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Complex Analysis: what is a contour integral? 

Maths 505
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9 сен 2024

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Комментарии : 38   
@ryankelly9772
@ryankelly9772 10 месяцев назад
common Maths505 W
@TI5040
@TI5040 10 месяцев назад
Video was pretty good. To get a clear intuition on what exactly an integral in complex analysis mean I recommend the book "Visual complex analysis" by Tristan Needham combined with vector calculus chapter in "Feynman lectures in physics".
@quanle1539
@quanle1539 2 месяца назад
Hi there! I just wanted to say that your video on complex analysis is fantastic. I'm starting to learn it again on my own, and your video has been a tremendous help. Great work, and thank you so much!
@AB-nu5we
@AB-nu5we 10 месяцев назад
Didn't I watch this on your other site, focusing on Complex Analysis. I keep going crazy. Not that watching it again is a bad thing as doing so builds strong bones and teeth.
@user-wt6oe8nm7y
@user-wt6oe8nm7y 10 месяцев назад
Although my math is bad,I still watch most of your videos idk I probably enjoy watching someone solving hard problems
@maths_505
@maths_505 10 месяцев назад
Thanks bro
@ikarienator
@ikarienator 10 месяцев назад
That's a very nice introduction! Can you cover the branch cut next time? I think I have never really understood it.
@maths_505
@maths_505 10 месяцев назад
I've made videos on branch cuts for all the important functions. Check out the complex analysis lectures playlist. The discussion of branch cuts starts with the the complex exponential from Euler's formula.
@silentmath3198
@silentmath3198 10 месяцев назад
awesome video
@fuckayo-ti1fj
@fuckayo-ti1fj 10 месяцев назад
I noticed something in one or your videos. I forgot which one but it was using lobachevsky formula. You had the integral from 0 to inf of sin(x)sec(x)/x and used the Lobachevsky integral formula. Yet, sec(x) is indeed pi periodic but with alternating signs, but it is not continuous which makes the formula non valid. This integral is basically the integral from 0 to infinity of tan(x)/x. The limit as x -> inf doesn’t exist anyways.
@maths_505
@maths_505 10 месяцев назад
Bruh I have never evaluated that integral. And there are 2 versions of Lobachevsky's formula and I've proved both of em.
@fuckayo-ti1fj
@fuckayo-ti1fj 10 месяцев назад
@@maths_505 « Bruh », you did indeed at 8:39 of this video ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-SwizwPy-GmE.htmlsi=He6zBt6AhK1s5GjO. I know there are 2 versions I watched all of your videos i love your content, but it remains the sec(x) isn’t continuous
@maths_505
@maths_505 10 месяцев назад
Oh that's an integral that was part of the solution development of another integral. There's nothing wrong with that application cuz you can always break down the integral into a series of integration operators like I did for the proof of the formula.
@tifn4g190
@tifn4g190 10 месяцев назад
I have a question about double intégrals: when you have a double intégral from 0 to Infinity, and the integrand is f(x,y) dx dy. My question is when can you inverse dx and dy (like what are the conditions on f ?)
@maths_505
@maths_505 10 месяцев назад
Continuity of the function.
@tifn4g190
@tifn4g190 10 месяцев назад
@@maths_505 there isn't any condition on the convergence of the integral?
@maths_505
@maths_505 10 месяцев назад
@tifn4g190 isn't that plainly obvious????? Convergence is always key.
@apologizemin9457
@apologizemin9457 10 месяцев назад
:'0 WOW
@spiderjerusalem4009
@spiderjerusalem4009 10 месяцев назад
Did you use shakarchi's complex analysis 🤔
@maths_505
@maths_505 10 месяцев назад
Who?
@maths_505
@maths_505 10 месяцев назад
I use lang, dettman and gamelin for complex analysis
@youknowwhatlol6628
@youknowwhatlol6628 7 месяцев назад
thanks for the video! i didn't understand your proof (since i am a beginner in advanced calculus and analysis)...i don't know these sums are and most importantly - WHY we have this inequality....intuitively, for me, it doesn't make sense. Could you guys (or the admin) please enlighten me on this? Thanks so much, in advance :)
@KusacUK
@KusacUK 7 месяцев назад
For the inequality, imagine summing the values 1, -2, 3. If you take the absolute value of each element, then do the summation, it has to be greater than the absolute value of the overall sum - because the absolute value of -2 would be +2. The inequality in general is less than or equals (or >= depending on which way round you write it) because the number of negative items in your set of values might be zero (so the sums would be equal).
@KusacUK
@KusacUK 7 месяцев назад
As for the Riemann sums - that’s really just the definition of integration, written in summation notation. Dividing the area under the curve into rectangles of width delta x, then taking the limit as the number of rectangles approaches infinity (and delta x therefore approaching 0).
@pandavroomvroom
@pandavroomvroom 10 месяцев назад
pretty cool
@mtl.wraith9981
@mtl.wraith9981 10 месяцев назад
could you do a line integral next? i see them for one formula in my physics class but they were not explained at all
@worldnotworld
@worldnotworld Месяц назад
OK Cool
@giacomocervelli1945
@giacomocervelli1945 10 месяцев назад
Why did you upload this here and not on the second channel? (Just out of curiosity)
@maths_505
@maths_505 10 месяцев назад
Experimental purposes
@anupamamehra6068
@anupamamehra6068 10 месяцев назад
hi thanks for this... by the way are you a bachelor in mathematics or physics?
@maths_505
@maths_505 10 месяцев назад
Majored in math Nd took lots of physics courses.
@notsodope834
@notsodope834 Месяц назад
Ok but 1/z dz integral is not ln(z) here😢
@maxvangulik1988
@maxvangulik1988 10 месяцев назад
does parametrasiation mater?
@maths_505
@maths_505 10 месяцев назад
No it doesn't and my spellings are horibal
@AlBoulley
@AlBoulley 10 месяцев назад
DOES PARAMETERIZATION MATTER
@maths_505
@maths_505 10 месяцев назад
NO IT DOES NOT
@maths_505
@maths_505 10 месяцев назад
My spellings are pretty horibal
@comdo777
@comdo777 10 месяцев назад
asnwer= dz isit hmm
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