balancing a redox reaction / oxidation number method 

Dr McCord you just balanced my grade! Thank you sir!

simple and straightforward . i thought id NEVER understand this . thanks a lot sir u really helped

I FINALLY UNDERSTOOD THIS, NEVER THOUGHT IT WAS THIS EASY, THANK YOU SO MUCH❤️

Just straightforward, no time stalling and yapping, thanks a lot

You just did this better than my teacher tysm

what a fucking king, I love you Dr. McCord

Thank you so much for teaching! U help me understand how the method work by the simple way.

best chem guy on yt

TQ so muchhhh...I wasted 30 minutes before watching this vedio..in search of this concept

that was clear and extremely helpful with the steps. thank u

Thanks for this diluted easy video

thank you!! I finally understand and I'm so relieved I want to cry

You saved my day Thank you so much

Thank you, sir. You helped me before my exam

Thank you sir, really helped a lot

thank u so much... understood the concept easily

Thankyou soooooo much. I watched many videos but not this simple thankyou once again❤

How do you figure out how many electrons are canceled out?

thank you so much saved me for finals

This is so awesome! I even understood when I have nothing to do with Chemistry! I got interested and was thinking, what if one of the half reaction’s change of charge is 0? I figured the 8step method does not work in that case. Then we cannot put coefficients to balance it out. Is there an easy step by step way for such a case?

Wow, thank you so much!! I understand it so well now :)

This was soo helpful!

thank you bro. you just saved my average

too cool keep up the good work

Thankyou sir you made it so simple brilliant.

I never got this from class.. Thanks u Ve really done a great favour.. 🙏

thank you sooo much for the best explanation ever!!

Thank you very very much made it very simple 🙏🏻🙌🏻✨✨💫

Nice explained

Thank you so much for this video 💯👍🏻😀

Brilliant Video

Was pretty helpful

the best method!!

understood perfectly !

how is the MnO4 is +7 like how we knew that please answer

Nice. Thanks a lottt

where did u get the oxidation number of Mn

Since hydrogen is more electronegative than manganese, how is it that hydrogen seemingly displaces managanese in forming water/ hooking up with oxygen.?. I could be way way off in what's actually taking place. Same thing with iron. It is more electronegative than manganese, so why would it be oxidized and manganese reduced? This is a pretty freaky reaction to me. Does it have to do with the reaction occuring in an acidic solution?

Well understood now

Thank you soo much sir ❤

GOOD VIDEO

SOMEBODY HELP! @ 0:55 If there isn't the same number of atoms of species that are not O or H like in: N2O4 + Br^- > NO2^- + BrO3^- What do i do??? i tried just multiplying NO2^- times 2 without changing anything else including the difference in oxidation numbers (+4 - +3 = -1), and the other difference of Br being -1 - +5 = -6, i ended up having to multiply the reduction half reaction by 6, so 6N2O4 and 6(2NO2^-) = 12NO^-, but eventually the charges on the two sides did not match taking into account the protons and all

How do you know which oxidation to use?

Thank you!!

Humble is that you..?

This method looks very similar to the ion electron method

How is manganese +7

thank you sir

Thankyou so much!!!!

Thank you🙏🏿🙏🏿

What if I take 2O2 on right hand side instead of 4H2O

Thank you sir❤

Thankssss brooooooooooo

Wow 🔥🔥🤩

thank you bro

Thank u soooo much !!

How do l know that manganese oxide is going to be decomposed to manganese 2+

Thanks a lot

Thank you chemistry jesus🙏🙏

I don't understand

thanks

Tq sir ......😊

Thank you I love u

Thankss❤

Omgg cool

The Same To You

2:29

j

Thanks