Nice video and you explained well. Just a minor point, it is a bit confusing when you say that when calculating F1 or F2 you don't need to worry if it is positive or negative because that just tells you the direction. Then later you say that the positive or negative for Fnet tells you the direction. I think it would be clearer to say that the negative or positive for the F1 or F2 indicates an attraction or repulsion. The positive or negative when calculating Fnet would indicate direction, left or right.
Thank you and this will be very helpful for my future tests and topics in Physics 2: Electromagnetic Waves❤! But i have a question, what is the exact value of 1Coulomb? It is 6.241x10^18 or either +/- 1.6x10^-19? I'm really confused that i cannot make progress about this problem. And also, if for example there's 2C, should i also multiply it by 2 on either of those 2 on my first question? The answer i get if there's only number of charges instead the value of C is on scientific notation and higher numbers that isn't I expected. Anyway thanks again for these!
It would help to see a time link for what example in the video you are asking about. q3 could be anywhere relative to q1 and q2, depending on how we specify it. You might ask, where can we place q3, so that the net force on it due to q1 and q2 is zero? Given q1 on the left and q2 on the right. In which case, you'd set up a generalized equation for the force on q3, along the axis of q1 and q2. You'd then identify three regions (left of q1, between q1 and q2, and right of q2), and develop an equation for the force on q3 in each of these regions. By inspection, you can rule out regions where the force on q3 could not equal zero. For instance, if q1 and q2 are opposite signs, then we know the force on q3 can't be zero between them, so we can rule out that region. If q1 > q2, then we know the force on q3 can't be zero to the left of q1. This leaves only one region (right of q2), where there could be a zero force point, to place q3.
Basically (cos) is used when your closing the angle. Like if the angle is on the y-axis, then you use (cos) with respect to the y-axis and (sin) with respect to the x-axis. And vise versa. Hope you understand and it helps.
It's like watchmaking. Cheap, mainstream ones are easy to replicate. While expensive ones require craftsmanship and many complications. By having many complications in your homework your professor is building an expensive, luxurious brains. XD
Followed this ex down to a tee and its saying my Net Force value is wrong, not sure what else to do. Only difference in my problem is that my q2 is positive and my q3 is negative and it wants my answer in mN's not N. Have walked through 3 different tutors now and none of them we're able to come to the same conclusion. not sure what else to do...
We're dealing with far more than microcool. He and we at this House are dealing with every fitted label and price setter. That's Android policy you're taking about. So I have shopped for this house and receipts were sent out I expect. It also has a limited right to ERR within it's space as the state lottery stays next door. Our house may clip some hedges and it's height is as high as federalist access goes. In our practical lives here, we don't all do this. I do. I'm the fence keeper here and it is a house Paul. So let's just say it has a soft underbelly as an opportunity to prove youre A: capable of outlining a property's edges. You know what that is and you can be found at the door. B: You're safe being trusted to stand in C: You're a stay put homebody D:You'd kick instead of shoot E: You'd Enterprises F: you'd find treasures in the dirt on ground G: has no right this high up.
You need to break into components because it consists of horizontal rise and vertical as gradient I.e. it is not fully vertical or horizontal - it's between them. This shows you that, it consists of vertical and horizontal line which you will need to find each of them. Another thing that can show you it consists of two components, It's like hypotenuse which is found by using the horizontal and vertical lines. Hope you'll get it.
@@ahmedomar9804 Thank you alot Ahmed for the reply... even though I don't need physics anymore but it was helpful for a further knowledge thanks again.
unfortunately you have no choice the forces are vectors which have a length and a direction and you might need to add several vectors together. This will require some vector algebra.
It's a universal constant that we experimentally determine. It has a value you can look up, which is about 9*10^9 Newton-meters^2/Coulomb^2. Coulomb experimentally determined this constant, in a similar manner as Cavendish determined the Big G of gravity, and hence became the namesake of this law and the unit of charge. You may see it written as 1/(4*pi*epsilon0), to relate it to Gauss's law, in which case epsilon0 is the experimentally measured constant that directly depends on the Coulomb constant K. This way, 4*pi*r^2, the surface area of the sphere of influence, appears in the denominator.
No, you don't need. The negative sign just shows you that the charge you have is a negative charge. But if it is force, the negative sign shows you the direction of the force.
