Calculus - The quotient rule for derivatives 

thats good you said that this site should help alot he doesn't mess any steps ( mathtutordvd) he teaches everything

I agree. Sometimes it's the factoring that trips me up.

same 👍👍

Did you passed?

sounds familiar.😂

negative x negative = positive

No, the terms are preceeded by a minus sign. So that when you multiply 1x3x^2= 3x^2, -x^2* 3x^2 = -3x^4 , you are subtracting thus negating all the signs of each term inside the grouping symbol; -(3x^2-3x^4 )

He just simply factor x^2e^x-2xe^x all over x^4 ---> x(xe^x-2e^x)all over x^4 ---> then cancel x at the numerator and x^4 becomes x^3

@@HannagraceHonrade ahh he factor it first, then cancelled for both num and deno. that's why deno left with x^3. How can i forget that hahaha thanks bro

We would have to factor before we worry about canceling. Thin the first example we could only factor out an x. Then we could cancel that x with one from the x^4. This would turn the expression into ( x e^x - 2 e^x ) / x^3 Let me know if that helps out. :^D

He took an x outside from the numerator so it becomes: x(xe^x - e^x 2) / x^4 Now you can divide the outside x on the numerator by one x on the denominator, i.e x/x^4 which will make the denominator x^3 Hope that helps and correct me if I'm wrong :)

At first i also confused while watching above video at 4:55 ....... than i scroll down to find answer i found that many other have confused too so i looked up again very closely and Wallah find the logic he get the common x(xe^x-2e^x)/x^4 and than cancelled it with single x in denominator and get xe^x-2e^x/x^3 ;D simple :D

Kavya Saxena by arranging it. -2x^4 + 3x^4 = x^4 and copy the rest to highest exponent to low.

If you reverse distribution X^2e^x - e^x2X = e^x(X^2 - 2X). You can’t cancel e^x with nothing.

You mean finding a second derivative and having to use the quotient rule? Let me know if this is what you have in mind, I can cook something up. :^D

Nick Y bit slow and not ideal with trig

You might be able to simplify it further, but careful not to distribute. When looking for things to cancel out we want to see the factors. This means it would be a good idea to factor the x^3 + 1 piece using the sum of cubes formula. Then we could also work on factoring the top. From here we could check for common factors to cancel out. You should get: x(x-2) / (x^2 - x + 1)^2

​@@MySecretMathTutor Ahhh okay, thanks I was really confused but I see what you're saying now!

Works every time. :^D

Jocell Rosas i think you are wrong. (x^3 + 1)^2 should multiplied to itself. so the answer would be x^6 + 2x^3 + 1

Noice!!

I masturbate on my body pillow so much that it stands up now.

paul shelley same. i was confused with that too.

Yess it was a simple mistake Made unintentionally

Jim Halpert, is that you?

I'll never tell. :^D