1:03:04 isme ek therom h jo hume pta honi chayiye ki "When two circles intersect at any point then the line joining the centre is the perpendicular bisector of the common chord" isliye wo equal hoga sir...aur agar isme bhi problem h to ek aur therom h ki if a line segment pass through the centre of chord then the line segment is perpendicular bisector of the common chord and the angle made is 90°
1:15:00 This is for anyone who is confused in Q1. Sir solved it correctly here our x=0 Therefore, distance between C and O' which is x is 0. Hence, C is the center of the smaller circle and O' and C are the same point. So AB is the longest chord of the smaller circle thus its diameter. and radius of the smaller circle is equal to AC.
1:14:53 you did so much to solve a 4 marks question, i did this to soove a good puzzle. Visualise with me 1. A line segment with length of 4 cm. 2. From the right side point of this segment, u draw a perpendicular line of 3 cm. 3. line with 4 cm(lets call it oo') and the line with 3 cm(call it o'p) make a 90° angle. 4. If we from point o and connect it to the point p, it will automatically be 5 cm(pythagorus theorum) 5.now imagine that the line op is a radius of a circle with center at o, sane for the line o'p. 6. You will see that the point where two circles intersect each other is point p. 7. Draw a line perpendicular to point o' again(call it o'p') of 3 cm at bottom side. 8. Now draw line op' of 5cm 9. The line oo' is 4 cm and is the common side of both the triangles. 10. Now as we can see that it is just 2 triangles which are congruent by sss criteria. 11. Now the common chord will be line pp' 12. We know the oength of line po' = o'p'=3 13. So, length of pp'= po'+o'p'= 3+3=6 14. You got the common chord as 6 :)
53:41 At this question you can use herons formula them find the height by 1/2×b×h. First you have to prove triangle AOO'=triangle BOO' then by cpct triangle ACO=Triangle ACO' then cpct AC=BC
In ques.1st it is also done by another method by heron's formula... We take perimeter - 5+3+4÷2:- 6cm Thanks heron's formula :- 6(6-5) (6-3) (6-4) (1) (3)(2) 2×3×3×2 Common factor:- 3×2= 6 ( area) Next formula 1/2×b×h 1/2×4×h=12 2h = 12/2= 6 Now 6 is total length of common chord
I got 1st rank in school for imo and now i have qualified for level 2 so i need your help to guide me how to prepare for level 2 i am so confused plzz help me and other also who have qualified level 1 and selected for level 2 to score good in level 2 also .i have studied from you for level 1 and now also want to clear level 2 plzz make video as soon as possible as exam is on 11 feb 2024 i hope pw will help me
Sir tomorrow is my Pre boards exam for maths and I am watching this lecture for revision. Your speech in the start motivated me thank you for your hard work K 2 sir
Sir please tell, question 1 me agar Phele circle ka radius 5cm ha aur dusre ka radius 3cm ha to dono ke center to center distance 4cm kase ho gya center to center distance 5cm+3cm= 8cm hoga na 😂😂😂😂😂😂😂😂😂
in first question you said that OC is a perpendicular needs justification. But just we can prove that my theorem that " if any line falls from the center to the cord then it bisects it and also it is perpendicular also". Am i right😊
no , it is " the perpendicular from the centre of the circle to chord bisects the chord " and " he line drawn through the center of the circle to bisect a chord is perpendicular to the chord " .
@@anby0_0here, they have (4-x)² so we know the identity, (a-b)²=a²+b²-2ab, so by applying this identity here we get (4-x)²=(4)²+(x)²-2(4)(x) so by simplifying it we get 16+x²-8x
Sir pura spoil ho gya hamara exam hua tha abhi aaj kal hee khatam ho gya tha par maths ka phir se hone wala hai aur teacher bol rahe hai ki aur tough banayenge bole hai hva Tak nahi lagegi bahot dar lag raha hai sir 12 date ko hai 😢😢
Sir chaahe spirint 1 ghande aur badha do lekin ese padhao ki samajh me aa jaye kuch samajh nhi aa rha😢😢😢 circle aur quadrilaterals kaise samjhu 10 din baad paper hai
😂😂😂Sir aap itna lengthy kia sbse acha tarika hai ki aap herons formula se area nikalia aur phir 1/2×base×height ka formula use krke height nikal lijia aur phir height +height kr dijia aa jaega common chord bss 6 line me
