COMPILER DESIGN: UNIT-2 LEXICAL ANALYZER (PART-3) | Thomson method | RE TO NFA | NFA TO DFA 

"aap insan nahi bhagwan ho", struggling to understand this since the start of my semenster.Thank you very much for this video.

Thank you so much, unable to find any clear video in compiler designer for this topic. This one is one of the best!

bhai bahout easy way me samjaya hai aapne.......thank you so much bhai❤❤‍🔥❤‍🔥❤‍🔥

Bhai mai is subject me ek dum khtm insaan hu bt apki vjah se lgta hai pass ho jaunga . Don't have words to thank you man ✌️❤

Finally somebody explained thomson rule .

this was a lifesaver

Best explanation of all videos for nfa to DFA 💯

Thankyou so much sir all the concepts clearly covered in one video ❤❤

Thank You for making this video it is very helpful😊

Thank you so much. you are my savior! ❤💯

You made this easy to understand👌

Nice explanation, thank you 🙂

Best video thank you sir

very helpful... thank you

Wonderful explanation

thank u for making this very easy

Thank you for sharing

Yor are God Sir

Thank you so much 🎉

PERFECT!

Thanks... Nobody not posted this unit..

great!!!!

Thanks a lot ☺️

how many states will be there in total for a(b | c)*a*c following your method i got 15 states in total but chat gpt says it will be 16 because you have to add an epsilon transition from end state of a* to start state of c. but in your example (a|b)*abb you have not added any epsilon transition after (a|b)* to a please clarify

Thankyou so much

thank you so much

nice

why is there a null in some of the expressions ?

Thanks sir

question no 4 (a* | b* ) how to convert into NFA

For (a | b)*a(a | b) does I have to draw ( a | b) two times or only one time while concetenation

Sir please do share the PDF of exercise question

please provide the exercise answers

please, give me Exercise soluation

When we draw nfa then # is included or not?

(a*|b*)*aa how to convert it in NFA

book name plz

kfueit se prhne k bad yahn ana farz hai ap per ,, compiler itna mushkil nhi jinta hmy btaya gya tha ,,

Makkhan 🧈