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Can you solve the fortress riddle? - Henri Picciotto 

TED-Ed
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Bad news: your worst enemies are at the gate. Your fledgling kingdom guards the world’s only herd of tiny dino creatures. To you, they’re sacred. To everyone else, they’re food. The three closest nation-states have teamed up to smash open your walls and devour the herd. Can you build fortifications for your kingdom before the siege weapons arrive? Henri Picciotto shows how.
Lesson by Henri Picciotto, directed by Igor Coric, Artrake Studio.
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23 сен 2024

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Комментарии : 1,3 тыс.   
@TEDEd
@TEDEd 2 года назад
Keep honing your riddle-solving skills by visiting brilliant.org/TedEd and check out Brilliant’s 60+ courses in math, logic, science, and computer science. They feature storytelling, code-writing, interactive challenges, and plenty of puzzles for you to solve. And as an added bonus, the first 833 of you to use that link will receive 20% off the annual premium subscription fee.
@bosmoth
@bosmoth 2 года назад
Isn't this the same as the mcnugget problem?
@V3Aura
@V3Aura 2 года назад
@@bosmoth yeah, I think vsauce made a video about it
@MJ-2797
@MJ-2797 2 года назад
Word problem not riddle. this clickbait disrespects mathematicians and writers.
@Amitmalaghan
@Amitmalaghan 2 года назад
A
@V3Aura
@V3Aura 2 года назад
@@Amitmalaghan thank you sir, very inspiring
@harrysboylan
@harrysboylan 2 года назад
Easy solve: Go up to the approaching army and say that at least one of them has green eyes. This will buy you enough time to build your defenses up as they wait days to determine who has green eyes
@cedriclee8724
@cedriclee8724 2 года назад
H a
@EvTheFlickFan
@EvTheFlickFan 2 года назад
Nice
@alfi2531
@alfi2531 2 года назад
Smort
@erikaz1590
@erikaz1590 2 года назад
Alternate answer: go to one army and ask "If I asked 'is the army to your right led by Arr', would you answer 'ozo'?" The armies will be so confused by the question, you'd have time to build two walls.
@maapauu4282
@maapauu4282 2 года назад
I would tell the dino that they have green eyes
@rextanglr4056
@rextanglr4056 2 года назад
The moment I heard "6 9 20" I immediately thought "43 CHICKEN MCNUGGETS" and realized why the enemies are all based on fast food chains.
@jonramos2676
@jonramos2676 2 года назад
True
@maxwang2562
@maxwang2562 2 года назад
smart
@roideschiffres6760
@roideschiffres6760 2 года назад
I thought the same ting.
@manavshah8335
@manavshah8335 2 года назад
@@roideschiffres6760 ting ting dong in hole, triplets came out, all abort
@jartistsimpression2291
@jartistsimpression2291 2 года назад
Please explain?
@corncake4677
@corncake4677 2 года назад
60% of ted ed riddles can be summed up as “hope you know your prime numbers nerd”
@itsphoenixingtime
@itsphoenixingtime 2 года назад
I mean, they ARE pretty much what mathematicians obsess about.
@d1v94
@d1v94 2 года назад
@@itsphoenixingtime true.... but then letters came along and made it worse( or better)!!
@imperator9343
@imperator9343 2 года назад
"riddles"
@Noname-67
@Noname-67 2 года назад
@@itsphoenixingtime only number theorists
@ganbarimasu9446
@ganbarimasu9446 2 года назад
And the rest is about repeating odd and even numbers...
@rasern
@rasern 2 года назад
When I saw the siege weapons, I realized this was the Chicken McNuggets problem. Thank you for animating it. That solution was actually quite interesting. Used guess and check to get the answer, but this method is much more elegant.
@buildertherobloxian4731
@buildertherobloxian4731 5 дней назад
The Chicken McNuggets Problem? What's that?
@oomfie_rhine
@oomfie_rhine 2 года назад
"I fart in your general direction." That's the single most hilarious quote I've ever seen in a TED-Ed video
@antonioscendrategattico2302
@antonioscendrategattico2302 5 месяцев назад
It is a Monty Python and the Holy Grail reference.
@Nuoska
@Nuoska 2 года назад
Here's how I solved it: The greatest common divisor of 6 and 9 is 3, and the largest safe wall of size 3n is 3. This means that every wall of size 3n that is larger than 3 can be destroyed. Therefore, a bigger wall would have to be 3n+1 or 3n+2. The siege weapons can only reach 3n+2 numbers by using the 20 once or 3n+1 times, and since they can reach every multiple of 3 larger than 3, every 3n+2 wall larger than 20+3 can be destroyed. Similarly they can only reach 3n+1 numbers by using the 20 twice or 3n+2 times, so every 3n+1 wall larger than 20+20+3 can be destroyed. 43 is safe and no larger safe walls can exist, so 43 must be the answer.
@vishakh6929
@vishakh6929 2 года назад
same here
@rozafisheikh7968
@rozafisheikh7968 2 года назад
Damn you lot smart. I just didn't want the cute little dinosaurs to die XD
@fejfo6559
@fejfo6559 2 года назад
This is essentially the same approach as in the video but you only used 3 columns instead of 6
@Serjgap
@Serjgap 2 года назад
But you can not make a 1000 length wall out of blocks of length 43. 1000 / 43 = 23,2558... The closest you can get is 43x23 = 989. Stating that "you can plug gaps at the ends with loose boulders" without stating max allowed length of the gaps just makes the riddle bad
@reevus01
@reevus01 2 года назад
Ez , get more wall fabricator .
@Hazy_Heart
@Hazy_Heart 2 года назад
For the first time watching one of these riddle videos I actually decided to try and solve it and got the answer by 1. Listing every number up to 60 2. Removing every multiple of 3 except 3 because they can be made with combinations of 6's and 9's 3. Repeating step 2 but starting from 20 then removing 26, 29, 32, 35 etc. 4. Notice a pattern and realise that I don't need to go beyond 60 5. Highest number left is 43! It's not the most elegant solution but that doesn't mean I can't be proud of myself.
@kfirnachum4928
@kfirnachum4928 2 года назад
They can get 6.01×10^52
@redthefoxisWritingUpAStorm
@redthefoxisWritingUpAStorm 2 года назад
Impressive
@ie8118
@ie8118 2 года назад
What a coincidence I also listed every number up to 60 probably cause none in 50-60 range work
@neofitoff
@neofitoff 2 года назад
43 factorial is a pretty large number indeed
@Misteribel
@Misteribel 4 месяца назад
You basically used the sieve of Eratosthenes, tailored to your situation. I find it very elegant. 😊
@sirreginaldfishingtonxvii6149
Alternatively, point the wall fabricator at your enemies and tell it to produce a 100 000 m long wall. Due to the machine producing any size of wall at equal speed, this huge wall will be shot out of the machine at outstanding speed, crushing your opponents. Unless it, uh, requires raw materials or something.
@anbubu
@anbubu 7 месяцев назад
If the wall fabricator's input unit is in inches, then the required amount of inches to be inputted for the fabricator to be fabricating so many inches of wall at once that it would be travelling at 99% the speed of light, then you would need to input about 1.43 times 10^10 inches
@SuperDestroyerFox
@SuperDestroyerFox 3 месяца назад
@@anbubuthe input is in meters evidenced by the labels on the siege weapons
@buildertherobloxian4731
@buildertherobloxian4731 5 дней назад
Did you… not see the Big Funnel of Rocks on top of the Fabricator?
@TheBlueArmageddon
@TheBlueArmageddon 2 года назад
0:04 This video had the best philosophical quote yet
@-nightlyfireflies-9561
@-nightlyfireflies-9561 2 года назад
Ah yes, "i fart in your general direction" the most philosophical quote ever
@Jake28
@Jake28 7 месяцев назад
@@-nightlyfireflies-9561 philosophy not psychology
@-nightlyfireflies-9561
@-nightlyfireflies-9561 7 месяцев назад
@@Jake28 thanks didn't even notice till you pointed it out lol
@songhengsoeur8459
@songhengsoeur8459 Месяц назад
"I fart in your general direction -sersues of Athens
@JaybeePenaflor
@JaybeePenaflor 2 года назад
Love it when TED-Ed makes these puzzle videos! Most of the time, there's a mathematical concept that's hidden in these puzzles. So excited to watch!
@EnriqueLaberintico
@EnriqueLaberintico 2 года назад
Funnily enough, this time it's the Chicken McNugget Theorem.
@almophant1673
@almophant1673 2 года назад
@@EnriqueLaberintico Was so funny seeing all the Easter eggs about the chicken McNugget Theorem. With all the other armies being inspired by fast food chains and the unhappy meal at the end.
@imperator9343
@imperator9343 2 года назад
You have it backwards. Most of the time, it is a simple mathematical mechanism that they've dressed up as a riddle. Impressive to laypeople, kinda boring and silly to anyone that has passed college freshman level math.
@JaybeePenaflor
@JaybeePenaflor 2 года назад
@@imperator9343 Yes, I agree.
@commander8625
@commander8625 2 года назад
@@imperator9343 it annoys me because it really isn't isn't riddle. Don't get me wrong, I like the math and all, but I came to try to solve a puzzle, not to be told about some mathematical equation or concept that hasn't been used in 1000 years.
@KettouRyuujin
@KettouRyuujin 2 года назад
I love how it just opens with “BAD NEWS”
@clush913
@clush913 4 месяца назад
When you forgot to press save before you close your game BAD NEWS
@pmathewizard
@pmathewizard 2 года назад
Finally I have solved my ever first Ted-Ed Riddle.
@Purple_Mesh
@Purple_Mesh 2 года назад
I have solved my first one too! Inspired
@kohikappu
@kohikappu 2 года назад
Nice, I failed for the first time, I went for 34 and didn't notice it should be the highest.
@HiImKangarou
@HiImKangarou 2 года назад
I got it via minor brute force and guessing because 6 and 9 are both divisible by 3. You're screwed if one siege designer misheard and made one 5 or 7 wide, though.
@frozenfeet4534
@frozenfeet4534 Год назад
nah, they use fabricators too, nothing to mishear
@therealelement75
@therealelement75 9 месяцев назад
boss: 5 wide is useless you're fired them after seeing wall of 43 being 20 + 5 + 3(6): nvm you're unfired 5 is useful
@AffectionateGraphingCalc-bq6cb
@AffectionateGraphingCalc-bq6cb 4 месяца назад
😂
@newpgaston6891
@newpgaston6891 2 года назад
Found it even faster, using a different method! Any multiple of 3 can be divided by a combination of 6s and 9s, except 3. If a number isn't divisible by 3, then it WILL become divisible by 3 if you remove 20 or 40 from it. (because it changes the rest, and changing it either once or twice always work). This means that any number higher than 40 is either: 1) Divisible by 3 2) Will be divisible by 3 if you remove 20 3) Will be divisible by 3 if you remove 20 twice (so, 40) And if the number is divisible by 3 and it's above 3, it's no good. (the added 20 don't matter because one of the wallbreakers can take the 20s down). So if you remove 20 or 40 from the number, it can't ever give you a number divisible by 3, that is above 3. But as you're looking for the highest possible solution, then it has to be the solution where the number you get from removing 20 or 40 gives you EXACTLY 3; Between 23 and 43, you obviously pick 43, and that's the highest possible solution! Anything above that will either divide by 3, or divide by 3 if you remove 20 or 40 from it (and if it divides by 3, it means you can get it with the 6s and 9s, no matter what it is - as long as it's not 3, but we already picked the solution that gives you 3, i.e. 43).
@existentialchaos8
@existentialchaos8 2 года назад
That's what I did!
@lubu682
@lubu682 2 года назад
**has a mental breakdown**
@hash5996
@hash5996 2 года назад
that is a great solution!
@dhien2103
@dhien2103 2 года назад
Geines
@shreyanray7624
@shreyanray7624 2 года назад
Same method, imo their method is not the best or even efficient as it involves some hit and trial
@pvzprime187
@pvzprime187 2 года назад
Usually I have no idea how to solve these and just watch the solutions, but for the first time, I actually managed to figure it out on my own!
@altersami9660
@altersami9660 2 года назад
What approach did you use?
@Lemony-lemongrass-LEMOO
@Lemony-lemongrass-LEMOO 2 года назад
I..... Uhh... Congratulations
@aarongrooves
@aarongrooves 2 года назад
43? Okay, time to check my answer... Yay! I got it :) I realized that 3 is the greatest common factor between 6 and 9, so all multiples of 3 will be eliminated from 6 onward. If you add 20 to this, then you end up at 26, which eliminates all multiples of 3 minus 1 from 26 onward. Once you get to 46, then you eliminate all multiples of 3 plus 1. At this point, you can create any number. The highest number that wasn't eliminated is multiples of 3 plus 1, but less than 46. Which is 43. Fun math problem!
@adrianwoodruff1885
@adrianwoodruff1885 2 года назад
This is how I solved it.
@aarongrooves
@aarongrooves 2 года назад
@@adrianwoodruff1885 Great minds think alike!
@devangsingla5411
@devangsingla5411 2 года назад
But 43 is 4×6+9+10
@pietroparini2008
@pietroparini2008 2 года назад
I also used this approach.
@VNYoshi
@VNYoshi 2 года назад
Basically Chinese Remainder Theorem.
@joshuatinyforest1204
@joshuatinyforest1204 2 года назад
In rule 2, it states that the opening is one kilometer wide, & that loose boulders can plug up any gaps. So, wouldn't it be easier to use a prime number, say 997, & plug up the 3 meters of holes? Yes, you could use several boulders, but that seems impractical.
@raphaellaalexander8853
@raphaellaalexander8853 2 года назад
While 997 is prime, you can still make that number from two 20s, one 9, and 158 6s, since it falls in the first column in the chart that they made to solve the problem
@joshuatinyforest1204
@joshuatinyforest1204 2 года назад
@@raphaellaalexander8853 Ah okay, I see where I went wrong. Thank you.
@aadityamohta6966
@aadityamohta6966 2 года назад
I had a similar idea and then realsied it was wrong lol
@TheWatcher328
@TheWatcher328 2 года назад
@@raphaellaalexander8853 How about 998?
@IH8Reflorished
@IH8Reflorished 2 года назад
@@TheWatcher328 that’s a mutible of 2
@flawlessmsc
@flawlessmsc 2 года назад
Hope can update this series more often. One of the very few on the entire internet that can provide quality riddles
@tonito5588
@tonito5588 2 года назад
Got it with a different method after a few takeaways. - Realized you can get all multiples of 3 (except for 3 itself) with 6 and 9 alone. - If you can prove that you can find all lowest multiples of three such that 3A=20B+x for every integer x from [1,20], you could basically make any number greater than the greatest of those multiples (ex. for x=4 you have 3*8=20*1+4). This works since if we have a representation like this for each number from 1-20, we can just add multiples of 20 to one of these to get any other natural number greater than these representations we find. Note that A and B must be natural numbers. - It turns out that you can find those lowest multiples of three in the first 20 multiples. The greatest of these low multiples is 63 (for x=3 we have 3*21=20*3+3). - Since 63 is the lowest number we can find for a representation of x=3, there must be no representation for 43 (since it is 20*2+3) or 23 (since it is 20*1+3). Since 63 is the greatest among these "low" multiple representations, 43 must be the greatest number without a representation made up from 6,9,20. How did you all do it?
@Sargas-wielder
@Sargas-wielder 2 года назад
I had a similar sort of elimination method: With 6 and 9 you can make any multiple of 3 besides 3 itself, and only multiples of 3 with those 2 numbers 20 is 1 less than a multiple of three so, above 20, you can add 6s and 9s to get 1 less than any multiple of 3 besides 23 40 is 2 less than a multiple of 3, so similar to the last step, beyond 40, you can add 6s and 9s to get 2 less than any multiple of 3 besides 43, effectively eliminating all numbers past 43 since you've already eliminated multiples of 3, one less than multiples of 3, and 2 less than multiples of 3
@randompastahandle
@randompastahandle 2 года назад
That is what I did also.
@invisiblejong
@invisiblejong 2 года назад
same, i also used this method, so I was fairly surprised seeing prime number is used
@jezer8325
@jezer8325 2 года назад
Yess, I did it exactly the way you did
@888SpinR
@888SpinR 2 года назад
The chicken Mcnugget problem! I remember seeing it on Numberphile what feels like a decade ago.
@aldar8240
@aldar8240 Год назад
given there's no max limit, and it doesn't matter how big the wall is, just make the number several quadrillion or so. I kinda doubt hundreds of siege weapons are sufficient for that.
@dennisevanko6152
@dennisevanko6152 Год назад
Oh yeah that’s right… Wait then how will you get the resources for that big of a number?
@aldar8240
@aldar8240 Год назад
@@dennisevanko6152 the fabricator isn't stated to have any resource requirements, and it's already an arbitrary magic device with unclear rules, so it can be assumed it just handles that somehow
@ChillaxeMake
@ChillaxeMake Месяц назад
The wall is 1km large. It's assumed that the armies have infinite of each weapon.
@budgie3666
@budgie3666 2 года назад
0:20 is that mcdonalds burger king and wendys!
@killdyouback
@killdyouback 2 года назад
My solve was a little different. The first thing I realized was that with 6 and 9, you could combine them to make any multiple of 3 above 6 (6+6=12, 6+9=15, etc.). Then using the 20, you would be able to offset it down one number, so multiples of 3, minus 1 (20+9= 30-1). So offsetting it a second time, with 40, would remove every potential number. So the highest available number would be a number less than 46, that is offset from a multiple of 3 by -2, 45 - 2 = 43. Not the solution they hit on, but I'm proud of it.
@SuperKyba
@SuperKyba 2 года назад
I may not be able to solve the riddle of the wall, but I can solve the riddle of the kingdoms: Royalburg : Burger King Circuslandia: McDonald's Redheadonia: Wendy's And I feel that is a real achievement
@frozen_spider
@frozen_spider 2 года назад
As someone from a country not having any of these - thanks! I didn't know about Wendy's at all.
@sharonannco8713
@sharonannco8713 2 года назад
You forgot about jurassic bite
@samudralaanu3429
@samudralaanu3429 Год назад
Dunno, don' care
@ShivaharikumarB
@ShivaharikumarB 2 года назад
0:25 Mc Donalds , Burger king, Wendy's
@kiti_cat524
@kiti_cat524 Месяц назад
unhappy meals
@Mr.chriscroft
@Mr.chriscroft 20 дней назад
That’s such a creative way to think about this
@TheGregamonster
@TheGregamonster 2 года назад
Teded: Can you solve the riddle? Me: Can you ask me a riddle? Teded: Yes. Me: An actual riddle, not a convoluted math problem? Teded: Yes . . . . . . .. . . .. Me: Then I'll give it a shot. Teded: It's math. Me: For the love.
@desrenaud100
@desrenaud100 2 года назад
Thank you! Really glad I'm not the only one to feel this way. Everytime a new one drops, I keep hoping maybe this time it'll be an actual logic puzzle like the pirate riddle, or the medieval tournament or green eyed islanders, and every damn time it's just some long, convoluted math problem.
@KERES_Makani_.
@KERES_Makani_. 2 года назад
Now this was creative. Hats off to the people who can come up with such unique logic problems.
@darthgumby2406
@darthgumby2406 2 года назад
They don't make the problems. they find an obscure mathematical solution someone made up at some point in history and create a silly scenario that would use that solution.
@HunterOfWumpus
@HunterOfWumpus 2 года назад
This is a rip off of the “what is the largest number of chicken nuggets you can’t order from McDonald’s”
@lambadajewo.4143
@lambadajewo.4143 2 года назад
Step one: make sure that the invaders have green eyes. Step two: tell them to leave
@Dexaan
@Dexaan 2 года назад
Ulu
@kishorikumari9014
@kishorikumari9014 2 года назад
an explaination would be helpful
@lambadajewo.4143
@lambadajewo.4143 2 года назад
@@kishorikumari9014 that is a running joke on the channel, ever since the green eye prisoners dillema video was released!
@lambadajewo.4143
@lambadajewo.4143 2 года назад
@@Dexaan ozo!
@pageturner2958
@pageturner2958 2 года назад
Glad this joke is being kept alive
@123idk
@123idk 6 месяцев назад
Just do 1,000,000,000 because they only have hundreds of weapons
@survivordave
@survivordave 4 месяца назад
That's why the opening is 1 kilometer. You can be short by a bit and fill in the ends with boulders but you can't go over 1,000 m
@123idk
@123idk 4 месяца назад
Oh
@CarthagoMike
@CarthagoMike 2 года назад
I really like the aesthetic theme the graphics of this video take.
@8248m
@8248m 2 года назад
I actually solved this one pretty quickly thanks to the fact that I've seen it before in a different video and remembered the answer. I'm gonna try and use this tactic more in the future.
@vari1535
@vari1535 2 года назад
Damn, the quote at the beginning was especially inspiring this time: "I fart in your general direction."
@Vistresian1941
@Vistresian1941 2 года назад
If the dinos are sought after as a food source, is there something special about the food source or are the invading forces starving? The latter seems more likely and you could simply create rows of walls and wait until they go hungry. The walls would also have to either be fabricated "into place" from the side of the machine, or physically moved into place. If it's the latter, the invaders could just move the walls. But all of that ignores that the camped forces could attack the engineers in the video's scenario or mine through scout parties in the night. (And that the machine is apparently able to fabricate entire walls in equivalent degrees of time regardless of the size)
@baconlettucepotato69
@baconlettucepotato69 2 года назад
oh my god this is the mcnugget problem disguised as a ted-ed riddle
@showmikakand7694
@showmikakand7694 2 года назад
-can you solve this riddle ? -yeah but that's gonna take forever and also i would've missed this awesome video
@nikhilgarg9618
@nikhilgarg9618 Год назад
The kingdom: Does not want dinos to become food. Also the same kingdom: Names itself jurassic bite.
@ireneboyle4261
@ireneboyle4261 2 года назад
✨TInY dInO cReAtUrEs✨
@SonicLoverDS
@SonicLoverDS 2 года назад
I used the divisible-by-three insight some other commentors mentioned, knowing that only 20's could change the divisibility by three. Knowing that it would take up to two 20's to make the number easily divisible by three, I started with 39, the biggest number you couldn't fit two 20's into, and counted backwards from there until I hit a number that couldn't be made any other way. Thus, I got the answer 37. ...apparently I overlooked the fact that the number 3 itself couldn't be made, only greater multiples thereof.
@PragmaticAntithesis
@PragmaticAntithesis 2 года назад
I made the same mistake.
@adarshmohapatra5058
@adarshmohapatra5058 2 года назад
Same dude. And then the animation at 2:37 showing a lot of 37's made me think, "aha" I've hit the right answer.
@cloudy.matters
@cloudy.matters 2 года назад
Ted: Can you solve the fortress riddle? Me: *No.*
@danielrhouck
@danielrhouck 2 года назад
1:58 “[…] the siege weapons, which your enemies have hundreds of” So not thousands. Anything that’s 35,000 or longer is safe.
@hkayakh
@hkayakh 2 года назад
Now I remember. Numberphile made a video about this with McDonald’s nuggets
@NumbToons
@NumbToons Год назад
I tried with other numbers along 6, and it works like magic.
@Anove.
@Anove. 2 года назад
That feeling of superiority when you recognize the TedEd quote.
@erickpoorbaugh6728
@erickpoorbaugh6728 2 года назад
I used a different method. 6 and 9 are both multiples of 3, so the 20s have to be used to make up for any remainder when divided by 3, so if you let them use three or more 20s, they can replace three of the 20s with 6s and 9s to get more options, but if you keep it to no more than two 20s, they don't have this option. Now if you divide 6 and 9 by 3, you get 2 and 3, which together can cover any number larger than 1, since for even numbers you just use 2s, and for odd numbers you use 2s to get to the even number below your target and then replace the the last 2 with a 3. Thus, the only multiple of 3 that 6 and 9 can't cover is 3 (1x3). Add the two 20s (that are the most 20s you can use without letting them start from a lower number of 20s) and you get 43.
@fabriziobrown4454
@fabriziobrown4454 2 года назад
0:07 I see...meme potential
@penguinchess
@penguinchess 2 года назад
Ted Ed: Can you solve this riddle? Me: no also me: *clicks video*
@huhneat1076
@huhneat1076 2 года назад
I love how this riddle was inspired by the "how many chicken mcnuggets can't you get?" problem, and everything got burger-themed.
@matesafranka6110
@matesafranka6110 2 года назад
Appreciate that the wallbuster sizes (6/9/20) are perfectly matched to chicken nugget serving sizes
@victoriaperalta6595
@victoriaperalta6595 11 месяцев назад
5:00 and a herd that wont become *unhappy meals*
@emeraldtop5662
@emeraldtop5662 2 года назад
There are so many people referencing old riddles and I love it
@yosheryoshi6170
@yosheryoshi6170 Год назад
Love that you guys made a Monty python and the holy grail reference
@ajbXYZcool
@ajbXYZcool 2 года назад
What I'm not clear on is the underlying principle for solving for prime numbers using the chart. While eliminating the factors of 2,3,5, and 7 are good through 120, you'd need to also run that elimination for the higher primes to eliminate numbers like 187, which is 11 * 17. Unless it's all diagonals all the way down, which would be harder as you have to start skipping lines.
@Lance0
@Lance0 2 года назад
The nice thing about 6 columns is that all primes except for 2 and 3 are actually of the form 6n+1 or 6n-1. This does in fact make it diagonals all the way down. And I mean ALL the way down. Every single one of them. Yes the slopes would be much steeper but they're still straight lines.
@JonMurray
@JonMurray Год назад
1:06 urgh, already bored. Weaponise your dinos, murder your enemies in their beds, drink from their skulls.
@docfox4353
@docfox4353 2 года назад
While I didn’t get the chicken nugget reference, I did love the Monty Python reference. So here’s an alternative solution, Fetchez La Vache, and if that doesn’t work, manure.
@anonymous93155
@anonymous93155 2 года назад
When you are not able to solve any Ted ed riddle but then also watch every Ted ed riddle video.
@伊紹菲
@伊紹菲 2 года назад
I did this in a fairly roundabout way- first you figure out the smallest combos of 6s and 9s to get to various numbers in the 1s spot. The largest number combo of 6s and 9s is 33 to get a 3 in the 1’s spot, so it would be advantageous then, to have a 3 as the last number, since it’d take up more of the entire number to get it to a multiple of 10, would then be divided by 20s, or an additional 30 if it’s an odd number of 10s. With all that in mind, only 43 would work, as 53 gives you a 20, 63 a 30, and literally everything else can be solved by all 20s or a bunch of 20s + 30. So it was indeed 43.
@alex.g7317
@alex.g7317 2 года назад
2:10 infinite in size obviously
@TheWorldsLargestOven
@TheWorldsLargestOven 11 месяцев назад
There's a time limit
@hatimbharmal8537
@hatimbharmal8537 10 месяцев назад
​@@TheWorldsLargestOven1:43
@Wezryx
@Wezryx 8 месяцев назад
I like your style better than my answer of a billion kilometers.
@Wezryx
@Wezryx 8 месяцев назад
But they will mention that safe weapons and there will just be more wall materialized Infinitely instantaneously
@Minclnhat
@Minclnhat 2 года назад
Truly one of my most inspirational quote ever, "i fart in your general direction"
@Ari_Tree
@Ari_Tree 2 года назад
lol there's an animation error at 4:54 where it makes the same wall twice
@jasons408
@jasons408 2 года назад
my favourite videos here please keep churning these riddles up :p
@yakoubborgi3165
@yakoubborgi3165 2 года назад
Love ted ed riddles, because they feel real and honest, the text holds all the information you need. But I wish they werent mainly mathematically driven
@ayaanamin3339
@ayaanamin3339 2 года назад
The sun shines when Ted-ed makes riddles
@ie8118
@ie8118 2 года назад
My Feedback: So I did this by listing numbers up and basically through manual testing them all to see if they could be sieged. The problem is I didn't clearly get that you were going to make 1 wall out of segments of the same length and the point was to use the longest segment length possible in order to minimize the wall making time/number of segment used. I thought that you could only do 1 print total and that was going to be the whole wall, because it talked about the machine taking the same amount of time to print any length. I was just under the impression you only had time to do 1 print before the enemies got here, totally forgot about what it said at the start about how it can make segments of a specific whole number length you set. I think the main thing that would help is that instead of the question at 2:00 being "What wall length will save your kingdom?" say "what wall segment length" instead. I have a suspicion this is the main thing that confused me. Also, at 1:54 when it shows the segment, it could show it as a part of many other segments of similar size to emphasize you want to figure out the segment length not the whole wall length. (I know the voice says segment but I must have missed that). The clock being shown to take a full 12 hour cycle to print 1 segment also might have been misleading, not by itself but in combination with the other things like the question wording. The sentence "Adjacent wall segments reinforce each other if struck simultaneously" is just confusing. It basically just means "A siege weapon cannot take down multiple segments at once- only 1 segment at a time." and I think this would be much clearer.
@ronaldiplodicus
@ronaldiplodicus 2 года назад
It does say that the final wall will be 1km wide
@ie8118
@ie8118 2 года назад
@@ronaldiplodicus Yeah if it said it would be exactly 1km wide then I'd know the answer was the segment size. But since it said at the countdown that it doesn't have to be exactly 1km because you can fill the ends with rocks, I was still able to keep the wrong impression that the answer is the total wall length
@smnio5619
@smnio5619 5 месяцев назад
Easier solution: print over 15,000 units of wall
@cheryl9809
@cheryl9809 2 года назад
I can see this as an actual math examination question, not too hard but still challenging
@jayanspaliwal5907
@jayanspaliwal5907 2 года назад
' A herd that won't become unhappy meals ' 😂😂😂😂😂
@zacklee9260
@zacklee9260 2 года назад
This is by far the best quote we get at the beginning of any TED-Ed videos.
@jchaux1
@jchaux1 Год назад
Well, if the riddle says that you can make any length wall in the same amount of time, you could literally make a 10000000000000000 meter wall and they probably wouldn't have enough seige weapons to destroy all that😂😂😂
@nolivesmatter.
@nolivesmatter. Год назад
1:01 look at those nugs
@andersontruong3298
@andersontruong3298 5 месяцев назад
0:08 this part literally said BAD NEWS
@shinyagumon7015
@shinyagumon7015 2 года назад
I love that you decided to just throw in parodies of fast food chains into this riddle for no reason.
@JoeThomas-lu6fy
@JoeThomas-lu6fy 2 года назад
The numbers are based on the former McNugget serving sizes.
@ChanwooPark-me1wc
@ChanwooPark-me1wc 2 года назад
이번 문제는 아마 처음으로 제 힘으로 풀어 본 TED-ed 수수깨끼인 것 같습니다. 혼자서 풀어보니까 성취감도 느끼고 더욱 재미있네요. 앞으로도 이런 영상 많이 올려주세요! 좋은 영상 감사합니다.
@EnriqueLaberintico
@EnriqueLaberintico 2 года назад
Reached the 70th riddle! We have come a long way.
@MrFishio
@MrFishio 2 года назад
I never thought I’d hear a story about Dino chicken nuggets in war but here we are
@matthewdodd1262
@matthewdodd1262 2 года назад
If anyone has ever heard of the McDonald's 43 nuggets problem, then they should have instantly known what the answer was. Exact same problem, exact same numbers, just simply given a different coat of paiint
@SilenceIsDeafnin
@SilenceIsDeafnin 2 года назад
Haha the chain restaurant mascots at 0:20 were hilarious. (Ronald McDonald, Burger King, Wendy)
@TheOldBlackShuckyDog
@TheOldBlackShuckyDog 2 года назад
None of these riddles are ever really riddles. They’re just maths problems with a story
@yunaaaa46
@yunaaaa46 2 месяца назад
fr
@sinnerthesinful552
@sinnerthesinful552 2 месяца назад
So... a riddle?
@samsungturtle368
@samsungturtle368 2 года назад
We really got Ronald McDonald, Burger King, and Wendy teaming up to eat some dinosaurs. Nice to know that despite the fact that they're constantly at war with each other they're willing to team up to eat some baby dinosaurs.
@prajna-thingsbrief7496
@prajna-thingsbrief7496 2 года назад
Ted always provide everyone with a wide range of knowledge and also inspire science to the world
@ZeneonOMEGA
@ZeneonOMEGA Год назад
0:02 “I fart in your general direction.” Why did this kill me of laughter?
@grimtygranule5125
@grimtygranule5125 2 года назад
"It is possible to solve this problem with trial-and-error" Not when we only have *one* kingdom it isnt.
@alex2005z
@alex2005z 2 года назад
Just yolo it
@Trip_koLng
@Trip_koLng Год назад
I finally found their video with the funniest quote that I thought never existed
@voltmatrix1250
@voltmatrix1250 2 года назад
I thought a wall segment of 1 was 1 meter, and we had to fill 1 km or 1000m. So the answer I got was 997. On the bright side, this is the first time I solved a ted-ed riddle.
@merolivia
@merolivia 2 года назад
997-49=948. 948÷6=158
@ie8118
@ie8118 2 года назад
Yeah it does say each wall segment is in meters, cause all the weapons are also in meters. I got confused the same way I thought it was asking how can we make the longest wall in 1 print and I missed the thing about equal segments
@Aleinwhisper455
@Aleinwhisper455 2 года назад
"I fart in your general direction".... Yes I shall
@yur048
@yur048 2 года назад
Easy solve: if the builder always takes the same time, and the enemies have an big number, although finite number of walls breakers, just make an 9999999999 Meter wall
@unrellated
@unrellated 2 года назад
But the opening is only a single kilometer wide.
@fandroid6491
@fandroid6491 2 года назад
Imagine making a 9-billion meter long wall...
@ie8118
@ie8118 2 года назад
Yeah speaking of the opening being only 1km wide, my thought on why that wouldn't work is that if it was that long the wall and wall machine would start going into enemy territory, and they'd destroy the machine, stop it from generating more and then just take time to destroy it
@FunWithPraKat
@FunWithPraKat Год назад
Fun fact the best way to apologize if this is an accident is: I’m sorry I didn’t know how much those dinos meant to you. Fun fact: The best way to apologize if this is on purpose (which it is) How did you feel? I felt sad. Sorry I broke my promise.😮 true it’s on Ted Ed channel best ways to apologize.
@onetwothreefour386
@onetwothreefour386 2 года назад
Just make a wall that’s less than 6 There no rule saying that they can’t removes walls below the break freashold So if you wanted you could make a bunch of 1 length walls and be chillin
@onetwothreefour386
@onetwothreefour386 2 года назад
Never mind, I completely ignored Rule 1 :(
@onetwothreefour386
@onetwothreefour386 2 года назад
Better Idea : Build a wall so ridiculous big Like 10000000000000 Lengh, it would literally take then years to break it (the fastest they could go is 20) And the wall maker says it can create ANY wall in the SAME speed REGARDLESS of lengh
@JoeThomas-lu6fy
@JoeThomas-lu6fy 2 года назад
@@onetwothreefour386 The gap is only 1km, so that wouldn't fit.
@absolutetriad7714
@absolutetriad7714 3 месяца назад
​@@JoeThomas-lu6fybut still, a 1km wall will hold fast, @onetwothreefour386 might be onto something
@franciscorui
@franciscorui 2 года назад
You guys are like the Riddler in terms of what constitutes a riddle.
@gamixhyperdrive8425
@gamixhyperdrive8425 Год назад
While I didn't get the solution (and actually tried trial and error lol), the solution shown is strange. Yes, 43 cannot be made out of 6s, 9s and 20s. I fully agree there. What I don't agree with is what is shown and presented during the video. Here's the thing... It shows that Redheadonia's weapon is 20m wide. At 1:30 however is what is the confusing part. It shows 4x7 walls that in total are 28. This wall is considered as 28 now and cannot be taken down.... but if I add more walls with the length 7 this way (since that 28 is made out of 7s as SHOWN in the video) it will reach 63 which can be breached by 9m. So while 43m walls alone can hold out... a 86m wall will crumble. Now, I hear the explanations already "It overlaps so it cannot break!", etc., etc. Then the video should've shown it properly. To me, the 28 made out of 4x7 was very misleading because what keeps me away from also just attacking it with 2 6s and 1 9? That's 21 which would break that 3x7 segment. That's just how I see it though. I also thought that because of this you could make different lengths at one point since reprogramming it seemed fairly easy (but rereading the rules clearly meant that I can print only one wall segment length). In the end, visuals and rules contradicted each other. Who knows if it would've been better without them or correct visuals...
@ottodog9154
@ottodog9154 2 года назад
They won’t become unhappy meals got me 😂
@worldofgaming748
@worldofgaming748 2 года назад
Fact: It's your habit to check the comments after watching videos. No matter WHAT
@AnthonyDentinger
@AnthonyDentinger 11 месяцев назад
That’s not true! I haven’t- oh.
@ASmolPotatoOntheInternet
@ASmolPotatoOntheInternet 2 года назад
Doing maths in school: ❌ Keeping the Dino nuggies safe using maths: ✅
@penguinchess
@penguinchess 2 года назад
Imagine being able to bust down all walls of length 44 and greater but not being able to bust down a wall of length 1...
@kohwenxu
@kohwenxu 2 года назад
Or not being able to bust down the wall one shorter (43)
@kohwenxu
@kohwenxu 2 года назад
42 and 44 are bustable, but not 43
@ie8118
@ie8118 2 года назад
I think cause it must contact into both side pillars Actually I don't think wall length 1 would be possible if each must have 2 pillars
@missusboonandoodle489
@missusboonandoodle489 10 месяцев назад
Twenty three 43's, and an 11. That combination will protect you.
@samanahassan2725
@samanahassan2725 2 года назад
Lol I thought I got it right on the first try cuz I did 997 lol
@GandWizard
@GandWizard 2 года назад
Me too! 1 km = 1000 metres, so I sought the largest prime under 1000, 997 metres. As no maximum size is given, I don't understand why this answer is not correct.
@EnriqueLaberintico
@EnriqueLaberintico 2 года назад
I recognised the Chicken McNugget Theorem and ended up finding a formula that gave me 151, ab - a - b. Turns out it can be obliterated by 5 redheads, 5 royals and a clown.
@EnriqueLaberintico
@EnriqueLaberintico 2 года назад
@@GandWizard 47 redheads, 5 royals and 2 clowns. 47•20 + 5•9 + 2•6 = 940 + 45 + 12 = 997
@GandWizard
@GandWizard 2 года назад
@@EnriqueLaberintico Thanks for pointing out the flaw in my assumption!
@aj28b2xe16
@aj28b2xe16 2 года назад
الحُزن! يقول ابن كثير رحمه الله: "لا تُستنار البصيرة إلا بالحزن، فعندها يرى المرء حقيقة كل شيء؛ حقيقة نفسه، وحال قلبه وصحبته وأهله، حقيقة الدنيا على حالها، فيجعل الله من كل ذرّة حزن في نفس العبد نورًا يضيء به بصيرته حتى يدرك هوان الدنيا برغم جمالها وحقيقة الأشياء".
@davidtitanium22
@davidtitanium22 2 года назад
Enjoy your impregnable fortress while the long siege wears down the defenders and as food supplies dwindle, the morale of the soldiers dropped to rock bottom until eventually you are left with the ultimate choice you need to make to survive. At that point, everyone else has made their own choices on the matter. Chaos reigns as the people who chose to abandon their faith over their hunger stormed the creatures' sanctuary and the starved defenders need to point their weapons to their fellow countrymen, resulting in a lot of losses. But wait, look at all these fresh bodies! Surely they were provided to you by the gods themselves to let you survive just a bit longer? You command the troops to gather and not to waste a single cadaver, anyone who refuses to eat will be put to the sword to become part of the meal! We are following a divine calling after all. Our lives will serve the gods until the end! Thus went the day, two days, three days, a week, two weeks, three weeks. The chaos has toned down as anyone who would openly revolt has died and become food. The masses is back to starving. Some rumors on the street is the remaining pockets of resistance will try to open the gates and let the enemies in. You began to suspect eveyone but your closest friends. The paranoia led to more killings, as anyone suspected of betrayal will be immediately punished. Until three months later. You have lost 70% of the original population of your country. At one night, while the constant guilt and paranoia kept you awake, your "friends" visited your room. They have had enough. All of them began stabbing you and while you fall to the floor in a pool of blood, you see them slitting their own necks. Ah, the country you've fought so hard to protect. Will the gods at least be proud of what you've done?
@thecoconutnutisagiantnut7525
@thecoconutnutisagiantnut7525 2 года назад
The siege will probably end before that
@fandroid6491
@fandroid6491 2 года назад
Olo
@redfluxbluedawn414
@redfluxbluedawn414 2 года назад
I seem to be missing something... The width to be defended is 1000, which isn't divisable by 43, so that leaves a gap of 11 through which the enemies can get in? Wouldn't it be simpler to produce 997 + 3 instead of 23 * 43? Or if you want to stick to 43, produce 1 extra piece of 11 to close the gap?
@blakechow8294
@blakechow8294 2 года назад
The instructions say you can fill the gaps in with boulders
@alex2005z
@alex2005z 2 года назад
997 could be broken with 3×9+5×6+47×20. And making 23 walls of 43 and 1 of 11 is the fastest way possible
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