Carnot Cycle & Efficiency 

Liked ur style of writing 'A' 😂

1-2 isothermal expansion 2-3 adibatc expansion 3-4 isothermal compression 4-1 adibatc compression Isothermal meant change in T equals ZERO or T is constant throughout Adibatc means change in Entropy equals ZERO.

OMG thanks to your video I finally understand the Carnot Cycle for my presentation. Thank you so much !

In process 3-4 the workdone should be [-mRT2 ln(V3/V4) ]

When we find the value of q 3 to 4 - it negative values then why not put the value of negative in efficiency of carnot ....??????

Helped a lot....ill pass because of you:)

Fully byhearted

Nice hand. Writing and good explanation sir ..

Sir if adiabatic compression and adiabatic expansion is remove from carnot cycle than what happen and what is the efficiency

This what happens if you know physics but don't know maths. 🤣🤣🤣

Kal mera paper h Or mujhe aaj yaad are h sir ji

A Million Thanks to you Sir☺🙏. You explained very neatly .

Process 1-2 is an isothermal process, how come T2 is then different from T1, constant temp expansion means there is no change in temp during the process, which according to your derivation implies that the efficiency is zero. And how this adiabatic process equation is applicable for the process 1-2

Thermodynamics gives you bounds on real engines. Moreover, the explosion of the fuel mixture is not even approximately reversible. How can thermodynamics be of any use, in designing real world internal combustion engines?

Thank you !! 👍🏻

7:27 if its ln(v4/v3)then how can the numerator and denominator get cancelled the numerator denominators inter change

In exam if you don't want to waste your time on writing long limitation. Then you write this much only , "But practically it is impossible to achieve" Therefore: "There is no real heat engine of 100% efficiency " 👆🏻This much is enough this contain that all things..🙂

Awee such an awesome sound❤️👀

sir, you explained very neatly but for site students it is not visible clearly from a hand distance, for now it's ok sir but from your next videos please explain on a white page where light is clearly visible, it is a request from me and the students who face the same problem.

Sir value of work 3-4 was negative........so why it did not make the efficiency n= 1 - (-mRT² ln (V⁴/V³) ----------------- mRT¹ ln (V²/V¹) Please explain sir

wrong at end adiabatic relating with volume

Nice work brother 😍

Tq for good explanation

Thank you sir . your explanation is very neatly

Exam se ak din pahale 😅😅😅😅

Thank you sir I understand this topic

Sir can you plz plz reply quickly my question answers 1. A piston cylinder system contained air is worked on carnot cycle to do some mechanical work. Initially ,the system contains air at 1bar ,298k and 0.01m3. the system is first compressed until the volume is 0.002m3 (isothermally) .after that, the system undergoes an expansion process (isothermally) to a point where pressure in the system is 5 bar .At that point , the system is subjected to an isothermal expansion process until system reaches the initial state completing a cycle. Calculate the net work done of the cycle and cycle efficiency.

This is easy method to learn tqsm sir😊

You wrote the wrong thing when replacing Q³-⁴

Sir thanks this is easy method to learn

Where did the -ve sign go because heat produced by 4---1 was -ve And V4/V3 = V1/V2 then how can you cancel them by changing denominator with numerator (i.e V2/V1)

Sir plzz draw Carnot cycle accurately...

how is - - not equal to plus?

Sir explain the keerchoffs law

Nice video sir

Finally mujhe carnot cycle ki efficiency samajh aa gyi. Thanku sir😇

Nice Voice recording 👏

Sir that part Q3-4 equals minus was there but after where the minus was out

Is it possible to perform it

Well explained..👍😍

Amazing

What happened to the -ve sign of Q3-4 when you substituted it in 1-(Q3-4/Q1-2)

Super sir

Sir ,you forget to write negative sign in Q3-4 and you written V4/V3= V1/V2 as V2/V1

Absolutely great way of teaching ...all understood 😊

Thankyou sir

but sir Q3-4 ka minus Kahan gya

Carnot cycle is cyclic process? If it is then initial state should be equal to final state t1=t2, p1=p2 and so on. And plz explain reversible word you use in cycle? Is it means that you added hear from process 2 to 3 ,can reverse from 3 to 2 with out effecting system and surrounding In a cycle?

Thanks🙏🙏 sir

thank you sir.very well understood

WHICH IS COMPRESSION WHICH IS EXPANSION BRO IT IS AN INCOMPLETE PRESENTATION

Nice video 👍

Thank you!

Nice sir ❤️👍

Why have you taken T2 replacing T3 in Q3-4 ?You just copied from book not explained well

Can the efficiency of Carnot’s engine be 0 or 1?

Tq so much bro

Thank you❤ sir

🙂

Nice video

Nice one

Tq sir 🙏🙏 adorable explanations 🙏🙏😛

How u substute in v2/v3=v1/v3 in efficiency

Nice..🇧🇩🇧🇩♥️♥️

Can I write this derivation for my bsc 2nd year exam?

Soo Nice

pliz explain stirling cycle

Nice

Thanks you

👍🏻👍🏻

You sound like ROHIT (Hritik Roshan)from Koi mil when watched at 2x speed

Thank you sir, for explaining 😇

Thanku sir👍👍

TNX Bhai

Tnq u

Where is source or sink🤔🤔🤔???????

Yu to sir ji book se hi pd lenge 🙂

1:51

Q3-4 value is nagetive and you use it as positive why

Kya yaar likhte time kbhi tera haath aajata h or kbhi vo typing kuch dikh bhi nhi ra 🙄

Nice😇

Sir apana contact send kr

🖤❤️❤️

CAN I BORROW UR HANDWRITING FOR MY TODAY'S EXAM !! PLEASE 🙏❤️🥺

Kya galt comments karte han log

Puri engineering me mko thermodynamics se bhut Dr lgta h bilkul smjh ni aati ye

It is inter

ARVIND VERMA FAIZABAD CLASSES 365🙏

Ho it is possible 4to 2 ,4 to1

Firstly u say Q1&Q2 are adiabatic process and know u r writing in next steps that 1-2 ara reversible isothermal and 2-3 ara adiabatic wtf is that.. 🙄

Shakir

wingis 😍😍😍😍

Please be energetic

Plz tell that telugu

Ur voice is like Hritik Roshan somehow😅

Sir hindi me bola kijiye

Sir don't put words in the bottom of video it's hidding the video

Minus kha chod dia bro .kuch vi poor

Telugu lo kuda explain chesthee ardhamavthundhii raaa

K ho yesto jama