It's crazy how paid teachers have much lower efficiency in delivering the knowledge than you guys, if I one day become rich I would like to support you guys handsomely! Thank you.
Your explanations are awesome 👌. So many concepts in just one video.This kind of study material will get any student interested in the subject. I don't think I have to revise it again. Thank you so much.
@@Devilhunter69 college tends to deepen what you learn in highschool in my experience. well actually i'm in university but anyway. i'm doing computer science so the physics level is closer to high school level but still bit higher than what i learned in highschool. it uses basically the same material but has more explanation and where the formulas are from and uses more calculus.
You have to use r^3 if you dont use the unit vector. the guy used unit vectors which is why he uses r^2. for more info you can look at the english wikipedia article about biot-savart
@@user-cc7ks7re3w the other explained it pretty well, you can either use unit vector in the direction of radius to denote the vector for radius, or just simplify the unit vector which turns out to be *r* /r , plug this value instead of unit vector and you'll get the textbook equation
Isn’t this finding just the magnetic field as it is affected by the length of dl? So to find the total force applied on a single point you would need to do multiple equations? Or should you just use the perpendicular measurement (since it is where force is strongest) for an estimate?
by any chance were you born in South India and moved to New-York or California?? Just curious about your accent. Great video by the way it was very very helpful
This is Anand Srinivas, reason for Byju’s initial exponential growth. His lectures are still there on Byju’s channel. He’s from Tamil Nadu and a BTech grad from NIT Trichy
I appreciate your efforts. But you lacked in explaining why magnetic field changes when we change angle. You just explained the effect but skipped the cause...!
Concept: Vectors - Cross Product Suppose we have two vectors, A=2i+3j and B=4i−j where i and j are unit vectors along the x and y axes, respectively. The cross product A×B is given by: A×B= ∣ i j k ∣ 2 3 0 4 -1 0 Now, calculating the cross product; A×B=(3×0−(−1)×0)i−(2×0−4×0)j+(2×(−1)−3×4)k we get: AxB =0i-0j-12k A×B= −12k. [It is in the negative z- axis] But in this case if we do B x A: By doing the same method again as shown above but putting values accordingly. Mathematically the relationship is expressed as: B x A = - ( A x B ) A x B= -12 (as calculated) B X A = - (-12k) = +12k [it is in Positive Z axis] Difference in the direction!! Similarly, we cannot write r x dl.
Hey in ncert textbooks we have inversely proportional to r^3 relation but here it is r^2. also your calculation from solving vector equating down to magnitude equation is wrong
Notice that in ncert the cross product is between dl and r VECTOR(and not r cap)... r vector is essentially the magnitude of r multiplied by unit vector of r(r cap) Therefore, dB = I dl × r / r³ = I dl × mag(r).r cap/r³ The magnitudes in the numerator and denominator gets cancelled and we're left with dB = I dl r cap / r² both derivations are equivalent. You can use either Hope this helps
In his equation, he has taken the unit vector of r that is r cap. But in textbook it is vector r which is equal to the unit vector times the magnitude of r so we have to multiply r on numerator and denominator to get db = μ0/4π x I dl × vector r/r^3
