Complex Analysis | CSIR NET DEC 2023 Mathematics | Short Cut Tricks | 704036, 704030, 704033, 704034

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This lecture explains the PYQs on CSIR NET Dec 2023 Complex Analysis Short Cut Tricks. Q.ID 704036, 704030, 704033, 704034
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5 окт 2024

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Комментарии : 16

@cauchyacademy9618 7 месяцев назад

Please check dot product of (1,0) and (0,1)

@Mathhubsdl 2 месяца назад

Dot Product for the 1st Option is not correct it is an orthogonal actually

@Thoni-op9kq5em8s 7 месяцев назад

The best of the best thing is you never left behind any option without explaining it. Be it the right or wrong option, you never fail to amazed in both the sides......... Very helpful... Thank you so much.

@MohdAasif-mf8tu 7 месяцев назад

Sir please complete the ode in the same way. Please make videos on Wronkskian, Sturm livollis problem and other important topics

@shrawankumarpatel2148 7 месяцев назад

Thank you a lot sir🙏🌼🌼🌼🙏

@irshadsirslectures4446 7 месяцев назад

It is real differentiable function that means imaginary part is zero

@amankajla234 4 месяца назад

Sir complex analysis ke part-c ka bhi solution upload kar dijiye

@nehaprajapati5920 7 месяцев назад

Sir dot product of (1,0)and(0,1) is 0

@DrHarishGarg 7 месяцев назад

Then take other example as f(z)=z^2

@nehaprajapati5920 7 месяцев назад

Ok sir.. thanku

@Donotknow417 6 месяцев назад

@@DrHarishGargf(z)=z^2 still gives dot product 0

@SukhPreet-mp8jt 5 месяцев назад

Too sir option konsa thik hoga

@anitayadav9673 3 месяца назад

@DrHarishgarg sir , f(z)=z^2 also gives dot product zero

@irshadsirslectures4446 7 месяцев назад

Y f(H) is not convex set

@learnwithsan5017 2 месяца назад

In convex set a line AB joining any two points A, B in the set lies completely within the set. Here f(H) is points inside unit circle except zero. If we connect two points in real line let one from negative real axis and other from +ve real axis ,when we connect that two point using a line definitely it will pass through zero but zero does not belong to f(H).There fore its not a convex set.