CSIR NET LECTURE SERIES - Complex Analysis - CSIR NET MATH'S FEB 2022 SOLUTION -  

No one can touch to your simplicity and concepts of teaching sir. 🙏

Best teacher

Thanks for this lecture sir. Love you sir

Thank you Sir.

12:03 par RHS ka function 0 par define nhi h to identity thm. kaise apply hogi sir identity thm. k liye function define to hona chaiye

Is f(z) obtained entire? Also whether f(z) obtained satisfies given condition?

Z.h(z) to tb likhenge agr simple zero ho...agr zero ka order more than 1 aaya to zada se multiply krenge ...pr hme sure kese hoga k ye simple zero hai

Sir please explain how h(z) is bounded in |Z| less than 1