Design Of Short Rectangular Column For Axial Load | Hindi | IS 456:2000 | Limit State Method | 

Thank you so much sir ✨❤️ this video very helpfull 🤗 and your teaching is also very good

For those who don't know how 490.6 value came ill tell you First take the dia of bar, which in this ques is 25 Then divide it by 2 to get radius Which will be 25/2 = 12.5 Then multiply pi (π) with square of radius Which is π×(12.5) ²= 490.6

Thank you sir 🙏

Great explanation

indeed best teacher

Thank you so much ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️ sir this video very helpful thank you very much ❤️

Bahut badhiya

Great 👍❤

Bro won’t we consider lex/D value for rectangular columns?

Ekdum systematic 💥💥💥

if nothing mentioned in question about the ends of column then how we can get effective length

আপনার কাছে structural design শিখতে চাই, আপনি আমাকে টিউশন দেবেন? কিভাবে যোগাযোগ করতে হবে

Thanks sirrrr

Sir... Please make a video on. Lateral tiles kase lagte haii

Thanks Sir 😊

Thanks

Great

in my question no column length is given. how can I solve the problem

Reinforcement kaise laite hai 4 - 25 ,?

this question from which book bro , can anyone tell?

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Can u make video

👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼👍🏼

I didn't understand bars

Your Asc value is wrong plzz check you calculation it is 10,309 not 3110.5

Thanks

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