Can You Pass Harvard Entrance Exam? Exam Tips and Tricks. 8^x +4^x =36 

Once you spot the solution y=3 to the cubic y³+y²=36 there's no need to look any further. This is because y=2ˣ>0 and for y>0 y³+y² is strictly increasing, so only a single root exists.

8^x+4^x=36 2^3x+2^2x=2^5+2^2 3x+2x=7 5x=7 X=7/5

X=log3base2 is the answer ,solved in mind

You miss the power. 8^x does not equal 8x.

If Y=3, then from eqn 1 Y+X=6 X= 6-Y X=6-3=3 XY=36? ANS is wrong and it has no solution.

I use Brain. He is trying to explain every step. YOU SHOULD THANK HIM.

Just a simple question. Why make it too complicated? 8^x + 4^x = 36 2^(x+3) + 2^(x+2) = 36 (2^3 + 2^2) (2^x)= 36 2^x = 36/12 2^x = 3 x = log3/log2

These video makers are addicted to the words Harward, Einstein ,Gauss, Ramanujam,etc

×=1

open ai found the solution x = (log 3)/(log 2). It told me there are no other real solutions. I said about what about complex ones. It said there are an infinity of them "due to the periodic nature of the complex logarithm" !!! I won't try to put it here as I haven't found a way to clip text from open ai.

very simple arithmetic.

Is synthetic division still valid? I'm old school.

3:43 i dont understand how it remain one ( y - 3 )

😅😅 3:33 3:34

Use Chat GPT to solve

NOTE. Given equation has complex roots too.

Seriously long winded method! X=log 3, where log is to the base 2.

x=1.585

Stop the BS. Harvard does not have a specific entrance examination. Like all universities they work off SAT scores.

X=3

Sir y we can't write (-36) as (2+34) or(4+32)&etc?

Why it was difficult method? 😱😱😱

Nice work!

8x+4x=36 12x/12=36/12 x=3 checking. 8(3)+4(3)=36 24+12=36 😂

Aehx....! Yeas ! Proper English please.......

your solution is wrong.