Calculation of vector potential for a given magnetic field

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Опубликовано:

8 сен 2024

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Комментарии : 19

@mikefredd3390 6 лет назад

I appreciate that you go through some basic calculations of A. This subject is not treated well in many courses other that noting that A(r) like V(r) exists.

@deepachauhan9365 2 года назад

Good evening sir Thanku sir 😃

@deepanshuchaudhary986 3 года назад

The direction of A is always supposed to be in the direction of current. But in the 2nd example, direction of A is in negative z axes. Also, at s=infinity, A was assumed to be zero in the 2nd example but according to the equation, A depends on -ln(s) so how does A tend to zero when s tends to infinity?? Please explain

@vishnusankar5335 5 лет назад

In example 2 you have taken the limits of the integral as infinity and s, but you have written only ln(s), where did ln(infinity) go? The assumption that A(infinity)=0 is not obeyed when s' is infinity. Please correct me if I am wrong.

@debanjan7883 5 лет назад

@dakshchhabra5975 4 года назад

@@debanjan7883 We have to consider only dependence of A on s

@diegonavia1404 4 года назад

I have this same question can someone please explain

@dakshchhabra5975 4 года назад

@@diegonavia1404 We want to se variation of A with respect to distance s. We use Vector potential to calculate magnetic field. Since magnetic field equals curl of vector potential and culr of constant is zero. You can ignore that infinity.

@diegonavia1404 4 года назад

@@dakshchhabra5975 damn, I see now. thank you

@pandav01 3 года назад

Very nice lecure Sir

@kandiecarren7157 3 года назад

Appreciate

@ibreakkidslegs 6 месяцев назад

In the first example, the integral of A_phi comes out of the line integral because A_phi is independent of phi, NOT because A only points in the phi direction.