👍

@komalshekhawat6351 3 года назад

Sir jaise ce +4 e tyag kar xe ka sthai vinyas prapt kar leta hai lekin sir pr +3,+4 o.s rakhta hai i mean ye to 3,4 e tyag kar xe ka sthai vinyas parpt nahi karta xe ka vinyas parpat karne ke liye 5 e tyag ne hoge or is ki o.s +5 hogi lekin esa nahi hota hai kyu sir ??????

@LearnChemistryOnline 3 года назад

5th electron ko remove karne ke liye jayada energy ki requirement hoti h.

@komalshekhawat6351 3 года назад

Ok thanku sir

@adarshup9012 2 года назад

Thank you sir or solve my doubt

@varshajangra7467 4 года назад

Thanks sir 👍👍👍

@varshajangra7467 4 года назад

Sir plz upload video on qualitative and quantitative analysis of Inorganic chemistry

@LearnChemistryOnline 4 года назад

@morisd5066 2 года назад

Error: 2:50 from Tb to Yb all electronic configuration are incorrect Tb = 4f9 5d0 6s2 Dy = 4f10 5d0 6s2 Ho = 4f11 5d0 6s2 Er = 4f13 5d0 6s2 Tm =4f13 5d0 6s2 Yb = 4f14 5d0 6s2 Lu = 4f14 5d1 6s2

@LearnChemistryOnline 2 года назад

Yes. I have already mentioned it in pinned comment.