Ignoring the fact that the IITians are taking 5-10 mins to solve JEE Advance Paper questions and the Aspirants are expected to take 3 mins each at avg. But still the vid was cool ;)
Man that was the easiest question i've seen in JEE adv It took me just 20 seconds to answer it. I'm not arguing that he isn't intelligent but the question itsellf was too easy for anyone to solve it
Hey maaaannn... I was solving all the questions which u gave to them. I was able to solve 3 of them it boosted my motivation of my preparation bro.. Thanks man
Also, the toppers are so serious about themselves, that they are always in doubt whether they are doing it correctly or not😅, or the particular thing can be done better yet..
I did the maths permutation question in my mind 😂 then i realised it was easy considering the fact that I am a noob in maths and still working.. hope I get into an iit someday :)
Even the IITians are taking like 5 to 10 mins for each problem and sitting in a calm environment Imagine the person who is giving advanced paper , that person has very limited time and is sitting in exam hall with pressure on himeither the way , hats of to all the ppl who take this big steap and dream big and take responsibilities and decide wt they wanna do , I myself am a NDA aspirant , best of luck evryone for their upcoming challenges no matter we make it or not , we took this decision of working hard and giving our best
"What's the point of studying when we're ultimately going to forget it" this is what I used to think as a kid. Now, after watching this video, my curiosity got even more to get the answer to this question
@@Asleep_Beat oh c'mon it's been just an year. You are saying as if 1 year is a big time, they fucked their asses of studying for somany years and they forget it in just an year
Thanks tharun bro for making this amazing vdo..❤️ A huge respect to all the IITians who have participated in this video and they are trying the problems even though many of them forgot the concepts, they were not ready to give up! That's very inspiring and motivated for my jee preparation.
What makes this video unique is the end conclusion part. This just made my day and motivated me to practice more. (depressed from pyqs :/) Thank youu ❤❤
The take-away from the video stated at the end of the video clip is great. While intelligence and hard work play a role in succeeding in competitive exams, it is timely and current study and practice that ensures success as the human mind is not perfect and unless one stays in touch, one may forget the concepts learned. I liked the way in which Tharun provided this take-away speaking to 'what did one learn from the video'.
Mind boggling as always bhaiya..... Such a simple concept of the video but you still surprise with you shooting and editing skill...a bit late but loved the video❤️❤️
Damn!!...this is crazy🤯 it was freaking amazing🔥..I was very excited and solved of some them too...but the end of the video was really great..thanks for the video❤
This is true ya... *Practice is the key..!!* 💯💯 Good video..!!✨️💯 And I was actually expecting that u will announce there would be some unacademy class.. but u didn't... 😢😢... it's been more than a month... and no live interaction with ur audience yet... Please plan something of that kind... please...🥺🥺🥺 Btw.. did u shoot this video when u went to IIT Bombay?... I mean r they students of IIT Bombay or IIT Kgp..?
Man I too didn't revise anything but when I see a log question I straight away pause the video and run to get pen and paper and solved it...I too get the answer 8 ...m happy
HEY Tharun bhaiya..The video was so cool ..Learnt the key for achievement. One thing we missed was you solving one of the question 😃(I mean the 3rd and 4th year students of IIT). It would be more hilarious and nice video...
Hey Tharun ✍️ Been watching your videos since the past year and almost regularly this month. You're awesome. I didn't have the thought of starting preparing for jee back after 10th , i started prep in 2020 April and then couldn't get through in 2021. Even a partial drop was a complete depression thing. I've started doubting my capabilities now. But you keep me motivated. Thanks . Thanks a lot. You don't know what power you words really have .✍️❤️
My friend shared the chemistry advance question, with the movable partition stuff going on; with me and I solved it in 5 min max without realizing that was an advance level question. I still remember the answer was 20/9 maybe and to be honest the question asked in the video were not really hard. They were on the easier end of advance in my opinion
Bro Venkat's answer wasn't mentioned, so here is how I solved it. 1. 5 digits numbers must be made using {1,2,3,4,5} and repetition is allowed. 2. The 5 digit nums must be divisible by 4. The rule to find if a num is divisible by 4 is that the last 2 digits of any number (ie. one's place and ten's place) must be divisible by 4. Keeping this logic in mind, I wrote the table of 4s till the highest possible 2 digit num ie. 55 so the possible 2 digit multiples of 4 using the elements {1,2,3,4,5} are: 12, 24, 32, 44 and 52. 3. Now, the above nums are the nums present in the 5 digit numbers. 4. Therefore considering the 5 digit places: 5th, 4th and 3rd place can have 5 options (1) 2nd place can also have 5 options since, 12, 24, 32, 44, and 52 have all 5 elements in ten's place. but 1st place can only have 2 options (ie. 2 or 4) since the above nums have 2 or 4 in one's place. 5. Hence total no of 5 digits nums = 5 x 5 x 5 x 5 x 2 = 25 x 25 x 2 = 625 x 2 = 1250 is this correct? I am studying in 11th class, so I think I may be wrong. I welcome all kind of comments.
@@HarshaVardhanaRaj bhai aise questions aur odd digits walo me case banaya kr fir last me add krde first me 5×5×5×3 aayega 2 ko fix krke fir second me 5×5×5×2 aayega 4 ko fix krke fir inko add krdo ☠️
@@pussyhunter4292 oh bhai samajh gaya both 2 and 4 ek sath nahi ho sakta hai tho one's place keliye sirf 1 option hoga (2 ya 4) therefore: total = 5 x 5 x 5 x 5 x 1 =625
The answer to AP question was wrong how can there be 3718 common terms if there are only 2018 terms in each set, i got 288 as the answer even in the gaseous state question i got 20/9 as the answer not 1.5
Ans of the first question F=ati+bj a=1, b=1, m=1 dv/dt=ti+j v=t²/2i+tj+c, t=0, v=0 c=0 v=t²/2i+tj dr/dt=t²/2i+tj r=t³/6i+t²/2j t=1 r=1/6i+1/2j Torque=(1/6i+1/2j)×(i+j)=-1/3k
Carry on with the same attitute man!! keep that spirit up..!!😇 You are on the way to something undiscovered..It seems Your skills are at another level..keep hitting hard man.!❣💌
What is The number of 5 digit numbers which are divisible by 4, with digits from set {1,2,3,4,5} and the repetition of digits is allowed Ans To determine how many 5-digit numbers are divisible by 4 using the digits {1, 2, 3, 4, 5} with repetition allowed, we can break down the problem into cases: Case 1: The last two digits are 12, 24, 32, or 52. In this case, the first three digits can be any of the five given digits {1, 2, 3, 4, 5}. So, the number of possibilities for the first three digits is 5 * 5 * 5 = 125. Case 2: The last two digits are 44. In this case, the first three digits can be any of the given digits, except for 4 (as it would lead to repetition of 4). So, the number of possibilities for the first three digits is 4 * 5 * 5 = 100. Adding the possibilities from both cases, we have a total of 125 + 100 = 225 possibilities for the first three digits. Now, let's analyze the last two digits: - If the last two digits are 12 or 52, there is only one possibility for the last two digits. - If the last two digits are 24, there are two possibilities for the last two digits (24 or 44). - If the last two digits are 32, there are three possibilities for the last two digits (12, 32, or 52). - If the last two digits are 44, there is one possibility for the last two digits. In total, there are 1 + 1 + 2 + 3 + 1 = 8 possibilities for the last two digits. Therefore, the total number of 5-digit numbers divisible by 4, with digits from the set {1, 2, 3, 4, 5} and repetition allowed, is 225 * 8 = 1800.
Your Answer Is Wrong Bro ! You Have To Multiply 625 By 2 Cause We Have A 2 Digits Which Is Divisible By 4 In Our Set !! The Actual Form Of The Answer Is ( 5×5×5×5×2 ) = 1250
@@antarpantar4435 bro I can't advice u coz I have not practised log from books I just followed my assignments which were given by my coaching But I guess cengage could be a good option If u wouldn't mind solving questions which are actually hard
I am much interested in what they got in gifts 😂 . A beautiful mind ! ☝🏻if u remembered this above sentence tell me in reply , ur English was amazing !
Learning from the video 1) don't be quick, be correct. 2) Never underestimate a CSE student. 3) even if you don't remember concepts, act like you are the GOAT 4) winners and losers both get gifts, so there's no point in winning. This video was just made to promote filo app.
6:02 ! I am in standard 8th and i have studied logarithm and when i saw this question i got surprised because it was too easy . I have used the properties of logarithm and substituted log 9 base 2 to be x and simply solved the problem and got 8 as my answer Yayyyyyyyyyyyyyyyyyyyyyy !
Hey bro, I am in class 9th and I see your videos for my motivation!! For me they are at another level and boosts me for my preparation!! Thnks a lottt❤️
Thanks tharun bro for making such a video, as per the results I think most of the students forgot the concepts after clearing JEE , but some of them still remembers might be because of their branches like if you're in mechanical you need to use Physics most of the times .
After wathing this video mujhe lag ra h drop lena hi padega bcz main sirf 2 que kr paaya in sab main sae , 20 din baad mera adv hai , the intensity of demotivation this challenge gave me was on peak😭😭😭
