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Derivative of sin(x) and cos(x), PROOF 

blackpenredpen
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Geometric proof of sin(x)/x approaches 1 as x approaches 0, • The Limit (do not use ...
Angle sum formula: • Angle sum identities f...
part1: derivative of sin(x) and cos(x), • Derivative of sin(x) a...
part2: derivative of tan(x) and cot(x), • derivatives of tan(x) ...
part3: derivative of sec(x) and csc(x), • derivative of sec(x) a...
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Комментарии : 141   
@alexdarcovich9349
@alexdarcovich9349 6 лет назад
"sine and cosine are like homies" #yay
@blackpenredpen
@blackpenredpen 6 лет назад
Yup!
@schizoframia4874
@schizoframia4874 3 года назад
Thats hawitt
@PackSciences
@PackSciences 6 лет назад
I saw a student using L'Hospital for this, it made me really angry because he used sin'(x) to calculate sin'(x)
@Bodyknock
@Bodyknock 6 лет назад
PackSciences Hypothetically it might be possible to use LH’s rule to simultaneously calculate sin’ and cos’ if it results in two expressions with two unknowns, much like using implicit differentiation where you have a derivative on both sides of an equation and solve for the derivative. In this case you end up with sin’(x) = sin(x)cos’(0) + cos(x)sin’(0) and since cos(x+h) - cos (x) = cos(x)sin(h) - sin(x)cos(h) - cos(x) you get cos’(x) = cos(x)sin’(0) - sin(x)cos’(0). Whether or not you could use those two equations to simplify out the sin’(x) and cos’(x) values in terms of sin(x) and cos(x) is another question, but on the face of it this sort of method isn’t completely out of line in general.
@metalsunsuccess-7868
@metalsunsuccess-7868 Год назад
It wouldn't be perfect wrong.
@Arycke
@Arycke 10 месяцев назад
Not good to get angry at students for trying. Simply guide them in the right direction and explain why you can't use circular reasoning (to some, it isn't obvious and it should be explicitly stated nonetheless). Anger makes most people not want to learn fron you in a teaching setting.
@Supportindiangamingcommunity
@Supportindiangamingcommunity 10 месяцев назад
leave your teaching carrier 👍🙂
@sevopaper984
@sevopaper984 3 месяца назад
I know this comment is 5 years old but this method asumes that the derivative exists in the first place, which might not be true.​@@Bodyknock
@JuditaKindlova
@JuditaKindlova 4 года назад
Prefect! I didn't know that cosine stands for complement of sine. Thanks for the video!
@HalifaxHercules
@HalifaxHercules Год назад
Sine and Cosine are basically opposites. It explains why the Tangent is the same as Sine/Cosine. It also explains why the Tangent of 90 degrees is undefined as Sine of 90 is 1 and Cosine of 90 is 0, so 1/0 is undefined.
@rishisivakumar2013
@rishisivakumar2013 6 лет назад
Can u do that proof of cosh-1/h and sinh/h
@tejaswiniattada1531
@tejaswiniattada1531 2 года назад
Sinx/x value is 1 and cosh-1/h substitute h value
@zen4939
@zen4939 Месяц назад
Since you might know sinh/h is equal to 1 but for (cosh-1)/h we can solve it like lim [h tends to 0] (cosh -1)/h We can use the trigonometric function of cos2x just substitute 2x by h and we can break it into sine functions as cosh=1-2sin²(h/2) So next we just substitute cosh in the above equation as [1-2sin²(h/2)-1]/h = -2sin²(h/2)/h And now using limits lim [h tends to 0] -2 [sin²(h/2)/(h/2)² × h/4 Again [sin(h/2)/(h/2)]² is equal to 1 Therefore lim [h tends to 0] -h/2 which after putting the value of the limit we get 0
@darnellyiadom3596
@darnellyiadom3596 6 лет назад
Student: I'm so smart, I know how to derive all the trig function derivatives Bprp: Really? Can you show me it for sin and cos then Student: ... #yay
@lakshya4876
@lakshya4876 6 месяцев назад
What's up with that hashtag
@Engeneeringtips
@Engeneeringtips 6 лет назад
You can also use the identity sin^2 + cos^2 = 1 and derive both sides then you got (sin^2 + cos^2) ‘ = 0 and (cos^2) ‘ = -(sin^2)’ so 2cos*(cos)’ = -2sincos and so (cos)’ = -sin
@elbonais683
@elbonais683 Год назад
GODDAMMIT, IT'S THAT EASY?
@Engeneeringtips
@Engeneeringtips Год назад
May sound complicated but this is to show that you can use and play with identities to prove common relation in maths :)
@asenazaleas3161
@asenazaleas3161 Год назад
@@elbonais683you take d/dx(sinx) = cosx for granted, but it's still cool
@h4c_18
@h4c_18 6 лет назад
I ended with lim as h->0 cos(x)*sin(h/2)/(h/2). Using some tricks with the e^iz formula xD.
@gagadaddy8713
@gagadaddy8713 6 лет назад
Master Cao, no explanation of why (cos(h)-1)/h tend to 0 when h tend to 0
@novidsonmychanneljustcomme5753
Gaga Daddy 5:35 He is aware of this, but it would have been too much for this video to explain this in detail. I'm sure he is able to show this extra proof if he wants to.
@gagadaddy8713
@gagadaddy8713 6 лет назад
@novidsonmychannel, hi! thank for your advise! I am not challenge Master Cao for ignoring the Limit part. The Point here is: lim(h->0) cos(h)-1/h goes to zero can be applied L'Hospital rule, easily. However, if we do so, it go back to the origin point - we want to work out the derivative of sin and cos function from fundamental. This is MY dilemma! ... and this' why I asked this question... sorry if there is any clever way which I am not aware!
@novidsonmychanneljustcomme5753
Gaga Daddy No problem. ;) I can understand what you mean. And I admit that I don't know another "clever" way either. I only can sketch an idea of a "proof" for the two limits: We know that sin(0) = 0 and sin(h) is approximately equal to h for abs(h) 0 ((cos(h))'/1) = 0/1 = 0. I am aware that every mathematician would scream seeing this "proof", but since I'm studying a physical subject please forgive me. :P At least for me it is sufficient if I find ways like these to understand the mathematical backgrounds.
@gagadaddy8713
@gagadaddy8713 6 лет назад
@novidsonmychannel, thank Physicist! Hope u be another Hall of Fame in your professional area! :)
@novidsonmychanneljustcomme5753
You're welcome, thank you too! :)
@HamedAbdulla
@HamedAbdulla 5 лет назад
In summary, It's like 19÷4 = 19/4
@redone3647
@redone3647 2 года назад
Thanks a lot sir . Amazing explaintion 😀
@Alisha-lx8ir
@Alisha-lx8ir Год назад
God bless you instead lecture was superb 👏🏻👏🏻
@alejrandom6592
@alejrandom6592 3 года назад
Nice! I hadn't thought about using complementary identity to prove the derivative of cos(x)
@ckmishn3664
@ckmishn3664 6 лет назад
Why not do the derivative based on the Maclaurin series for since and cosine? The approach you used here has the issue that, without the numerical ✋ waving you might have been stuck with L'Hospital's rule, essentially needing to know the answer to the derivative you were trying to find. Maybe there's a non-circular, rigorous way to solve the "0/0" limits without L'Hospital's rule, but it didn't come readily to mind.
@leadnitrate2194
@leadnitrate2194 4 года назад
Sir, with due respect, people like me who are new to calculus and just learning the derivatives of the trig functions often wonder how these derivatives came about. And while this might not be the most rigorous proof out there, it is more accessible, and, as you say, may be proved to be rigorous. Which is why I'm grateful to BPRP for this video.
@sneedle252
@sneedle252 9 месяцев назад
Please correct me if this is not the case: Don't the Maclaurin series for sin and cos require the result in the above proof to start with?
@joshuapaulorigenes1936
@joshuapaulorigenes1936 6 лет назад
Can you prove tan(x+y) = [tan(x)+tan(y)]/[1-tan(x)tan(y)]? BTW thanks so much, I learned much in your videos.
@leadnitrate2194
@leadnitrate2194 4 года назад
That directly follows from tan(x+y)= sin(x+y)/ cos(x+y) Just give it a try.
@itookashower3485
@itookashower3485 2 года назад
@@leadnitrate2194 what about sin(x+y)??? its proof
@leadnitrate2194
@leadnitrate2194 2 года назад
@@itookashower3485 the proof requires a few illustrations, so I can't outline it in the comments. But this video by bprp shows it very well ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-2SlvKnlVx7U.html Hope it helps
@leadnitrate2194
@leadnitrate2194 2 года назад
@@itookashower3485 you can also prove it by writing sin θ= {e^(iθ) - e^(-iθ)}/2 and cos θ = {e^(iθ) + e^(-iθ)}/2 but I don't know if you've studied complex numbers yet.
@mariomario-ih6mn
@mariomario-ih6mn 5 лет назад
I am not an adult I'm 12
@blackpenredpen
@blackpenredpen 5 лет назад
mario mario you are a math adult!
@ammulureddy5108
@ammulureddy5108 4 года назад
I understand good 😊😊😋😋
@harshsinghbaghel8753
@harshsinghbaghel8753 6 месяцев назад
Best teacher in world ❤
@pronk4321
@pronk4321 2 года назад
saving lives in 2022 T-T thank you for this
@chloeavesmoras355
@chloeavesmoras355 4 года назад
Finally, a video that I can understand xD
@hellgamer5250
@hellgamer5250 4 года назад
Yes
@hellgamer5250
@hellgamer5250 4 года назад
#deathSTRoKEgamingAKANKSHYA
@levi2732
@levi2732 4 года назад
2:05 for those ho want to understand how he get the rule; go watch videos about addition and soustraction for cosinus and sinus cos(a+b) cos(a-b) sinus (a+b) sinus (a-b) it s kinda difficult but you will understand it ; then after that get back to the video
@aidanbryant154
@aidanbryant154 3 года назад
ty
@wierzbi8568
@wierzbi8568 6 лет назад
I wonder where trig identities come from, would you please explain us? Thanks :) #yay
@blackpenredpen
@blackpenredpen 6 лет назад
Wierzbi sure. It's here ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-2SlvKnlVx7U.html
@banderfargoyl
@banderfargoyl 6 лет назад
Since we're all adults now... Tee-hee! 😁
@user-nb6zu3rk4f
@user-nb6zu3rk4f 5 лет назад
?
@BeastMode070subscribe
@BeastMode070subscribe 4 года назад
South park
@shenzhen8302
@shenzhen8302 Год назад
how to proof the lim for (cost(h)-1)/h is 0? 0/0=infinite
@jackkalver4644
@jackkalver4644 2 месяца назад
I figured out two proofs that don’t use the limit of sin x/x, the limit of (cos x-1)/x, or any angle-sum identity. One uses the definition of arc length (as well as the Pythagorean theorem, the fundamental theorem of calculus, and the derivative of sqrt(1-x^2)), but the other one just uses the parametric definition of a derivative (d[x,y]/dt=[dx/dt,dy/dt]). If I ever teach a math class, I will be looking for one of those.
@ListentoGallegos
@ListentoGallegos 6 лет назад
can you use the definition of the derivative for e^x??
@egeyaman4074
@egeyaman4074 5 лет назад
e^x=1+x/1!+x^2/2!+x^3/3!+x^4/4!... e^x=sum x^n/n! ]0-inf Take derivative of that
@Akumansion
@Akumansion 2 года назад
the doraemon theme playing at the start is just awesome
@rashmisrivastava5261
@rashmisrivastava5261 4 года назад
Hey brother could you please provide a geometrical proof ?(actually, I was anticipating for one such proof........ )
@thatmathkid-anthony6658
@thatmathkid-anthony6658 4 года назад
This is a very good video. I have the geometrical proof in my video here. ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-64dguvQBwUQ.html
@mohammednourinjerini3816
@mohammednourinjerini3816 6 лет назад
It is nice Thank you so much
@melakhiwotaberadinke6423
@melakhiwotaberadinke6423 Год назад
You are my Best 👌 👍 😍
@anything6889
@anything6889 6 лет назад
The limit of (f(x+h) - f(x)) /h Where did it come from??
@tablecat6687
@tablecat6687 3 года назад
general definition
@MrLuigiBean1
@MrLuigiBean1 6 лет назад
This is really neat! Glad I found this! =D
@ghostgaming7378
@ghostgaming7378 6 месяцев назад
Why write cos(h) please tell me sir 1:59 video please explain Sir
@drshiii
@drshiii Месяц назад
Did you get it already? If not, I think it is because sin(x+h) has an equivalent identity which is sin(x)cos(h)+cos(x)sin(h) In trigo, it is written as sin(a±b) = sin(a)cos(b) ± cos(a)sin(b) correct me if I'm wrong. thanks
@FFF666GP
@FFF666GP 3 года назад
A more elegant and compact proof exists which uses the identity SinC - SinD = 2Sin(C-D)/2*Cos(C+D)/2 together with the limit Sinh/h ➡️ 1 as h ➡️ 0. Note, C = (x + h) and D = x. Substitution: lim h ➡️ 0 (2Sinh/2h)*(Cos((2x+h)/2)) evaluates to (1)*(Cos(2x/2)) which, in turn, evaluates to Cosx.
@richa4173
@richa4173 3 года назад
Really good
@MathForLife
@MathForLife 6 лет назад
Nice video!!
@blackpenredpen
@blackpenredpen 6 лет назад
MathForLife thanks! And glad to see you back!!
@MathForLife
@MathForLife 6 лет назад
blackpenredpen thanks! I was moving to Berkeley:)
@blackpenredpen
@blackpenredpen 6 лет назад
MathForLife nice!!! How you like it there so far??
@MathForLife
@MathForLife 6 лет назад
blackpenredpen I love it!! Everything is so close:)
@Luka_c123
@Luka_c123 Год назад
you saved me 5 marks sin my alevel thanks
@dolevgo8535
@dolevgo8535 6 лет назад
this video really reminded me on an older one of yours. you even said they're like homies. :) #YAY
@Ffgamingfullonrush
@Ffgamingfullonrush 3 месяца назад
Thank u sir ❤🎉
@biggy7211
@biggy7211 5 месяцев назад
Doremon theme song in the background , so gooooooooood
@sanch3608
@sanch3608 Год назад
Why can you bring the sin of x and the cosine of x out?
@ankursrivastava2809
@ankursrivastava2809 2 года назад
You can also use the expansion of sinx and it is very easy with that approch
@15schaa
@15schaa 6 лет назад
This is pretty neat. #yay
@zahidlala5340
@zahidlala5340 3 года назад
Thank sir for guiding
@i_am_anxious0247
@i_am_anxious0247 5 лет назад
I use the complex definitions
@mdezazkhan4772
@mdezazkhan4772 3 года назад
Thanks sir, well explained ❤️❤️❤️
@jannesl9128
@jannesl9128 6 лет назад
Just a little question: Couldn't you just say cos(h) approaches h and sin(h) approaches (1+h) ? The result is the right one but we got the answer in less steps. #yay
@jannesl9128
@jannesl9128 6 лет назад
Could somebody please give me an answer? :o
@SurinderKumar-os5il
@SurinderKumar-os5il Год назад
Sir, What is dα/ dx of sec α
@Balramsingh777yt
@Balramsingh777yt 3 года назад
What is your language sir but teaching mathod is very nice
@littlescience7855
@littlescience7855 2 года назад
I still wonder how derivative of sinx can be cosx . Is it possible to proof the derivative of sinx is cosx from graph of it
@Metalhammer1993
@Metalhammer1993 5 лет назад
well for the definition of the derivative i tend to do a "useless" extra step. i write the limit but the denominator (anyone with eyes will see why it´s "useless") i´ll write down "x-x+h" ofc it is just h. i´m aware of that. but i just want that pair of f(x) in the numerator amd x in the denominator and f(x+h) in the denominator ans x+h in the numerator just to show that this is nothing but the slope of a line between two points. and then, when this is clear we can kill the x-x in the denominator like a sensible human being and get to work but okay i´m a maths tutor so i show it to kids. Not adults who have their own fair share of mathematical knowledge. sow there is no need to link it to previously learned things this strongly. YOur viewers would appreciate something brand new as well as something build on a foundation they already have.
@GlamourCat1920
@GlamourCat1920 4 года назад
You are undoubtedly a cool human! 😎
@RishiRaj-xj2zb
@RishiRaj-xj2zb 3 года назад
I came here to understand a mug up 1step. But here he says to mug 10 steps ahh shit😂
@nurafiahfifih984
@nurafiahfifih984 5 лет назад
how to prove derivative of f(x) = (u(x))^n?
@VilemJankovsky
@VilemJankovsky 6 лет назад
Can you do an indefinite integral of cos(tan(sec(x)))? All calculators stuck on this.
@heinzanderson462
@heinzanderson462 6 лет назад
no elementary function in terms of standard mathematical
@VilemJankovsky
@VilemJankovsky 6 лет назад
Heinz Anderson what?
@heinzanderson462
@heinzanderson462 6 лет назад
you can not present the solution in a closed form
@novidsonmychanneljustcomme5753
Vilém Jankovský There are already more than enough more "simple" functions which have no explicit indefinite integral, in other words no anti-derivative in terms of elementary functions. e^(x^2), sin(x^2), 1/(ln(x)) - just to name some. Every calculator would stuck on these as well.
@VilemJankovsky
@VilemJankovsky 6 лет назад
novidsonmychannel justcommenting Oh, thank you.
@renugas3162
@renugas3162 3 года назад
Sir What is the answer of -d/dx cos x Pls reply me sir🙏🙏
@novidsonmychanneljustcomme5753
Another alternative way to compute (cos(x))' if you already know (sin(x))', would also be to use cos(x) = sqrt(1-(sin(x))^2) and then the chain rule - works as well, I tried it. ;)
@novidsonmychanneljustcomme5753
And of course you could also use the definition sin(x) = (1/(2i))(e^(-ix) - e^(ix)) by using the chain rule - if you are aware of the derivative of e^x and the definition cos(x) = (1/2)(e^(-ix)+e^(ix)) so that you can recognize it in your result. This is much faster, but of course you're aware of this and on the other hand I also like it to find non-complex proofs for real functions - especially if you explain it to students who don't already know complex numbers.
@yashvardhan6521
@yashvardhan6521 4 года назад
Which company 's markers do u use??
@EMorgensztern
@EMorgensztern 6 лет назад
can you find the continuity (or not) of y=x^(1/x) from -inf to 0 ? I love your videos about complex #
@dolevgo8535
@dolevgo8535 6 лет назад
non-continuous, plug in x=-2
@antimatter2376
@antimatter2376 6 лет назад
I don't think it's continuous because some are complex but at -1 it's not
@dekrain
@dekrain 6 лет назад
@Jordan Saenz: y at -1 is also complex, so is at 1, 2, R & C
@antimatter2376
@antimatter2376 6 лет назад
Dawid Krainski oh yeah it is oops
@samraurooj3414
@samraurooj3414 4 года назад
Thank you ☺️
@biakmuantonsing381
@biakmuantonsing381 3 года назад
Amazing
@7fentertainments364
@7fentertainments364 3 года назад
Sir can you solve d/dx(e^x sinx) ?
@stonale3669
@stonale3669 6 месяцев назад
Why was Doraemon theme playing on the background
@VishalSingh-nn4ne
@VishalSingh-nn4ne 3 года назад
Pls someone explain me 3:43 how (sin(h)-1)/h become zero because when I calculated it on calculator the value show very large.
@wkmars
@wkmars 8 месяцев назад
Very late answer, but its (cos(h) - 1)/h that approach 0, not (sin(h) - 1)/h
@anshsahni6263
@anshsahni6263 5 лет назад
We can also do this using Series expansion of Sinx then taking derivative of Intial terms
@MrFeatre
@MrFeatre 3 года назад
sin and cos are like homies : )
@MrRyanroberson1
@MrRyanroberson1 6 лет назад
I wonder, what the full derivative of sin(a+b) is, since the full derivative of a multivariable function is more than just the successive partial derivatives? Mainly since layering the partials would simply give -sin(a+b)
@rupak6346
@rupak6346 6 лет назад
i have a problem can you solve for me? solve for x x+[x]=1
@Buenofresser
@Buenofresser 6 лет назад
RUPAK BISWAS I think x€IR_
@rupak6346
@rupak6346 6 лет назад
if x=0.5 [x]=0 than x+[x]=0.5
@呂永志-x7o
@呂永志-x7o 6 лет назад
You can solve it by graph; it's no solution.
@rupak6346
@rupak6346 6 лет назад
Thank
@Ben-wv7ht
@Ben-wv7ht 6 лет назад
x+|x|=1 x+x=1 if x>0 and x-x=1 if x0 and 0=1 if x
@SteveGuidi
@SteveGuidi 6 лет назад
Deja-vu: ru-vid.com/video/%D0%B2%D0%B8%D0%B4%D0%B5%D0%BE-VMNX2xGffzU.html
@alejorabirog1679
@alejorabirog1679 5 лет назад
Dude, but you did not proove the limits :(
@blackpenredpen
@blackpenredpen 5 лет назад
It’s in another video. Search “the limit”
@Chris_Gabriel
@Chris_Gabriel 3 года назад
sinhcosx on the third line dont get it wrong guys
@samraurooj3414
@samraurooj3414 4 года назад
👍🏻👍🏻
@flowerwithamachinegun2692
@flowerwithamachinegun2692 6 лет назад
Where are my homies?!!!
@ClashingLego
@ClashingLego 6 лет назад
Homies......LOL
@lenamuszynska8693
@lenamuszynska8693 6 месяцев назад
baby help me
@luisalburez2508
@luisalburez2508 6 лет назад
:v
@oscartroncoso2585
@oscartroncoso2585 6 лет назад
First!
@blackpenredpen
@blackpenredpen 6 лет назад
Oscar Troncoso yay!!!
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