Best Trick to solve Compound Interest Problems | Maths by Sumit Sir 

Guruji i am from Hyderabad..Telugu mother tongue though ur teaching poved language not necessary for concepts...tq guruji...Paahimaam Paahi Paahi....🎉❤❤❤❤❤😊

Super sir.,. aapke jesa koi teacher nehi hoga

sumit sir's concepts and trick are superb! thanku so much sir ❤️❤️🙏🙏

Thanks sir for the wonderful concept ...🙏 It's kinda similar to tree method taught in SSC coachings . But with you we get more depth .. Pls explain the HW question sir..

U r great Sir..

sir directly ratio of difference between CI and SI for 3years to that of 2years=(3+(r/100)) therefore,(3+(r/100))=19/6 r/100=1/6 so we can say that 1/6 = 16⅔% directly.

Thank you sir

Jabardasth technique sirji

Amazing trick sir

Thank you sir 🙏🙏🙏🙏

Great Mathematician 👍

Sir second question m principal pucha gya h to P=xcube mana tha ager whan X ki value put kre to P=2000 ayega wo principal nhi h ? Please tell

Math magician 😊😊

Nice 😊

Sir, Plzz explain hw. Question

Nice sir

75000 ANS... TQ SIR FOR CONCEPT

R= 8% P= 75000👍👍tq sir

( IN TERMS OF RATIO ) 1ST YEAR = 64 2ND YEAR = 72 3RD YEAR = 81 RATIO REMAINS SAME 8 :9 RATE % = 1/8 = 12.5% 480 = P* (12.5) 2 / 100*100 P = 30 , 720 RS

Plz sir next class me explain kardijiye

rate 12.5 percent , principal = 30720 thank u so much sir 🙏

Wealthy classes

Anyone explain h.w sum🙂

❤️

genuïne teacher

Yes sorry..... x=8 R=12.5% P=30720

30720

Wrong concept ❌ 1) You cannot imagine Principal = x^3 for your own 2) This concept is not applicable in 2nd question if we don't take ratio.

Exam m ye sb kaam ni krta 😒😒

Thank u sir