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Charge to mass ratio of an electron 

Soumitra Das
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J J Thomson's experiment to determine the charge to mass ratio of an electron

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27 сен 2013

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Комментарии : 123   
@seisukeota273
@seisukeota273 Год назад
Thank you very much. When I was high school student, I could not understand. I am now 52 years old and I understood the experiment. Thank you very much.
@ompansuriya3142
@ompansuriya3142 4 года назад
Who's here from 2021??
@valsalaramakrishnan9062
@valsalaramakrishnan9062 3 года назад
Vah vah... So professional I loved it!!! You didn't slow down and just kept going! And if viewer wants to understand he has to put in the effort vah vah! So refreshing in this age of unacedamy byjus and whatnot!!! Thank you for a beautiful crisp like a pakoda answer!!!
@akasegaonkar
@akasegaonkar 6 лет назад
This took me some time to understand lol. Didn't think it would be so complex.
@hemantsinghshekhawat7224
@hemantsinghshekhawat7224 4 года назад
When we use Fleming's Left Hand Rule for the direction of deflection of electrons, shouldn't we consider the direction of flow of current (instead of direction of motion of electrons). Fleming's Left Hand Rule states that the middle-finger must point in the direction of flow of current, not motion of electron (or xyz). Considering that, the deflection of electrons would be in the opposite direction as stated. Please consider.
@tuanphamrmit
@tuanphamrmit 6 лет назад
Thank you so much! i finally found a video that adequately shows how Thomson figured out this charge to mass ratio. Hope you have videos on other experiments too
@landongonsalves96
@landongonsalves96 8 лет назад
Thanks for the great explanation!
@techtimes1985
@techtimes1985 4 года назад
Wow what an explanation....sir how have you made this animation?
@MadhureshBhattacharya
@MadhureshBhattacharya 9 лет назад
According to Flemings left hand rule the force due to Magnetic field must be opposite to what is shown. In Fleming's Left hand Rule Velocity is in Currents direction. As we are dealing with electron beam we must consider the opposite direction of velocity.
@martinluther281
@martinluther281 10 лет назад
Thank You. It was of great help.
@GRANSETA
@GRANSETA 10 лет назад
a really great explanation, thanks a lot for the video
@chemistryClass182
@chemistryClass182 6 лет назад
One of the best video i have seen... Sir could you please tell me which software did you use to make this video?
@kanikamalik4261
@kanikamalik4261 2 года назад
Thank you sir for clearing our concepts.
@sreenivasm7624
@sreenivasm7624 2 года назад
Thank you for such a good lovely explanation
@siddharthmallbishen2115
@siddharthmallbishen2115 3 года назад
Thanks for this beautiful explanation
@satechknowledge2303
@satechknowledge2303 3 года назад
You nailed it....I am impressed
@anonymousgirl8611
@anonymousgirl8611 5 лет назад
Wow such a helpful video.. Thanks 👍👌👍👌
@NXG-YT18
@NXG-YT18 8 лет назад
well done..gud..presentation..i like it..this gud why to explain
@its_me2198
@its_me2198 6 лет назад
awesome vedio.........................well explain
@sardarad1937
@sardarad1937 6 лет назад
thanks for sharing such a knowledge
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