Thank you for the video! I have a question: In the paper called "The microfluidic Kelvin water dropper", it is stated that the upper rings/electrodes induce opposing charge in the passing droplets. I understand how the system can amplify a charge difference *if* the induction works, but I struggle to see what in this case serves as the "ground" for the induction, since the droplets are already separated from the faucets when this induction supposedly happens. The environment around each droplet is air in the original macroscopic dropper and some silicone oil in the microfluid version. It adds to my confusion that the main explanation in the Wikipedia article supposes that both faucets are connected, and that the upper rings simply polarize the connected faucets before dropping any water, which actually made sense to me. Can you explain how a water Kelvin water dropper can work by charge induction if the faucets are isolated from each other?
when an object is polarized and we say that negative charges go to the left side and positives go to the right, do we mean that electrons come out of the atom(goes left) and only nucleus (without some electrons) goes to the right? That's when negatively charged hand meets the nucleus without some electrons and it becomes balanced atom again?
Would it be correct to say that when induction occurs on insulators, the charges are polarized and the electrons simply move to one side of the atom, while when induction happens on conductors, polarization causes a separation of charges whereby the electrons are free to move from their atoms? Thanks
Depends on what you mean by induction? Induction is generally regarded as a charging process. The process includes a polarization step. Polarization is not a charging process.
Wht happens to the sphere after it gets charged through induction....does it becomes neutral again as charging through induction doesn't Stay for long?
A good sphere with very few surface imperfections can keep a noticeable charge for quite some time under dry conditions. A lesser quality sphere will "leak" its charge much more rapidly under humid conditions.
Really helpful, thank you! A couple of questions: When charging by induction, we have the metal sphere mounted on the post - can the post act as the ground rather than a hand? Also, how would you describe this situation: A metal sphere was charged by induction, then brought to a neutral metal sphere. There was an attraction between the spheres, then a sudden repulsion? Would this be polarization?
First Q: not sure I understand. Second Q : The charged sphere charges the neutral sphere by conduction. This gives them the same charge type so they repel each other.
I am really surprised that the diagrams show the movement of + or protons! Unless the +'s describe ions. I always stress that it is only the movement of electrons unless we are discussing ions. Please explain. Protons are in the nucleus and do not transfer between objects.
NOPE. NEVER. Your comment forced me to rewatch this video again. Throughout the video (and the series of videos), e- is the symbol for electrons. Multiple images (perhaps all) show arrows with an e- above them indicating the movement of electrons. The words describe that electrons move. The + and the - symbols represent regions of excess charge ... which are going to exist anytime there is a polarization step. When electrons leave a region that was neutral it leaves that region with an excess of + charge. That's what the + signs represent. They do not represent protons. Throughout the video series a proton is represented by a p+. But that symbol seldom appears since the protons are spectators fixed in their seats. You can learn more about this in the first video of the series - ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-wHtlDOmWwQI.html. The first 2-3 minutes sets the stage for what moves and why and make it clear that only e- move in electrostatic phenomenon. And consistently throughout the series, there is no explanation that describes anything other than electrons moving. I hope that clarifies.
Thanks it really helped me with my activities though I have one question. Is there a chance that the can X will be attracted to the negatively charged balloon?
