At that time i was attending your lecter ...i did understand about centrifugal compressor......now today i am working on centeifugal compressor ....that some point is missing than idid search on youtube ....now i am waching your video ...this video is very helpful for me
Thank you for this video. Can you provide me with an explanation showing what amendments can be done to change the centrifugal pump to a centrifugal compressor? OR can we use the same pump for compressing gas?
In which application water is being compressed in compressor... Can u tell me plz. Bcz as much I know compressors are only used to compress fluid having very small density like air and gases while for heavy liquid like water pump is used..
The only person who really understands the physical behavior!!!... the other people just learn from memory how to draw the velocity triangles (which do not help understand well the working principle) CONGRATULATIONS!!!
lecture is good. but there are few mistakes. such as it is not neccesrly 50% pressure rise in rotar and 50% in stator but fraction of pressure rise occurs in stator and rest in rotar. and another mistake is that pressure rise in rotar in not only because of increase in passage since there is external work involved. pressure rises to counter centrifugal force is also involved.
Arvind, I would like o clear your doubt 1) In the lecture I have said that its a 'common practice' to raise the pressure 50% in impeller and 50% in diffuser it means It is not necessary of course. 2) The static pressure rise of a moving gas takes place only due to 'diffusing action' that is by transforming K.E into Enthalpy. Suppose a pipe in which some fluid is flowing and there is turn in pipe . When fluid will pass that turn then; does at the exit of turn the static pressure of fluid will rise? the answer is no. At the moment the fluid was taking turn then it would experience centrifugal force on corresponding surface of pipe. When fluid will pass away the turn then pressure would be same is it was before entering the turn. But imagine that the pipe haves a turn together with diverging cross sectional area . In such case at the exit of turn it would experience the hike in pressure due to diffusing action. Workdone by impeller - rise in KE - Diffussing action - Rise in pressure
Amit Mandal thnx I got 1st point that was my mistake. but i couldn't get second point. yes there is pressure rise due to increase in area due to decrese in relative velocity. but what abut influence of change in cercrumfrencial velocity. U1 to u2. that will increase fluid pressure due to counter centrifugal action. in pipe there is no cercrumfrencial velocity involved so what u said is right but not in this case.
Hi sir Is there any more explanation for the conversation of centrifugal action to the pressure rise.? Any equation or mathematical explanation ? Can you please provide .?
Sorry, please at what velocity does air strike the nozzle. Let's rage for instance in a turbocharger of an IC engine. At what force does the air enter the compressor please?
+Onyedika okpala- ideally the air enters the nozzle with 0 velocity.however practically its mass flow rate / (density at entry ×area at inlet of nozzle), the force at inlet = pressure of air at inlet × area.
ashok ashok, P=F/A is true only when Force is restricted by perpendicular Area, that means the Pressure there rests on the blocking area. But when we talk about amount of mass of air flowing through an open Area, Pressure is not restricted therefore F = mass flow rate times velocity. In that case, according to Continuity Equation, the lesser Area embodied in that formula of mass flow rate (Mass Flow Rate = Density X Area X Velocity), the resulting Pressure must also be lesser due to conversion of Pressure formula as P = (0.5 X Density X Velocity squared) + given Static Pressure (due to atmospheric pressure). This is the Incompressible Bernoulli principle for convergent - divergent flow of air in stream tubes such as the one discussed in centrifugal compressors. If the velocity of air reaches more than 0.30 Mach, the equation becomes Compressible and Isentropic Flow equations must then be used instead. Do not confuse the formula P = F/A because it is not applicable on cross sectional areas that are open for fluid flow.
Sir you are telling in this video (cross sectional area decreases the pressure decreases it is not correct sir example if you take pressure is equal to force per area. So the pressure is inversely proportional to area so the area decreases in that place the pressure increases.
P=F/A is true only when Force is restricted by perpendicular Area, that means the Pressure there rests on the blocking area. But when we talk about amount of mass of air flowing through an open Area, Pressure is not restricted therefore F = mass flow rate times velocity. In that case, according to Continuity Equation, the lesser Area embodied in that formula of mass flow rate (Mass Flow Rate = Density X Area X Velocity), the resulting Pressure must also be lesser due to conversion of Pressure formula as P = (0.5 X Density X Velocity squared) + given Static Pressure (due to atmospheric pressure). This is the Incompressible Bernoulli principle for convergent - divergent flow of air in stream tubes such as the one discussed in centrifugal compressors. If the velocity of air reaches more than 0.30 Mach, the equation becomes Compressible and Isentropic Flow equations must then be used instead. Do not confuse the formula P = F/A because it is not applicable on cross sectional areas that are open for fluid flow.
there is big contradiction in your statement 1.velocity is directly proportional to area so as area increases so the velocity and ultimately pressure decreases (nozzle is used to increase the pressure not velocity) please reply on this as soon as possible,,,,emergency
sir,asking about 1.converging nozzle which has bigger area of intake than outlet 2.we use nozzle to increase pressure or velocity?? .morrow im having exam please clear it soon
sumeet more nozzles are generally used to gain kinetic energy by increasing fluid velocity thus pressure is converted into velocity inside a nozzle. Diffuser is opposite to that of nozzle.