C++ FOR BEGINNERS (2020) - What is while loop, How to count digits of a number PROGRAMMING TUTORIAL 

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I appreciate you making all of these. I've been learning C# for the last 6 or so months but recently discovered all of my comp sci classes will be using C++ exclusively. You making these videos will have a huge impact on getting up and running for my classes. As I said before, I really appreciate it. Please keep pumping these out!

I wrote in order to include minus numbers too like that: while (number > 0 || number < 0) :) It works:) Thank you for the lessons :) It helps me a lot :) I am still learning:) And I like your videos so much :D

C++ also has abs() which will return the absolute value of a number. You can do number = abs(number) and get the same result.

Before i even start watching the video i give you a like cause i know the video is going to be amazing👏

i have exam soon, i am using your tutorials thanks for your videos this is so helpfull for me , Good luck

For those that want to have greater than 10 Digits, change your data type from int number to long long number. I was able to get 19 digits from this data type.

your explanation made understanding easy ,thanks.

THANK YOU SO MUCH I NEEDED THIS SO BADLY

Yeah we need a video on debugging... and breakpoints

Thank you so much , you help me a lot .💙💙💙

Pozdrav, obzirom da nisam bas za C++ svejedno se da nauciti a ucim vec druge programske jezike pa cu dati sansu da iskusam ovaj kanal. Dobila si novi sub

Yes make a video on debugging... and breakpoints, you're doing well.

Sorry i have a question. What if there is a situation where user enters decimal number? I fried my brain trying to make some kind of a solution but nothing crosses my mind from the stuff we covered until this video. Is solution beyond this level of knowledge? Everything else in this video is very much clear. Thanks.

Yes, I would love to see a video about debugging. But I do feel like the code we wrote at 14:35 was unnecessary and made the code longer, so I just did this while(number>0 || number

So, what happens when user types in 25 or more digit number, what is the solution?

I really just changed While(number>0) To While(number!=0) And worked properly

Isn't it better to declare counter at the beginning and initialize it at the while loop? Is it the same thing?

Thank you very much.

How or could I use this same counter with a randomly generated number up to lets say 10 to tune it into a simple guessing game?

A little different variation int num; int digit = 1; cout > num; if(num < 0) { num = pow(num, 2); num = sqrt(num); } while(num / 10 >= 1){ num/=10; digit++; } cout

I was just wondering if You're actually a computer scientist or a model ;)

Hey I find your programming vedios the most easiest ones, thanks and I really need a mentor like you please be my guardian. I what to learn C++ programming lang.

Hi, why do you use system ("pause>0"); instead of return=0; ? Thanks!

So how we can count more than 10 digits if that is all and int can hold? Unsigned int? Also since a negative number can be divided by 10 couldn’t we simply change the while loop to execute as long as the number is != to 0 as opposed to > 1 instead of taking the absolute value?

16:27 you should write long long instead of int variable

What happens in the even that the user enters a number with a zero in it? for example number 1024?

Dear Saldina, there is also another way to count digits beside 0 -> while(number !=0) { number /=10; counter++; }

a other way of solution is: int number=0; cout > number; std::string s = std::to_string(number); cout

Woudnt it be more correct to state that the counter is really counting how many times the function can perform the operation(the act of dividing by 10), rather than saying that it's grabbing the last digit because it seems like that's what the modulo operation would do

please i did not understand from where did you get that value of 10

Solved the > 10 number length problem by using type long long.

Pozdrav, Zašto uopšte pišete dio u else{o množenju negativnog broja s -1} Je li se mogao while(number0) napisati ? Probao sam i meni lično radi pa ako možete molim Vas objasnite zašto taj korak sa else? Hvala :)

Counter variable and while loop are automatically related?

I think I found an alternative way to use negative numbers without the excess code or logic loops, what I did was for the while loop I put while(number != 0) and then the code, and that seems to work well, but perhaps doesn't work well elsewhere?\

Dear Saldana zero too have value is’t? When entering 0 it should show you it contains one digit is in it? Suppose the user enters other than digit will it convert and tell the digits?

I can do like that: while (number0) :) Thanks Saldina

thanks, mam💕💖

it can also be found using logarithms: floor(log10(number)) +1 except 0 obviously 😜

Help me one project Coil winding turn counting program Aurdiono based

i want to clear something that when i'm intentionally trying to overflow my code i am not getting 10 digits instead my code says contains 9 digits #include using namespace std; int main() { int number; cout > number; if (number == 0) cout

17:00 because you input 28 digit number, which is greater than integer maximum value

Hi I want to ask if is an app C++for iPhone

Break points please 🙏🙏

Idk why but your voice is so therapeutic XD Thanks for teaching this, keep up the videos!!

How we can enter more than 10digit number ??🤔

I didn't need to turn my negative number into a positive one to work. I did this: while (number > 0 || number < 0)

Thanks CodeBeauty🤩 Even as a slow learner,I am able to catch up with ur videos. Hope you can include exercises to try at the end of video, just a suggestion from me hehe.

For the last situation you did not say what the solution was ?

i did exactly as you showed but my program wont compile. i enter nr 12 ,and it takes a LOT of time to get the result ...it "eats" a lot of memory and my laptop fan makes a lot of noise EDIT :: MY MISTAKE :))) i wrote while (nr > 0) { nr == nr / 10; OMGGGGGGGG

#include using namespace std; int main() { int num; int counter = 0; cin >> num; while (num != 0) { num = num / 10; counter++; } cout

Just put the condition while (number!=0) Thanks.

Notice how she wasn't sure if -335 will work after adding abs part of the code and she switched to -236. Foxy Lady! :)

At 14:11 your solution to the negative number problem was inefficient in my opinion. I used an or logic gate in my while loop. Here's my code for the whole process here. *note I used n for number and c for counter. line 1 #include line 2 using namespace std; line 3 int main() line 4 { line 5 int n; line 6 int c = 0; line 7 cout > n; line 9 if (n == 0) line 10 { line 11 cout 0 || n < 0) line 16 { line 17 n /= 10; line 18 c++; line 19 } line 20 } line 21 cout

omg the headlice trying to understand the code 😵🤯

it seems like people lack motivation because as the course goes on the number of views are deceasing hugely .

10

int number; cout > number; if (number == 0) { cout

Comment for Algor

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