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Console Secrets: 5 Chrome DevTools Console APIs you probably aren't using! 

Jarrod Overson
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The chrome devtools are the first stop to debug JavaScript web applications and they include a ridiculous number of features, far more than anyone can keep up with at any point. Even if you are up-to-date, Google developers add new debugging and troubleshooting features almost every version so it's important to brush up on them regularly.
This video goes over new and old-but-unknown console like $0-$4, $_, monitorEvents()/unmonitorEvents(), getEventListeners(), monitor()/unmonitor(), and debug()/undebug(). Plus there's an undocumented feature of debug() that you'll definitely want to know about.
Check out full documentation here:
developers.goo...

Опубликовано:

 

27 авг 2024

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Комментарии : 12   
@domaincontroller
@domaincontroller 3 года назад
00:48 sign-in form 01:30 $0, $1, $[...] variables 03:26 monitorEvents() 05:09 getEventListerners($0), unmonitorEvents() 06:28 monitor() 07:19 debug()
@jsoverson
@jsoverson 5 лет назад
If you find any other undocumented tips with console methods please post them!
@JackBrunsion
@JackBrunsion 3 года назад
Absolute gold-mine!
@Surroundize
@Surroundize 4 года назад
Very helpful API. Thanks for the info. 👍🏻
@logkdogk
@logkdogk 4 года назад
Awesome video! Thanks for the headsup! 🤘🤘🤘
@mirhosseinmousavi7378
@mirhosseinmousavi7378 Год назад
Really cool stuff! thanks
@MrFedericoraggi
@MrFedericoraggi 2 года назад
Super useful. Thank you very much
@user-cu8sv7lg7f
@user-cu8sv7lg7f 8 месяцев назад
Very helpful API!!!😀😀😀😀
@thetrends5670
@thetrends5670 3 года назад
Who draw those drawings in your background/wall?
@osherezra8460
@osherezra8460 4 года назад
Wow Thank you so much was looking for an answer to the $0 for ages. just one question why is that every time you run the command it return undefined? cheers
@mishasawangwan6652
@mishasawangwan6652 3 года назад
i’m going off on a guess here but i think it’s because if not explicitly specified every function/expression/whatever in javascript has an implicit return value of ‘undefined’ therefore ..well, i think the rest is obvious..
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