lol 11 years ago and this is still helping us. Our teacher randomly came up with the assumption that we should be doing statistics because "maths was just simply too easy". So now 1 month before my exam for stats i have to go through the whole thing, Which im almost completed with it. Anyways this was a banger :P
Thank you so much, you just taught me this better in 13 minutes and 57 seconds, than my teachers have in 3 hours ;u;'' you are a life-saver, thanks a bunch ^^ TTuTT;; :'D
So that's how you find outliers, I knew it couldn't just be guessing which one looks a bit off, phew! You saved my grade, my teacher just wouldn't tell me of any formula and said use logic for it all...
Are the outliers really 4 and 26.5 because every time I enter it in my calculator I get 1.5 and 19.5. If that is wrong please someone take the time to explain that to me. Thank you!
Hi, thanks for the uploads! can you confirm whether you made an error when calculating the outliers upper and lower, as i made it out to be lower outlier = Q1 (12) - 1.5 (19-12= 7) so = 1.5 .... upper quartile = Q3 (19) + 1.5 (19-12=7) so = 29.5 Have i done something wrong? please advise :)
Question, what does the left and right skews tell us about data ? Same for if the data is symmetrical ? Also what if the median line is pushed to the right, and the right whisker is also longer ? What if median is pushed right or left but the whiskers are equal in length ? What kind of skews would these be at the point ?
with the correct values for the upper and lower outliers; (29.5 and 1.5) what would the new box and whisker diagram showing the outliers look like? Thank you
Hi,what if the boxes are symmetrical but the whiskers tend to be longer on the right side? Do I say it's positively skewed or symmetrical? Actually, when determining skewness, should we look at the box more or the whiskers? Thanks so much!
I was studying in your site and i would like to know if the box and whisker plots can be drawn in any part of the graph such as at the top or bottom of the graph.
ExamSolutions I love your videos, they have helped me so much. However, I'd like to point out the Upper inner fence, or Second Outlier if you will is also inaccurate. Even if you plugged it in the calculator straight, it's 29.5 not 26.5. I don't think it affected the results, but yeah.
thank you sir for this video..but when I am doing boxplot in spss 26is coming as an outlier....y so?? can you do a video with the same data points in spss...plz sir
The median is calculated by find the middle value. In this case there are two values in the middle, 15 and 17. The median = (15 + 17) / 2 = 16. not 15...
+Jack Kelsey :Are you studying statistics? If you need any help on statistics. just let me know, as i am a statistics tutor, and teach statistics. That is completely free of cost.