what if u2 is different tha U and we are given the function u(x,y), what should we do? does the expression on the second side of the pipe becomes "integral(rho*u(x,y)^2*dA" or "integral(rho*U*u(x,y)dA"?, i ignored the sign here btw.
Hello Sir, I find at 8:16 the explanation that force gets "stronger and stronger" with the steeper angle of the wedge a little confusing as the same force will instantly disappear when the angle theta turns 90 (in the absence of gravity) , as the jet would be pushing the wedge with purely horizontal component and zero vertical component. Wit further increase in the angle the force will change the sign, thus at angle 90 we see a discontinuity in the force curve.
Hello there. If you listen to what he says right after, he'll add that (quote)" it would be a faulty assumption for high angles", so I guess that would explain the Theta=90° case, though I find it a bit intriguing. You might wanna consider the fact that neglecting some terms in our equations could affect the results. This is an assumption, once again. Have a good day sir. Oh damn, I'm 11 months late XD
It is because I moved it to the other side of the equation. I had 0 = termA - termB + f and I rewrote as f = termB-termA It is easy to mess the signs up in these problems so let me know if you think this is still an error.
Small mistake happened here, the pressure is atmosphere, yes, but the outlet pressure force will never cancel that for inlet because of the cosine function found
