Centripetal Acceleration & Force - Circular Motion, Banked Curves, Static Friction, Physics Problems

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This physics video tutorial explains the concept of centripetal force and acceleration in uniform circular motion. This video also covers the law of universal gravitation, weightlessness, banked curves with friction, kepler's third law of planetary motion and other stuff. This video contains plenty of examples and practice problems.
Circular Motion - Formula Sheet:
bit.ly/4gIUL3r
________________________________
Centripetal Acceleration:
• Introduction to Centri...
What Is a Centripetal Force?
• Physics - What Is a Ce...
Centripetal Force Physics Problems:
• Centripetal Force Phys...
Tetherball Physics Problems:
• Tetherball Physics Pro...
Tension Force - Vertical Circle:
• Uniform Circular Motio...
_______________________________
Static Friction & Centripetal Force:
• Static Friction, Centr...
Normal Force on a Hill:
• Normal Force on a Hill...
Banked Turn Physics Problems:
• Banked turn Physics Pr...
Non-Uniform Circular Motion:
• Non-Uniform Circular M...
Gravitational Force:
• Gravity, Universal Gra...
______________________________
Universal Law of Gravitation:
• Gravity and the Univer...
Gravitational Acceleration:
• Gravitational Accelera...
Gravitational Field Strength:
• Gravitational Field St...
Satellite Speed:
• Speed of a Satellite i...
Kepler's Third Law of Motion:
• Kepler's Third Law of ...
____________________________________
Kinetic Energy and Potential Energy:
• Kinetic Energy and Pot...
Work, Energy, and Power:
• Work, Energy, and Powe...
Final Exams and Video Playlists:
www.video-tuto...
Full-Length Videos and Worksheets:
/ collections
Physics PDF Worksheets:
www.video-tuto...

Опубликовано:

3 окт 2024

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Комментарии : 588

@TheOrganicChemistryTutor Год назад

Circular Motion - Formula Sheet: bit.ly/4gIUL3r Physics PDF Worksheets: www.video-tutor.net/physics-basic-introduction.html Full-Length Videos & Exams: www.patreon.com/MathScienceTutor/collections

@AliKisubi-sv4ul 2 месяца назад

thanks so much

@iconic410 4 года назад

Timestamps for this lesson: Note: He sometimes teaches concepts(Kepler's third law, tangential acceleration...)during the practice problems so make sure to look out for those 0:00 - Intro 0:15 - Centripetal Force 14:31 - Centripetal Acceleration 15:22 - Period and Frequency 16:32 - Tangential Velocity 32:40 - Vertical Circle Problem(Varying centripetal acceleration) 1:10:59 - Gravity and Newton's Law of Gravitation Problems: 1. 18:50 2. 23:42 3. 26:27 4. 35:26 5. 38:05 6. 40:17 7. 46:31 8. 50:15 9. 58:12 10. 1:01:41 11. 1:07:31 12. 1:15:51 13. 1:22:29 14. 1:24:35 15. 1:31:22 16. 1:36:53 17. 1:43:24 18. 1:47:45 19. 1:50:34

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@chovvyy 5 лет назад

I know it’s too much too ask, but timestamps in these kinds of long videos would be extremely helpful. Other than that, very well explained and you’re a without a doubt a lifesaver!

@tx2sirk466 5 лет назад

Sad Toad +

@rei___l 4 года назад

click open transcript in the three dots next to the save button, you'll see timestampss

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but you are Elon Dusk surely you know like everything :)

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@@rei___l that does not help bruh

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@@cactus8911 why not

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50+ circular motion solved problems - : ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-SlJmzMCiHn8.html

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@picturebazzare 3 года назад

The circular motion and, the effect of magnitude of radius on the time period of an object was investigated in this practical. According to this the relationship between the radius and the period as follows, T 2 = r According to the collected data it was able to prove that above statement.

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@therandomperson9627 2 месяца назад

1:01:30 the answer for net acceleration is done right but due to intermediate rounding the answer became off by 0.4 In this scenario, 0.4 is a slightly large difference since the answer itself is less than 10. Rather if a direct input of the v^2/r in the Pythagorean equation then it would yield about 5.26. You taught the right way but it was just off due to rounding. But still you helped me learn how to approach these problems

@picturebazzare 3 года назад

The force causing the vertical acceleration comes from the centrifugal force. This causes the swings to move at a faster speed which then ultimately leads to the swings moving outwards and, in the direction, going up.

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@greatpharoh0303 4 года назад

Slight correction for the teatherball problem, for T x all you use is mv^2/r and T y is mg so you get 29.6 and 2.45. By pathagorean T = 29.7N right?

@DC-qk7hx 4 года назад

I'm just curious why the problem at 45:00 does not use formula FT = sqrt(FTx^2 + FTy^2), taking into account the effects of gravity

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it has been 5 years that u made this video. I am not sure whether u r gonna answer my question or not. But still, (56:39) u solved Normal Force equals to mg/cos. What makes it different from the other questions that the normal force was usually mg x cos? why makes the normal force to be mg/cos? Also, Thank you for making these videos. I like how u explain the general concept first and then u solved questions that are related to the concepts that u just taught.

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@Do-Some-Change Год назад

Awesome Teacher Ever found in Life

@andrewpq5149 Год назад

35:21 I got a question. Shouldn't the forced acting on the ball at point A be T-Fg because only T is pointing towards the circle. Point C should be T+Fg because both T and Fg are providing the centripetal for, so they should both be positive

@ArcherGabs 5 лет назад

Hey I think you made a mistake at around 35:00, the tension at the top is equal to the sum of the weight force and the centripetal force, and the difference of them at the bottom.

@DavidGarcia-ve2ll 4 года назад

Archer i’m thinking the same thing too but thinking about it it kind of makes sense because at the top the tension would be less than the tension at the bottom since gravity is helping the fc at the top and relieving tension, and at the bottom fc is trying to go up wards and gravity is pulling the opposite direction, increasing the tension. so the tensions there should be T at point A>C which proves his equation but i also get what you mean so i’m very confused lmao

@ralphanthonymallillin2712 3 года назад

Nope..actually it'a correct...he said that centripetal forces are positive when the direction is seekin to the center of the circle..He wrote it as Fc=T+Mg at the top since both Mg and T are directed through the center..and Fc=T-Mg at the bottom since T is directed through the center and Mg is away from the center :)

@kabouch 3 года назад

8:49 in this example, I would think that the normal force is balanced by a force of the magnitude of mgcosΘ and in an opposite direction; while, the acceleration along the direction of the velocity is due to a net force equal to the (mgsinΘ-friction) force. At the initial point when the moving object is no longer in touch with the ground i.e. when the gravitational force is not balanced by the normal force, the object accelerates downwards by gravity.

@ghadaalshanbari 6 лет назад

literally everytime i try and watch other videos i end up back at yours because you explain them the best!

@roberto3196 6 лет назад

Great video, but one question. At about 46:28 did you just not count the tension force for the Y component when calculating the overall tension force because the Y component tension is almost negligible? I counted the Y component and got 29.7 N instead of 29.6 N.

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@ntingletstacy3977 Год назад

I think there's an error; the value of the speed is 251.3m/s because the period T is equal to 0.25 sec not 0.2

@ivykanene2963 3 года назад

He is a saviour

@hasanciftci9432 5 лет назад

I had exactly that question. The question ask me the acceleration which i calculated and find 4 m/s2. But in answers i saw in two choice the number 4. The first: constant, with a magnitude of 4 m/s2 the second 4m/s2, pointing the center of the circle. Thanks God that i watch your video.

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@emigdiovillalobos5417 6 лет назад

force is linear with R, because V itself is a function of R. and when you square V you get an R^2 and R^2 divided by R is R. so R is linear with force.

@arhamsiddiqui7083 4 года назад

One thing that really helped me understand the free-body diagrams is that remember that fNET= Fac all the time. So in the roller coster example, at the bottom, Fnet= Fac= FN-mg and then at the top it is Fnet = Fac = mg - FN

@ro1882 4 года назад

arham siddiqui what do you mean by fac? I guess i have studied too much and am starting to mix things up

@arhamsiddiqui7083 4 года назад

@@ro1882 i meant force of centripetal acceleration

@sarahjacobs695 3 года назад

I can’t thank you enough I understand centripetal force problems so much better now thank you!! 😁🥰

@harjindersinghjanda8644 Год назад

Mind blowing, it really serves the purpose, thanks 👏

@jktification 2 года назад

For the frictionless bank problem. I had to research the Normal force being greater than the weight force. Still would like more explanation cause is interesting

@nataliematlock9020 4 года назад

i love how this was made 3 years ago and i am using it now ::::::)))))))

@rohaankhalid5754 4 года назад

The radius is not directly proportional to the centripetal force, as there are two formulas, and this formula actually comes from the other one, so we have to take in regard the relationships in that equation. The other equation is F=mrw(power 2 )

@efairahh 3 года назад

who is here because they sleeping during online class but will have exam soon . . . . . . . . cuz i am ;/

@lalalia7724 3 года назад

my exam is tomorrow lmao

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Got lazy half-way through the semester, 3rd midterm this weekend and final the next, let's fucking GOOOO!!

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missed my 4th exam and now have to take it in 2 hours

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@@brittonlemere5486 How’d it go?

@shanks6190 3 года назад

I have a 3 hour exam tomorrow.

@SmacOG 6 лет назад

Binge-watching these videos before my physics final tomorrow

@altera1882 10 месяцев назад

Kepler's third law had me take a break for a while and then comeback later.. my head was going to explode.😂😂😂😂......... Otherwise this is nice content your'e definately a lifesaver.

@shirayokidono3356 3 года назад

1:07:10 I want to understand. you said that if the speed exceeds the value that makes the normal force equal to zero it's going to fly off the road. but if the normal force was already 0 the car will lose contact so the normal force needs to be little more than zero, not exactly zero. isn't that?

@dinethdayananda5950 3 года назад

hey but in the question at 1:27:58 ,isn't R the distance from the centers of the two objects,and in the question they say that 3000km is the distance from the surface of the earth

@DS-ut9um 2 года назад

You're the real god of students who are in all around of the world. You're wanted to giving god's avoid .well done man after 5 years this. Thank u sir