Dear Pradeep, Once again excellent explanation and teaching methods in your video. I think one helpful addition to your channel would be if you made some lectures about developing the capability diagram of synchronous generator
sir because of you i will have to make my IES notes again for stability, load dispatch and fault analysis part . 😭 old ones too complicated . Thanks bdw 😂
for equation at 24:55, to solve for critical clearing angle, do we use Pmax @ fault? Or before fault? Or once fault is cleared? Pmax changes based on which condition.
Hye Sir. The area A1 ( or A2) is said to be the stored energy. How does the P axis vs delta axis or what is the relationship between P and delta that we can say the area is equals to the energy?
The areas A1 and A2 haven't been said to be "equal to the energy". Due to the discrepancy between the mechanical power input and the electrical power output the latter being zero on account of fault (V=0), the entire power input to the rotor manifests itself as kinetic energy, to accelerate the rotor. This accelerating power acting on the rotor, makes it's speed which was synchronous prior to the fault (on account of stable operating conditions), to go beyond synchronous now. The rotor angle delta increasing along with it. Following the fault clearance, the electrical power output becomes greater than the constant mechanical power input, as is evident from the power angle characteristic. Therefore the accelerating power goes negative now. This makes the rotor decelerate, it's speed gradually decreasing from super-synchronous to synchronous, until the kinetic energy which it had acquired during the initial accelerating period is completely given up as per the "energy conservation principle". Thus areas A1 and A2 are actually "representatives" of the Kinetic Energy gained or lost by the rotor and not mathematically equal to the kinetic energy gained or lost by the rotor. We equate A1 with A2 in equal area criteria just to comply with the "energy conservation principle".
Debanjan Datta : whats the physical reason of heigher electrical output power just after the fault clearance ? Is it , because of consistent mechanical input + the kinetic energy stored both will produce electrical power during the period it returns to sycn speed and hence the stored kinetic energy being consumed in output power generation ?
