Sir apka jitna tarip kru utna kam h sir sir apse ek binti h sir prt ke liye ap apne hisab se question set karke merathan lijye please sir kyoki ap jo merathan lete h usse kuch bahar exam me aata hi nhi h bs value exam me alag rahta baki pattern to apka hi rahta h sir isliye sir apse binti h ki ap guess question ko set karke ek merathan lijye sir apke charno me pranam sir 🙏🙏🙏🙏🙏🙏🙏🙏🙏❤❤❤❤❤🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir mai apki class live nhi dekh Pati hu but Recorded dekhti hu bhut achchha pdate h or math phle se kaphi thik ho gya h or app ke class ko 👍 v kr deti hu
Sir last question ka answer jarur dekhiyega,❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️🇮🇳❤️ Sir es trah ka question me humlog hundreds place se check karte hai, chuki question me divisible bhi karna hai 2 se, esliye humlog ones se check karenge.... Ones place par kewal 2 option hoga (0,2) , ab humko 2 case lena hoga Case 1 Ones place par 2 option hai, Agar humlog ones place par 0 lete hai to, tens place par par 4 option, aur hundred place par 3 option hai, total ... 4*3*1=12 Case 2 Ones place par 2 option hai, agar hum ones place par 2 lete hai, to hundreds par 0 nhi le sakte hai matlab hundreds par 3 option (1,3,5 ) hi hai, aur tens par 3 option, total 3*3*1=9 Eska matlab answer 9+12=21 hoga
सर एक बात कहें आपसे क्या? 🙏🏽 हम आपसे काफी वक्त से जुडे है, आपके समझाने का तरीका काफी सराहनीय हैं, एक हम -सब का विनम्र निवेदन है कि आप न प्रश्नो की संख्या में वृद्धि करेंगे क्या? 30-40 प्रश्नो की श्रृंखला लाऐगे क्या? बहुत ही आभारी रहेगे हम सब आपके 🙏🏽🙏🏽😊😊😊
Step 1: Conditions for divisibility by 2 A number is divisible by 2 if its last digit is even. The even digits available are 0 and 2. So, the last digit must be either 0 or 2. Step 2: Case 1 - Last digit is 0 If the last digit is 0, the first digit can be chosen from {1, 2, 3, 5} (4 choices). The second digit can be chosen from the remaining 3 digits. So, the number of such numbers is: 4 × 3 = 12 4×3=12 Step 3: Case 2 - Last digit is 2 If the last digit is 2, the first digit can be chosen from {1, 3, 5} (3 choices) because 0 cannot be the first digit. The second digit can be chosen from the remaining 3 digits (including 0). So, the number of such numbers is: 3 × 3 = 9 3×3=9 Step 4: Total number of 3-digit numbers divisible by 2 By adding the results from both cases, we get the total number of such 3-digit numbers: 12 + 9 = 21 12+9=21 Thus, there are 21 such 3-digit numbers that can be formed.
sir ek questions hai btadigiye plzzzzz......एक गेंदबाज ने अपनी पिछली 4 पारियों में 42, 34, ,28 और,57 रन दिए हैं। वह अगली पारी में अपना औसत 35 और 40 के बीच रखने के लिए कितने रन दे सकता है।?? Sir isko ho sake to step by step bta digiyega kuki humko smjhe nahi aa raha hai ki isko solve kaise kare plzzzzzzzzzz sir🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏
Sir question no 3 mein percentage increase and percentage savings Karne per answer 20 ho jata hai please sir reply this kyuki isme clear kuch nahi pata chal raha hai 🙏🙏🙏