Wow Richard was so extremely clever. The conundrum was anchorage and Richard said, "I's that right, I'll ask her (alaska,). I'm on my knees bowing to the man of words. Bravo Richard, one of the best puns on countdown ever.
I love how at the start Richard was saying it was August 1st, Yorkshire Day - as back then and now in 2018 Countdown is recorded months in advance in multiple blocks. Today they record a whole weeks episodes in one day.
Will you be uploading every episode? I ask as I no longer have the dvd of the 2 episodes I was on, and be great if they could appear on you tube after all these years
could i have dreamt it? i was in a phase where i was doing a lot of bath salts during this countdown era, i do recall there was a good shot of it going in.
All the comments on this post are far from the goodness of countdown and the great relationship they all had together on and off screen. I'm sad that TV is now only populated with assailed and posers. All innocence is lost in our society.
@alwl89 It's not! I'm telling you the facts as it were, it was 2004 she became permanent and that's that now stop arguing with me. True, she began appearing more frequently in 2003, but was not fully permanent until 2004, which was midway through series 52.
25:36 The century puzzle has no solution. 1+2+…+9=45, which is 55 away from 100. Every time a digit is used a the leftmost digit of a two-digit number, the sum increases by the value of the digit times 9. But the equation 9×n=55 has no integer solutions.
Replying to an old comment, but I’m just watching this video now :) He said to add up the numbers, which I took to mean no subtraction, so this wouldn’t be a valid solution (unless additive inverses - ie, negatives - are allowed). Was also interested in finding a solution where none of the intermediate answers are used to represent the digits (like the guy here did in his two solutions), and looks like it’s not possible if we restrict ourselves to integers. Sketch of proof: consider any partition of 1-9 into ones and tens places, with each partition adding up to y and x respectively, and then solve the linear equation 10x + y = 100 and x + y = 45 (since 1 to 9 all added together is 45). Solution here is not an integer, which contradicts the fact that each of the partitions’ sums x and y have to be integers.
