derivative of tan(x), using quotient rule, calculus 1 tutorial

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Derivative of tan(x), calculus 1 tutorial. #calculus
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28 сен 2024

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Комментарии : 85

@Hellstacocat 4 года назад

5 years later still saving student lives

@sepp3891 4 года назад

Confirming youre right :)

@andrewmckinley2214 3 года назад

Absolutely

@karenme5071 2 года назад

7 years later 😇

@TechnicalDhanush 2 года назад

Yup 7yr later 🙂

@willie333b 2 года назад

7 years later

@extralives8693 Год назад

only channel which almost solved all maths questions

@CryptowithKhalid 6 лет назад

super + nice +so simple way i appriciate you respected sir

@blackpenredpen 6 лет назад

thanks!!!

@_torgeek9108 2 года назад

Your explanations are concise and clear. Thanks man. I've been just writing sec^2x without really understanding how we got there😅

@yachmanut7864 Месяц назад

9 years and still helping

@brilliantmind1401 9 месяцев назад

allthough i cant understaND UR FULL LANGAGE BUT SEEING SOLUTION WILL SAVE MY LIFE IN TOMMROW LOVE FROM KaShMiR 🤗

@abdullahkhandawer8486 5 лет назад

I love the way u r teaching

@reddykiranrsr 2 года назад

very simple but always forgetting basics. really saved life...

@takyc7883 4 года назад

I love the way you write the number one

@nadasahraoui3136 2 года назад

اللهم صل وسلم على وبارك على سيدنا محمد وعلى آله وصحبه أجمعين

@faizan3504 3 года назад

Sir i am big fan of you very simple method ❤️❤️

@roronoasif Год назад

Thank you

@aidanstone9417 2 года назад

Bro should go back to the old look imo, his fit is clean

@amansinghmarkam1686 3 года назад

Super

@akhikhondokarpriya8279 4 года назад

tnq sir

@LoveKumar-sd6oc 5 лет назад

Welldone

@nagamanikilli4042 5 лет назад

Sir, my doubt is how did you substituted " cos x . cos x - sin x (-sin x) " in the f

@larrymonyei5818 4 года назад

In TRIGONOMETRY, (COSx)^2 + (SINx)^2 = 1; i.e, cos x square + sin x square = 1

@sixtysixx3933 4 года назад

@@larrymonyei5818 I think that didn't answer his question hahah, he was asking how he substituted in those f f' g g' to the numerator. The method is he simply did a quotient derivative (f'*g - g'*f) / (g*g)

@ericthecuberspeedcuber 3 года назад

it is quotient rule

@sandeepj2972 3 года назад

Formula ,learn that first

@FatBitches 7 лет назад

For fuck sake, im such an idiot. i had -(sinx)^2 for like hours and now i see i forgot the -from the derivative of cosx

@shraddha5702 2 года назад

Ohh 😂

@laitarianplayz8080 3 года назад

I went the long way. 😔

@abedbob4046 5 лет назад

Elementary math. 8th grade ?

@shraddha5702 2 года назад

Umm..it's introduced in class 11 🙄

@Saurabhqwe 4 года назад

Dik hai sir but hindime batay I am Saurabh Yadav Ratna up

@rajankumarrajan7599 7 лет назад

सर ऐसा ही वीडियो बनाया कीजिए सर

@solomon2747 Год назад

8 years later still saving student lives

@roc6596 4 года назад

I tried by the "h" definition and it went to infinity, didn't know a derivative that could diverge, I was the first to do that, probably

@djprometheus923 2 месяца назад

9 years later and bro stays clutch to this day

@nozel3216 3 года назад

Thanks❤🇩🇿

@trishagnidas2004 3 года назад

Thank you so much sir . Clearly understood😌

@radhwanetouahria2314 3 года назад

🤝🤲🤲🤲

@SurinderKumar-os5il Год назад

Plz define what /how sec^2x come fron derivative of tanx Only Explain/define

@CUXOB2 9 месяцев назад

30 years of math and physics, never heard of a "secant"

@abdullahkhandawer8486 5 лет назад

Ur teacching is exteremely nice i love ur teaching

@noell107 4 года назад

thank you, simple but powerful

@thatomofolo452 Год назад

🙋👍👍

@kn_halo 5 месяцев назад

Math is crazy 🤯

@harebanwar1980 5 лет назад

Love it

@AshrafAli-lb6vp 8 месяцев назад

Thank you sir

@nikithagr9795 Год назад

Sir are u from korea

@aphelmusonda5253 2 года назад

thenk you prof

@محمدتحسينحسين 3 года назад

Thanks for you

@madhatter1662 4 года назад

Can the derivative of tan x be done by first principle in terms of (sin x)/(cos x)? I tried, but before I got the end I could see that some how I was going to get the derivative of sin x.

@madhatter1662 4 года назад

Nvmnd, I foundz it.