Capgemini Java Coding Interview | Watch this if you want offer 

Great ..now we are aware of character class and its methods, toUpperCase(), toLowerCase()

One more way to do this, will just go on checking with the reference of index value I will check with arr[0] == I+1 if not the missing element is the I+1

Really good questions. Thank you!! Please, make videos on questions related to Collection also.

String s = "India is My Country India is My Country"; String s1 = s.substring(0,s.length()/2); String s2 = s.substring(s.length()/2); String result = "\0"; result = s1.toLowerCase(); result += s2.toUpperCase(); System.out.println(result);

i was asked missing and repeating number program for 3.5 lpa package

please don't do DS and Algo, we can get this easily. Do class related videos like Employee, list of employees , increase their salary, group by etc

public static void main(String[] args) { int [] arr = new int []{1,2,3,5, 6,7,8,9} ; int n= arr. length+1; int sum = n* (n+1) /2; for (int i : arr ){ sum -= i; } System.out .printIn("Missing number is "+sum);

If they really ask these questions I'm gonna go into interviews right now

Don't you think for missing number code the formula will result in overflow if n is very very large

So you don't need any actual DSA problem solving skills for Capgemini?? Is it that easy or am i missing something

Here is the simplest way public class StringQuestion { public static void main(String[] args) { String str="Capgemini Coding Interview Questions Capgemini Coding Interview Questions"; String upper=str.substring(str.length()/2,str.length()).toUpperCase(); String lower=str.substring(0,str.length()/2).toLowerCase(); System.out.println("The final output is "+lower +" " +upper); } }

if only one no is missing then only answer will work.what if 2 no are missing .

tysm for teaching begneers

This is not an actual capgemini interview....

Excellent

I must have the worst luck, for a 5LAP job, they asked me codewars morse code advance, as a fresher. 🤣🤣

String lowerUpperString = new StringBuilder().append(str.substring(0, mid).toLowerCase()).append(str.substring(mid).toUpperCase()).toString();

Sound is too low!

Plz post real time questions

Birlliant

If I provide the number in put how u find the last element in this case 10

He could have taken an variable with initial value of 1 and compare it with every element. If equal, increase value of that variable. Where the variable and element value differ, break the loop and cur value of that variable is the output.

capgi bht chindi company hai package ke mamle me