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Beam rigid body equilibrium example 

Terry Brown Mechanical Engineering
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This video screencast was created by Dr Terry Brown at the University of Technology, Sydney with Doceri on an iPad. Doceri is free in the iTunes app store. Learn more at www.doceri.com

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19 сен 2024

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Комментарии : 49   
@jaffer395
@jaffer395 8 лет назад
THANK YOU SO MUCH ... You are super understandable and you have great explanation skills ...YOU ARE JUST GREAT
@TerryBrownMechEng
@TerryBrownMechEng 8 лет назад
+Ali Jaffer thanks for the feedback. Glad it was helpful for you.
@frozenporcupine
@frozenporcupine 2 года назад
watched this 1 time and totally understood the material. tq
@brandonflorida1092
@brandonflorida1092 3 года назад
Crystal clear! Thanks.
@villyblock938
@villyblock938 2 года назад
Very good! I like how you took the time to explain every step in detail thank you!!
@TerryBrownMechEng
@TerryBrownMechEng 2 года назад
Glad it was helpful. Thanks for the comment and feedback. All the best with your studies in engineering.
@funkim96
@funkim96 9 лет назад
how do we know if it is going to rotate in clockwise or not? when we calculate moment, I thought 600sin45 would be plus.
@emmanuelheri3457
@emmanuelheri3457 2 года назад
Thank you!
@jonathansanchez2854
@jonathansanchez2854 Год назад
just to see if I understand even though I know this is super late sorry, if bx wasn't on the same line of action as A then you would take moment at B?
@TerryBrownMechEng
@TerryBrownMechEng Год назад
hi @jonathansanchez2854, sorry for the delayed reply. How are you going with your understanding? Your question indicates that you may have some misunderstandings. If you still need me to reply, please let me know. cheers.
@ye-absrat3258
@ye-absrat3258 7 лет назад
it was really helpful. thanks a lot sir.
@shizuchuan
@shizuchuan 2 года назад
Why is studying these shear and moments in a beam studied in mechanical engineering? Are there any applications?
@TerryBrownMechEng
@TerryBrownMechEng 2 года назад
thanks for the very good questions. Sorry for the delayed reply. Any structural component that has length greater than about 5x the other two dimensions can be considered a 'beam'. Of particular interest is the moment because we use this to calculate the normal stress due to bending, i.e. normal stress = My/I. A typical example in a mech eng application is a power/torque transmission shaft.
@aynil7487
@aynil7487 2 года назад
11:02 hello sir, why you didnt use Rbx ?can you guide ne please? Thanks for your videos ...+Rby×7+Rbx×7???
@TerryBrownMechEng
@TerryBrownMechEng 2 года назад
Hi, thanks for the question. Taking moments about point A, the line of action of Rbx passes through point A, therefore the perpendicular distance is zero. And therefore Rbx has no moment about point A.
@abamalarcon3526
@abamalarcon3526 Год назад
Do you have video of this but the condition is that; moment of A from 4meters moment of b from 3meters
@TerryBrownMechEng
@TerryBrownMechEng Год назад
Hi Abam, sorry, I don't have any other videos of this problem. Also, I don't really understand what you mean by "moment of A from 4 metres". A is a just a location on the beam. When we talk about moments, we talk about the moment of a force (or sum of moments) about a particular point, e.g. A, B or any other convenient or relevant point.
@emmanuelamanale4505
@emmanuelamanale4505 6 лет назад
fantastic sir
@MrAnon73
@MrAnon73 Год назад
I'm not sure if you're still around Mr Brown, and I looked through the questions to make sure this wasn't asked already, but i am curious to why the Rbx reaction is running left to right (+), as it is a pin and I see the push force from the other end (+600cos45) is also running in the same direction, wouldn't that make the reaction at the pin (Rbx) oppose that +600cos45 force, thus be negative? I saw in the comments someone say you didn't use it anyway because it was in line with a moment, thus this is sort of moot. but just curious to the theory as reactions sort of confuse me. Edit: Having finished the video, I guess for both horizontal forces to =0 (to be in equilibrium), one has to be the negative of the other. Instinctively feel wrong though, but adds up.
@TerryBrownMechEng
@TerryBrownMechEng Год назад
Hi, yes, I’m still around, but missed your comment. Sorry. Yes, Rbx will be negative and that is the answer that I get at about the 13min mark. Your last sentence indicates you may have some misunderstanding about moments though.
@MrAnon73
@MrAnon73 Год назад
@@TerryBrownMechEng I guess I I may be conflating horizontal equilibrium (LHS forces=RHS forces), where a moment is force x distance about a point, so I assume the reaction force will be the same but in opposition? I'm studying mechanics 1, we're looking at forces through a dissected beam currently. I did have an "A-ha" moment last week realising that the bend above and below the horizontal axis of the beam (tension and compression) indicates which direction the moment goes in (as often the reaction forces feel instinctively opposite to what I feel, I guess a reaction is always going to be opposite to the applied force) But thank you for replying, you must truly have passion for this subject.
@TerryBrownMechEng
@TerryBrownMechEng Год назад
Sometimes our instinct/intuition is wrong. Good and correct free body diagrams and use of the equilibrium equations will tell us the ‘truth’. Keep thinking more deeply about what you’re doing, and asking questions, and you’ll get it.
@MrAnon73
@MrAnon73 Год назад
@@TerryBrownMechEng I'm studying distance education, so just reading textbooks really. So your videos help thank you.
@eoin6952
@eoin6952 2 года назад
I could be 7 years too late but if I took the moment around B instead of A would I include the 200N acting on point B at all or would I ignore it?
@TerryBrownMechEng
@TerryBrownMechEng 2 года назад
Eoin - not too late, I'm stil here :) . If you take moments about point B, the moment effect of the applied 200 N force about point B is zero (since the perpendicular distance from the line of action of the force to the point is zero). Try it and see that you get the same answers. This is a good way to check your equilibrium equations and calculations.
@eoin6952
@eoin6952 2 года назад
@@TerryBrownMechEng thank you very much!
@ngumihlesleyndiseh6296
@ngumihlesleyndiseh6296 5 лет назад
Thank you... 🤗
@አይናችንነሽማርያምአንችን
thanks a lot sir.
@alinasser4496
@alinasser4496 9 лет назад
Would we reach the same answer if we took the moment about point B instead?
@TerryBrownMechEng
@TerryBrownMechEng 9 лет назад
Ali Nasser Yes. Assuming you do the equations and algebra correctly. Give it a go and find out. This is a good thing to do anyway to check your calculations.
@christopheranderson6831
@christopheranderson6831 Год назад
Why is that length a .2 and not a 2??
@TerryBrownMechEng
@TerryBrownMechEng Год назад
the 0.2 dimension is the distance from the centre-line of the beam to the top of the beam (i.e. the beam is 400mm deep)
@teolapad485
@teolapad485 3 года назад
Nice👍👍
@Engr9
@Engr9 Год назад
Please make more videos sir
@TerryBrownMechEng
@TerryBrownMechEng Год назад
Thanks for the feedback. I will do so. I have a few new ones that are unlisted at the moment that I will make public soon. Do you mind telling me whether you are one of my UTS students or not?
@Engr9
@Engr9 Год назад
Hi Sir. Thank you for your reply. Your videos are very helpful. Unfortunately, I wasn't one of your UTS students.
@TerryBrownMechEng
@TerryBrownMechEng Год назад
thanks for letting me know. And thanks again for the feedback. I sometimes wonder how worthwhile it is doing these videos as there are now many others doing similar and better e.g. ru-vid.com and ru-vid.com. Wishing you all the best for your engineering studies.
@SukhwinderSingh-ug1sx
@SukhwinderSingh-ug1sx 3 года назад
Sir if 600 N force at on point A and angle is unknown then?
@TerryBrownMechEng
@TerryBrownMechEng 3 года назад
Sorry, i'm not quite sure what you're asking.
@SukhwinderSingh-ug1sx
@SukhwinderSingh-ug1sx 3 года назад
@@TerryBrownMechEng sir im sorry it's just autocorrect. I'm asking if in the same question the angle of inclined force is not given then?
@TerryBrownMechEng
@TerryBrownMechEng 3 года назад
@@SukhwinderSingh-ug1sx if the angle of the 600N force is not given, then you can't solve the problem.
@SukhwinderSingh-ug1sx
@SukhwinderSingh-ug1sx 3 года назад
@@TerryBrownMechEng because the unknown would be more than the equation?
@TerryBrownMechEng
@TerryBrownMechEng 3 года назад
@@SukhwinderSingh-ug1sx kind of, I guess. But really, in this case, it would be because you would have incomplete input information.
@elizabethessien4558
@elizabethessien4558 3 года назад
the whole show
@friedabokkie2511
@friedabokkie2511 2 года назад
I think the 200 its negative cos its going to be clockwise
@TerryBrownMechEng
@TerryBrownMechEng 2 года назад
do you mean the 200 N.m applied couple moment? I'm not sure why you think it is clockwise, the curved arrow is indicating anti-clockwise. If you mean the 200 N force applied at end B, then yes, it will cause a clockwise moment about point A and I have shown that moment as negative in my solution i.e. -200 x 7
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