Calculating the mean of a histogram 

they still dont :/

When using univariate data, that is separated into equal class widths. It is not necessary to create a frequency density histogram. Yes I know when you do your studies many times teachers will focus on Frequency Density histograms, however, the reason for that is it allows for better comparison to other data sets. This is not what this video aimed at, this I a basic 7th grade Algebra I histogram. I made this video specifically for my students who were prepping for our state exam that could potentially require them to calculate the mean of a univariate data histogram of equal class width. The important part of this video is that my class widths are all equal. If my class widths were not equal then you would be correct that I must label the Vertical axis Frequency Density.

isn't that what he did though?

@Monik yes he did but it took him 9 minutes 3 seconds to explain it

Thanks mate

@@Rowse1994 some of us like having it explained to us

@@Shank5terand some don’t 😂

The answer is dependent on how you determine your class intervals. Here is a site you can look to see that there are three different ways to group your classes and the y-axis is labeled based upon those. newonlinecourses.science.psu.edu/stat414/node/120/

Glad it helped!

The Range is the greatest minus the smallest. The mode is defined as the most frequently occurring value.

Phoebe Cotes You do not label a histogram as frequency density when you have class-widths of equal length. I will relinquish to you the fact that in higher level statistics courses that yes a “true” histogram should technically be the frequency density. However it is not an absolute requirement to do so when the intervals are of equivalent length. So the video and all of its mathematical processes are correct and labeling the y-axis as frequency is not technically wrong. The concept of frequency density is important but as stated in the video this is a basic level problem. So there is no need to talk about density for this level of problem

@@dminger1 But if the class widths are equal lengths then showing it in a histogram is pointless

If the second class has a data range of 45-59, what you do is subtract the two numbers 59-45= 14, however, class sizes must include all applicable numbers in the class so what we do is add 1 to the value so the second class has a class width of 15. Based on your question about size of the actual class the frequency of the individual class is just extra information in the problem intended to confuse you from the question at hand. On the other hand, if you meant that you have a total sample size of 30 data pieces that span from value in 45-59. Then that is something different.

@@dminger1 thanks for the help

Only if you want a density histogram. There three types of histograms. The purpose of a histogram is mainly to show continuous data. The three types are a frequency histogram, a relative frequency histogram, and a density histogram. It depends on how you wish to represent the data.

I don’t plan on it. However, you are sadly mistaken if you think that there is only one type of histogram and no others. Here is some literature to help you with your qualifications. newonlinecourses.science.psu.edu/stat414/node/120/.

Imagine being this ignorant lmao

Here is a link to a better video that has all the times associated with it. Also is more in depth explanation. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE--haVXyCHMSs.html. Thanks for watching

Chris X glad it was helpful. Thanks for watching

Same

Dude he only took 30 seconds just to explain what the mode was, be grateful he even mentioned it.

Yes and no, I know it’s not a common statistical histogram but there are different versions of histograms if you want the real deal histogram video I have one on my channel

So when I said this was a very basic intro video. That’s what I meant. I know that they do not. This is as a basic of a histogram as it gets

I don’t but when I was teaching 6th graders, they needed more explanation as they didn’t have enough life experiences to understand topics. So video May just not be relevant to you. Hope you have a good day

@@dminger1 SHIIIIT mate, now I feel like an arse. Sorry for being a dick. I was angry cause I needed a quick answer, shouldn't have taken it out on you. The explanation was good because I understood it after watching. cheers.

Argeed

Sir, I believe you have misspelled Agreed. Are you proficient in spelling? jk jk lol