Ceiling fan ke RPM Kaise pata karen | Perfect Engineer 

Kal

Iss par kaafi video bana rakhi hai

@@PerfectEngineer Transformer data kaise nikaalte hain

Kahan se padhaai ki Hai sir aapane Maine ITI aur diploma donon kiya hai aur RPM ki ful form hamesha round per minut hi padhaayaa gaya hai aapane kuchh naya Bata Diya

Aur Delhi Pusa ITI aur Pusa diploma se

​@@ankitnagora5161Rotations per minute is right answer! Revolution per minute it's for engines not for fans.

Jab number of pole kam hote hain to RPM jyada or pole jyada ti RPM kam hote hain

@@PerfectEngineer to brother wohi pooch raha hun aisa q hai ...technical way mein jawab dein...

Bro bataya to wahi tha but aapko simple bhaasha m samajh nahi aaya to technically samajh lo, RPM nikalne ka formula hota hai, N= F×120/P N= Syncronus Speed F= Frequency 120= Connection ki °( Digree) Yani 360°/3phase=120°ka kond bana P= Motor k Pol Isiliye Formula hai N= F×120/P N= 50×120/12=500 To 12+12 k RPM hue 500 Ye Syncronus Speed hai Ab Load pr RPM bachenge 500-5%=475 475 Motor k Standard RPM ( Speed) hai Bro isse jyada ab m nhi samjha sakta 🙏🙏🙏.

@@PerfectEngineer ghussa hi kar gaye aap to brother..phir bhi wohi sawaal hai aap ghaur say nahi parh rahay.... aap technical way mein formula samjha rahay hein working nahi... mein yeh poochna chah raha hun k theek hai rpm 14 k sab say zeyada hon gey lekin phir hum 18 ka stator ya 21 ka stator q banatay hein 14 ka hi laga laitay hein winding bhi kam karni paray gi waqt bachay ga... rpm bhi zeyada milein gey... 36 ya 42 slot stator q banatay hein phir hum?

subscribing..

Iska matlab science ke formule wrong hote hain 12 coil 3 phase ki motor m hote hain 12/3=4 pole Use formula N= F120/P ( N=50x220/4) = 1500 RPM 1500-4/5%= 1440 RPM Kahne ka matalab ye hai ki 12 coil ki 3 phase motor k ek circuit m 4 pole hote hain

@@PerfectEngineer Let's we have an induction motor with p=2 and feed it from 50 Hz grid. Then we re-connect the winding coils to arrange p=4 and feed if grow 100 Hz grid. Are performances of these two motors different or the same? Please note excluding frequency and inter-coil connections all remained the same. It depends on the required speed. n (rpm) = (60 x f) / N where f = frequency and N = number of pole pairs. The 60 is there to convert from revolutions per second to revolutions per minute as the frequency is in cycles per second. Pole pairs is there because that any pole must be constructed in a pairs top and bottom / left right, so with one cycle it will move half the distance. If you are using 50Hz and have a two pole motor 60 x 50 / 1 = 3000 rpm. The induction motor will run at a slight less speed due to "slip" which is what gives the motor its torque. For example 5.5kW, 400v, 2 pole motor will run at approximately 2880 rpm. For a four pole machine, 60 x 50 / 2 = 1500 rpm so the same size motor at 5.5kW, 400v but 4 poles will have a nominal speed of 1500rpm but will run near 1455 rpm. 👉When selecting a three phase motor, the number of poles is chosen to achieve the speed of rotation that you require. Here are two tables, one for a 50 Hz power supply and one for a 60 Hz power supply: The formula is n = 60 x f /p where n = synchronous speed; f = supply frequency & p = pairs of poles per phase. The actual running speed is the synchronous speed minus the slip speed. For a 50 Hz three phase supply: 2 poles or 1 pair of poles = 3,000 RPM (minus the slip speed = about 2,750 RPM or 6 -7% n) 4 poles or 2 pairs of poles = 1,500 RPM 6 poles or 3 pairs of poles = 1,000 RPM 8 poles or 4 pairs of poles = 750 RPM 10 poles or 5 pairs of poles = 600 RPM 12 poles or 6 pairs of poles = 500 RPM 16 poles or 8 pairs of poles = 375 RPM For a 60 Hz three phase supply: 2 poles or 1 pair of poles = 3,600 RPM (minus the slip speed = about 2,750 RPM or 6 -7% n) 4 poles or 2 pairs of poles = 1,800 RPM 6 poles or 3 pairs of poles = 1,200 RPM 8 poles or 4 pairs of poles = 900 RPM 10 poles or 5 pairs of poles = 720 RPM 12 poles or 6 pairs of poles = 600 RPM 16 poles or 8 pairs of poles = 450 RPM To determine the number of poles, you can read the data plate directly or calculate it from the RPM stated on the data plate or you can count the coils and divide by 3 (poles per phase) or by 6 (pairs of poles per phase). Where the power of the induction motor is constant, the torque increases at the rate that the speed decreases 👉 I hope you understand