So unfortunate. Too many KBAT questions this year. Nevertheless, I want to thank you sir for being such a generous teacher. You've helped a lot of students including me. Keep the great work, sir!
+Ymx+c but your answers of length is different with the answer given by the KPM pasts year questions. it uses 2(pi)r = 2*3.142*8.9 = 55.9276 s=r(delta) 55.9276 = 25.60(delta) delta = 2.185rad. x+(pi/2) = delta x=2.185-(pi/2) =0.3477 rad. y/25.60 = tan(x) y=9.275 minimum length = 25.60 + 9.275 = 34.88cm i cant understand the x+(pi/2) = delta steps provided and came to your channel but found out different answers....
ya bro...the book actually made a mistake...If you look at the answers....the triangle drawn is wrong.....the hypertenuse is 25.6cm but the book put the adjacent side as 25.6cm
not too hard... the biggest problem i met is the paper 2 section a last question part (b) the window one... i cant found out the width of it. paper 1 is mostly easy.
