im currently doing physics in the irish version of your A Levels and we have the same topics as you and i just learned what my teacher thought us in 4 weeks in 19 minutes. Thank you so much :)
I had been flying with uniform circular motion until the vertical circle came into play, I was about to give up understanding it but this cleared my doubts. You just earned a subscriber.
“The friction between the tyres and the road... is acting towards the center of the roundabout, at all times.” Makes perfect sense. Anything moving in a circle, is circular motion!
For anyone who cant be bothered to go to 7:50 he basically says "you are going to be using this equation a lot especially probably the second year of your ANAL"
my AS in physics is finished and I'm quite happy with my marks its 80ish but I think some improvement needed but this channel is the only reason I survived my As and it's making me understand A level quite much now so just wanna say so much thank you for these videos as these helps a lot:)
I had a question at 18:25 when the car is at the top of the vertical circle, I think the support force should act upwards rather than down if it is in the circle as it needs reaction upwards from the track otherwise the car would just fall and support force will contribute to it. can somebody pls reply quickly as i have an exam tomorrow, thanks
Is tension centripetal force, or is tension part of the centripetal force equation? For instance, mv^/r = T - mg for a string at the bottom of a circular path.
It's exactly the same as the support force of the track in the last example. For the bottom of a vertically circular path, the tension is solely responsible for the centripetal force, but also has to balance the weight, so T=mg+mv^2/r
5:18 Can you please explain why the seats of the chair swing are being flung outwards if there is no such thing as centrifugal force? Really confused about this
So imagine the diagram of the circle and how the line for the velocity is in a straight line. Due to this line being straight there is a small component of the velocity acting pushing the chair away from its circular path hence why the chair swings are being flung outward.
Please clarify 15:55 please. Because to my knowledge, the theta should be betn F and mg and which results in root rgtantheta however what you did also makes sense, so im confused
A planes wing doesnt just generate lift in an upwards sense, it creates a force that is always perpendicular to it. In level flight all the force generated by the wing is matching the gravity - mg. But when the plane banks (rolls) the force generated by the wings changes direction accordingly. Also the wings lift changes depending on the application of the ailerons (up + down flight controlls). When the plane is banked the pilot will use the ailerons to increase the lift of the wing allowing for only the vertical component of lift to counter mg and the horizontal to provide the centripetal force. If the pilot didnt use the ailerons mg would be larger than the lift component and the plane would loose height.
The video is superb, but can you please explain the example you showed at 17:30 when the car is at the right hand side, the resultant force does not comprise of weight acting downwards??
direction of resultant velocity would continually change toward the center? But magnitude of the resultant would never change? This means the acceleration would not change & point toward the center? because the velocity is continuously changing the direction & the direction of the resultant velocity remains toward the center, & the rate called centripetal acceleration? Is acceleration defined number of directional changes per unit time in this case?
what exactly is the support force in the last example? if centripetal force is the resultant force and this is equal to mv^2/r. how is that you can write mv^2/r + mg = s?
why does the friction of the road against the wheels act towards the circle? other than it has to becuase it has to give the centripetal force. isnt friction against the direction of motion but the motion is tangential to the circular path? im abit confused about this point so would be grateful for some clarification. Thank you
BTW: I visited a sugar factory many years ago and I saw centrifuges turning very fast & centrifuging out crystals, separating the crystals? Also, I believe one would stick to wall inside a rotating wall? What force is that, is it not centrifugal force? Please explain, thank u
Because we know that the force responsible for circular motion must be greater than the centripetal force. For example, if centripetal force = 5N, it is impossible for say 3N of upthrust to provide this, which is what multiplying by cos or sin would get you.
Sir kindly help me in Q1 a level physics 2010 paper 4 summer varient 1. stone of weight 3.0 N is fixed, using glue, to one end P of a rigid rod CP, as shown in Fig. 1.1.85 cmCPωgluestone,weight 3.0 NFig. 1.1 The rod is rotated about end C so that the stone moves in a vertical circle of radius 85 cm. The angular speed ω of the rod and stone is gradually increased from zero until the glue snaps. The glue fixing the stone snaps when the tension in it is 18 N. For the position of the stone at which the glue snaps, (i) on the dotted circle of Fig. 1.1, mark with the letter S the position of the stone,
Why is the friction always acting toward the center ? If there is no friction which direction the car is going to move out, radially outward or along the tangent?
you know how you said velocity is 90 degrees to the object's path, isn't the object's path going along with the direction of velocity and actually 90 degrees to the centripetal force? sorry i'm confused on that.
Science Shorts sorry I misunderstood when you said that “velocity is at a tangent to the object’s path.” But I see now that you mean it’s at a tangent to object’s path which is a circle. I understand now. Thankyou!
hi, i'm just wondering, for the vertically circular path, at the end of the video, if the carriage is, say, slightly to the left of the top one would S become S = mv^2/r - Xmg where x is cos or sin of some angle?
The ISS orbits the Earth every 90 minutes not 30, at an average altitude of 400 kilometres above the Earth. This was likely chosen as a safe minimum altitude that the Space Shuttle could reach, and that the ISS only required minimal occasional altitude boosts to avoid re-entry. The velocity it has is a function of its altitude. A higher altitude, less velocity. Lower altitude higher velocity. However, there is still some aerodynamic drag on the ISS due to residual atmosphere even at 400 kilometres, so it wouldn't be safe orbiting much lower, as the station is expected to remain in orbit for years, not just mere months.
