Bisection Method made easy 

speed 1.25 thank me later

1.1562 is not the approximate root (1.1484,1.1562) are the intervals The approximate root is suppose to be in the "X" mark .C is the approximate root . Correct me if I'm wrong 😢

The third difference b-a is 0.25 not 0.75 . But I understood the whole concept clearly. Thanks for such a great explanation.

on the 3rd interaction b-a is 0.25

12:43 “ Thank you “ Me: No sir, thank you 😊

Sir how you consider the limit is 0.01

3:29 I was searching bisection method tutorial because of finding this questions answer.. Thanks Man :D

Your technique is good but *THE* *ANSWER* *IS* *C* *NOT* b

Thanks so much for the lectures. But i think there is a small mistake at the 3rd iteration in B-A =0.25 not 0.75

@ANEESH DEOGHARIA From where the value 0.01 come from? Why we need to do up-to

Speed 2.0 is also better man....😅

Shouldn't we take the C value of the 8th iteration instead of the b value!?

Sir as u said when b-a

How to solve a positive root of the following equation using by bisection method 2x=3+cos x

Hello permission to use your equation for sample report purposes. Thankyou. ...RUEL BACTONG JR. BS ENVIRONMENTAL ENGINEERING 4

The value of root must be the mid-point which lies between a and b...so logically final answer should have been the final value of c...why is b's final value considered as the answer?

Plz solve the logarithms problem...

how did u come up with 0.01 as the limit were we should stop

I don't know if you will see this but I got to ask; Why pick the last value of b as the approximate root instead of that of a?

I really appreciate this man, I so understand bisection method now.

What is the use of f(a) and f(b) in the table?

I didn't understand from where did 0.01 value came.. Can somebody please explain about it

Thanx alot but Y ain't u using ( B-A)/2

Why did the root come from b

Why did u chose the final value at B?why not on A?plz help

I really learned from your video I have a small comment here (2:25): I believe the interval should be like that (1,2), because if either 1 or 2 is the solution to my problem, they would have yielded a zero when substituting them above.

why the root approximation is taken from value of b not the a value?

Sir, how can u say that , we can stop the iterations when b-a < 0.01

thank you so much this video has made this method understandable. You're a champion dude

hello, thanks a lot, how we get 0.01 value?

How u have said that value of b-a < 0.01 in this sum ?? Doubt ???

A very good explanation I never met with... Thanks for your simple way of making me understanding well the general concept

This revived my knowledge back in school in few minutes, thank you so much!

Привет из России, я не нашёл разбор «метода бисекции» на русском языке, но вы мне очень помогли, благодаря вам все понял, спасибо большое!

Nice accent, Cool quality capturing, Easy and Direct Explanation.... That's really great!! Thank you

people who have native language (english) can watch it speed2x but ı can't. why god why :D

Can I know why value B is chosen instead of value A and C ?

Sir why we not here consider the value of "a" as a root?

What is the use of f(a) and f(b)???

Is it always the a that changes when negative and b when positive? Or is it because f(a) originally gave negative and f(b) gave positive that decided which value changes? So let me ask you a theoretical question. If f(a) originally gave a positive number and f(b) gave a negative, would it have been switched around? Need some clarification.

Thanx a lot bhayya it is helped me a lot

Thanks a lottttt. Saved my semester. Thanks

Find Bisection, interpolation & RegulaFalsi C codes here : eagletarians.blogspot.com/2018/12/statistical-and-numerical-techniques-c.html

Helpful ! Compared to those others speaking in Hindi

This is so helpful but l still don't understand why b-a should be less than 0.01 I order to conclude the final root. Thanks

Sir, can you show your workings on how to calculate the possible number of iterations to be carried out? That is before you draw the table of values, is it possible to know the number of iterations by using a particular formula to calculate? Need help Sir. Thank you.

Why is the root come from the b ? ....its the rule that is always come from b or anything else

If f(c) was positive in the previous step before the final row, would you use (a) as the answer?

f(3)=-5 f(4)=O f(5)=7 How to choose the interval for this??

Years from now first watch the 3rd row has correction 1.25 - 1 = 0.25 not 0.75 (Check) 6:24 in the video

During class time our Faculty he didn’t mentioned( b-a) if we ignored this column ultimate answer will be same or wrong?

THANKS but i have a suggestion plz don''t skip little things.

When should we stop doing iteration thanks?

Man U r the best ! thank s a lot bro ! tomorrow I have an exam on bisection method and thank to your video I understand all ! good job !

1.25-1=0.75,মানে এইটা পুরাই হাইস্যকর

Why yo did not took interval (0,2)??

Thank you for simplifying this topic for me.🙏🏼

Why you take b-a>0.001? Is it a rules to be following

Can you do a video on Regula Falsi Méthod using tables

I thought the midpoint (c) will be the root not b? So the root must be 1.1523 not 1.1562

why we use interval [1,2] and not [0,2] its also postive and nigative values can u please ansower ?

Ok...thanks for ur video.. but one ques that is b-a

thanks for the lecture, why did we stop when b-a = 0.01

how you get [1,2] as interval?

দাদা খুব ভালো বুঝিয়েছেন ধন্যবাদ।

is there any method to find the number of N before i start this method

Thanks for letting us know how many times, we should iterate

Sir...u will mistake in (b-a)=0.75 is wrong..it is 0.25

I want cosx=xe^x problem by using bisection method

but to use an interval always the function values is +ve and -ve this is not clear tome

Shouldn't the final column be (b-a)/2 ???

I really understood this method now but to give more examples

F(0) was -5 which is less than 0 so the root of the equation can be [0,1]?

your b-a value in your 3rd iteration is incorrect. answer should be .25. Excellent work tho, man. Really enjoyed this.

How to calculate Approximate error In% Plz say

B-A in the third iteration should be 0.25❓❓

Less talking more doing that's how mathematician learn

Why did you choose the value of b and not a to be the approximate root?

b-a

Its very good. The answer is (C), not the "b".

does b value is always be the approximate solution?

How did you know the root is b and its not a or the previous c?

Why we are not take o in interval cz it also given negative value

Speed 1.0 works great for us western students XD....

Is b-a the relative error? Is it same as |Xnew-Xold/Xold| ????

it have made me understand this more clearly thank you

bro how did you know that you will stop at 0.01?

I would like to know why when f(c) is negative, the "a" value will change?

b-a.... i prefer (xnew - xold) /xnew

Why v should Stop at b-a=0.01 value

This was super clear! Thanks!

sir hr sum mey iteration tb tk hi continue rkhni hai until, b-a

Where did you get 0.01?

why it should be b-a

Aneesh ji....In bisection method iteration third b-a should be 0.25 and not 0.75

In the last table... why is it b-a and not a-b rather ?

sir why should we change the b value if the f(c) value is positive why we can not change the value of a

Better than the other videos out there Thanks a lot

sir I try some problems according to your patters but I got (b-a=-0.01) is it correct or not comment plz

Thanks you sir for your easy trick to find out the root of any equation by Bisection method